(-5,5x - 44) : (- \(\dfrac{3}{2}\) ) = -30
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 5,5.x - 44 : - 3/2 = 30
=> 5,5.x - 44 = 30. - 3/2
5,5.x - 44 =- 45
=> 5,5.x = ( - 45 )+44
5,5 .x = - 1
x =- 1 : 5,5
x =- 2/11
(5,5x-44):(-\(\frac{3}{2}\))=30
5,5x-44 =30.(\(-\frac{3}{2}\))=-45
5,5x =-45+44=-1
x =-1:5,5=\(-\frac{2}{11}\)
\(a.-8:\left(4\dfrac{1}{5}x+\dfrac{3}{10}\right)=4\dfrac{4}{9}\)
\(4\dfrac{1}{5}x+\dfrac{3}{10}=\left(-8\right):4\dfrac{4}{9}\)
\(4\dfrac{1}{5}x+\dfrac{3}{10}=\dfrac{-9}{5}\)
\(4\dfrac{1}{5}x=\dfrac{-9}{5}-\dfrac{3}{10}\)
\(4\dfrac{1}{5}x=\dfrac{-21}{10}\)
\(x=\dfrac{-21}{10}:\dfrac{21}{5}\)
\(x=\dfrac{-1}{2}\)
Vay \(x=\dfrac{-1}{2}\).
\(b.4\dfrac{2}{3}-\left(\dfrac{3}{5}:x\right)=-20\%\)
\(\dfrac{14}{3}-\left(\dfrac{3}{5}:x\right)=\dfrac{-1}{5}\)
\(\dfrac{3}{5}:x=\dfrac{14}{3}-\dfrac{-1}{5}\)
\(\dfrac{3}{5}:x=\dfrac{73}{15}\)
\(x=\dfrac{3}{5}:\dfrac{73}{15}\)
\(x=\dfrac{9}{73}\)
Vay \(x=\dfrac{9}{73}\).
Câu c; d; e tương tự nhé.
a: =>3/2x=64/15
=>x=128/45
b: =>-1/6x=7/12
=>x=-7/2
c: =>11/2*x=1/2
=>x=1/2:11/2=1/11
\(\frac{4}{\frac{2}{5}}:\left(-\frac{33}{10}\right)+x=-\frac{1}{\frac{5}{6}}\)
\(10:\left(-\frac{33}{10}\right)+x=-\frac{6}{5}\)
\(-\frac{100}{33}+x=-\frac{6}{5}\)
\(x=\frac{302}{165}\)
a) \(0,5x-\dfrac{2}{3}x=\dfrac{7}{12}\)
\(\dfrac{1}{2}x-\dfrac{2}{3}x=\dfrac{7}{12}\)
\(\left(\dfrac{1}{2}-\dfrac{2}{3}\right)x=\dfrac{7}{12}\)
\(\dfrac{-1}{6}x=\dfrac{7}{12}\)
\(x=\dfrac{7}{12}:\dfrac{-1}{6}\)
\(x=\dfrac{-7}{2}\)
b) \(x:4\dfrac{1}{3}=-2,5\)
\(x:\dfrac{13}{3}=\dfrac{-5}{2}\)
\(x=\dfrac{13}{3}.\dfrac{-5}{2}\)
\(x=\dfrac{-65}{6}\)
c) \(5,5x=\dfrac{13}{15}\)
\(\dfrac{11}{2}x=\dfrac{13}{15}\)
\(x=\dfrac{13}{15}:\dfrac{11}{2}\)
\(x=\dfrac{26}{165}\)
d) \(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)
\(\left(\dfrac{3x}{7}+1\right)=\dfrac{-1}{28}.\left(-4\right)\)
\(\dfrac{3x}{7}+1=\dfrac{1}{7}\)
\(\dfrac{3x}{7}=\dfrac{1}{7}-1\)
\(\dfrac{3x}{7}=\dfrac{-6}{7}\)
\(\Rightarrow3x=-6\\ x=\left(-6\right):3\\ x=-2\)
câu d mình nhầm bạn nha
d)\(\left(\dfrac{3x}{7}+1\right):\left(-4\right)=\dfrac{-1}{28}\)
\(\dfrac{3x}{7}+1=\dfrac{-1}{28}.\left(-4\right)\)
\(\left(\dfrac{3x}{7}+1\right)=\dfrac{1}{7}\)
\(\dfrac{3x}{7}=\dfrac{1}{7}-1\)
\(\dfrac{3x}{7}=\dfrac{-6}{7}\)
Ta có : 3x =-6
x = -6:3
x=-2
a: \(\dfrac{-13}{40}< \dfrac{-12}{40}\)
\(\dfrac{-5}{6}>\dfrac{-91}{104}\)
Đặt \(\dfrac{x}{-3}=\dfrac{y}{-8}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=3k\\y=8k\end{matrix}\right.\)
Ta có: \(x^2-y^2=-\dfrac{44}{5}\)
\(\Leftrightarrow9k^2-64k^2=-\dfrac{44}{5}\)
\(\Leftrightarrow k^2=\dfrac{4}{25}\)
Trường hợp 1: \(k=\dfrac{2}{5}\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=3k=\dfrac{6}{5}\\y=8k=\dfrac{16}{5}\end{matrix}\right.\)
Trường hợp 2: \(k=-\dfrac{2}{5}\)
\(\Leftrightarrow\left\{{}\begin{matrix}x=3k=\dfrac{-6}{5}\\y=8k=\dfrac{-16}{5}\end{matrix}\right.\)
=>5,5x-44=-30*3/2=-45
=>5,5x=-1
=>x=-10/55=-2/11