a) \(x-\dfrac{5}{6}=\dfrac{1}{2}\)

           \(x=\dfrac{1}{2}+\dfrac{5}{6}\)

           \(x=\dfrac{4}{3}\)

vậy x = ....

b) \(3\dfrac{1}{3}x+16\dfrac{3}{4}=-13,25\)

    \(\dfrac{10}{3}\)\(x+\dfrac{67}{4}=-13,25\)

     \(\dfrac{10}{3}x=\left(-13,25\right)-\dfrac{67}{4}\)

      \(\dfrac{10}{3}x=-30\)

          \(x=\left(-30\right):\dfrac{10}{3}\)

         \(x=-9\)

vậy x =...

sai mog bn thông cảm!!!

\(\dfrac{1}{10}+\dfrac{2}{10}+\dfrac{3}{10}+\dfrac{4}{10}+\dfrac{5}{10}+\dfrac{6}{10}+\dfrac{7}{10}+\dfrac{8}{10}+\dfrac{9}{10}\)

\(=\left(\dfrac{1}{10}+\dfrac{9}{10}\right)+\left(\dfrac{2}{10}+\dfrac{8}{10}\right)+\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{4}{10}+\dfrac{6}{10}\right)+\dfrac{5}{10}\)

\(=1+1+1+1+\dfrac{5}{10}\)

\(=4+\dfrac{5}{10}\)

\(=\dfrac{45}{10}\)

\(13,25:0,5+13,25:0,25+13,25:0,125+13,25\times6\)

\(=13,25:\dfrac{1}{2}+13,25:\dfrac{1}{4}+13,25:\dfrac{1}{8}+13,25\times6\)

\(=13,25\times2+13,25\times4+13,25\times8+13,25\times6\)

\(=13,25\times\left(2+4+8+6\right)\)

\(=13,25\times20\)

\(=265\)

a) \(y+30\%y=-1.3\)

\(y+\dfrac{3}{10}y=\dfrac{-13}{10}\)

\(y\left(1+\dfrac{3}{10}\right)=\dfrac{-13}{10}\)

\(y\left(\dfrac{10}{10}+\dfrac{3}{10}\right)=\dfrac{-13}{10}\)

\(y\cdot\dfrac{13}{10}=\dfrac{-13}{10}\)

\(y=\dfrac{-13}{10}:\dfrac{13}{10}\)

\(y=\dfrac{-13}{10}\cdot\dfrac{10}{13}\)

\(y=-1\)

Vậy \(y=-1\).

b) \(y-25\%y=\dfrac{1}{2}\)

\(y-\dfrac{1}{4}y=\dfrac{1}{2}\)

\(y\left(1-\dfrac{1}{4}\right)=\dfrac{1}{2}\)

\(y\left(\dfrac{4}{4}-\dfrac{1}{4}\right)=\dfrac{1}{2}\)

\(y\cdot\dfrac{3}{4}=\dfrac{1}{2}\)

\(y=\dfrac{1}{2}:\dfrac{3}{4}\)

\(y=\dfrac{1}{2}\cdot\dfrac{4}{3}\)

\(y=\dfrac{2}{3}\)

Vậy \(y=\dfrac{2}{3}\).

c) \(3\dfrac{1}{3}y+16\dfrac{3}{4}=-13.25\)

\(\dfrac{10}{3}y+\dfrac{67}{4}=\dfrac{-53}{4}\)

\(\dfrac{10}{3}y=\dfrac{-53}{4}-\dfrac{67}{4}\)

\(\dfrac{10}{3}y=-30\)

\(y=-30:\dfrac{10}{3}\)

\(y=-30\cdot\dfrac{3}{10}\)

\(y=-9\)

Vậy \(y=-9\).

a)

Vậy .

b)

Vậy .

c)

Vậy .

a. \(3\dfrac{1}{3}x+16=13,25\)

=> x + 16 = 13,25

=> x = 13,25 - 16

=> x = \(-\dfrac{11}{4}\)

b. x - 43 = (57 - x) - 50

=> 2x = 57 - 50 + 43

=> 2x = 7 + 43

=> 2x = 50

=> x = 50 : 2

=> x = 25

a, \(3\dfrac{1}{3}x\) + 16 = 13,25

\(\dfrac{10}{3}x\) + 16 = 13,25

\(\dfrac{10}{3}x\) = -2,75

x = -2,75 : \(\dfrac{10}{3}\)

x = -\(\dfrac{33}{40}\)

b, x - 43 = ( 57 - x ) - 50

x - 43 = 57 - x - 50

x + x = 57 - 50 + 43

2x = 50

x = 25

1: Ta có: \(\dfrac{3}{x-3}+\dfrac{4}{x+3}=\dfrac{3x-7}{x^2-9}\)

\(\Leftrightarrow\dfrac{3x+9}{\left(x-3\right)\left(x+3\right)}+\dfrac{4x-12}{\left(x-3\right)\left(x+3\right)}=\dfrac{3x-7}{\left(x-3\right)\left(x+3\right)}\)

Suy ra: \(3x+9+4x-12=3x-7\)

\(\Leftrightarrow4x=-7+12-9=-4\)

hay \(x=-1\left(nhận\right)\)

2: Ta có: \(\dfrac{3}{x-4}-\dfrac{4}{x+4}=\dfrac{3x-4}{x^2-16}\)

\(\Leftrightarrow\dfrac{3x+12}{\left(x-4\right)\left(x+4\right)}-\dfrac{4x-16}{\left(x+4\right)\left(x-4\right)}=\dfrac{3x-4}{\left(x-4\right)\left(x+4\right)}\)

Suy ra: \(3x+12-4x+16=3x-4\)

\(\Leftrightarrow28-4x=-4\)

\(\Leftrightarrow4x=32\)

hay \(x=8\left(tm\right)\)

3: Ta có: \(\dfrac{5x^2-12}{x^2-1}+\dfrac{3}{x-1}=\dfrac{5x}{x+1}\)

Suy ra: \(5x^2-12+3x+3=5x^2-5x\)

\(\Leftrightarrow3x-9+5x=0\)

\(\Leftrightarrow8x=9\)

hay \(x=\dfrac{9}{8}\left(nhận\right)\)

`#040911`

`a)`

`3 1/3 x + 16 3/4 = -13,25`

`=> 3 1/3 x = -13,25 - 16 3/4`

`=> 3 1/3 x = -30`

`=> x = -30 \div 3 1/3`

`=> x =-9`

Vậy, `x = -9`

`b)`

`3 2/7*x - 1/8 = 2 3/4`

`=> 3 2/7x = 2 3/4 + 1/8`

`=> 3 2/7x = 23/8`

`=> x = 23/8 \div 3 2/7`

`=> x = 7/8`

Vậy, `x = 7/8`

`c)`

`x \div 4 1/3 = -2,5`

`=> x = -2,5 * 4 1/3`

`=> x = -65/6`

Vậy, `x = -65/6`

`d)`

`( (3x)/7 + 1) \div (-4) = (-1)/28`

`=> (3x)/7 +1 = (-1)/28 * (-4)`

`=> (3x)/7 + 1 = 1/7`

`=> (3x)/7 = 1/7 - 1`

`=> (3x)/7 = -6/7`

`=> 3x = -6`

`=> x = -6 \div 3`

`=> x = -2`

Vậy, `x = -2.`

a

=>10/3 . x + 16 + 3/4 = -13,25

=>10/3 x + 3/4 = -29,25

=>10/3 x = -30

=>x=-30 : 10/3

=>x=-30 . 3/10

=>x=-9

b.

=>23/7 x - 1/8 = = 11/4

=>23/7 x = 11/4 + 1/8

=>23/7 x= 22/8 + 1/8

=>23/7 x= 23/8

=>x=23/8 : 23/7

=>x=23/8 . 7/23

=>x=7/8

c.

=>x : 13/3 =-5/2

=>x=-5/2 . 13/3

=>x=-65/6

d.

=>3x/7 +1 = (-1/28) . (-4)

=>3x/7 + 1 = 1/7

=>3x/7 = -6/7

=>3x=-6

=>x=-2

a)4/5+x=2/3

x=2/3-4/5

x=-2/15

b)-5/6-x=2/3

x=-5/6-2/3

x=-3/2

c)1/2x+3/4=-3/10

1/2x=-3/10-3/4

1/2x=-21/20

x=-21/20:1/2

x=-21/10

d)x/3-1/2=1/5

x/3=1/5+1/2

x/3=7/10

10x/30=21/30

10x=21

x=21:10

x=21/10

1: Ta có: \(\dfrac{-3}{x-4}-\dfrac{3-5x}{x^2-16}=\dfrac{1}{x+4}\)

Suy ra: \(-3\left(x+4\right)-3+5x=x-4\)

\(\Leftrightarrow-3x-12-3+5x-x+4=0\)

\(\Leftrightarrow x=11\left(nhận\right)\)

2. ĐKXĐ: $x\neq \pm 2$

PT \(\Leftrightarrow \frac{3(x-2)}{(2+x)(x-2)}-\frac{x-1}{(x-2)(x+2)}=\frac{2(x+2)}{(x-2)(x+2)}\)

\(\Leftrightarrow \frac{3(x-2)-(x-1)}{(x-2)(x+2)}=\frac{2(x+2)}{(x-2)(x+2)}\)

\(\Rightarrow 3(x-2)-(x-1)=2(x+2)\)

\(\Leftrightarrow 2x-5=2x+4\Leftrightarrow 9=0\) (vô lý)

Vậy pt vô nghiệm

a. \(y+30\%y=-1,3\)

\(=>y.\left(1+30\%\right)=-1,3\)

\(=>y.\left(1+\dfrac{3}{10}\right)=-1,3\)

\(=>y.\dfrac{13}{10}=\dfrac{-13}{10}\)

\(=>y=-1\)

b.\(y-25\%y=\dfrac{1}{2}\)

\(=>y.\left(1-25\%\right)=\dfrac{1}{2}\)

\(=>y.\left(1-\dfrac{1}{4}\right)=\dfrac{1}{2}\)

\(=>y.\dfrac{3}{4}=\dfrac{1}{2}\)

\(=>y=\dfrac{1}{2}.\dfrac{4}{3}\)

\(=>y=\dfrac{2}{3}\)

c.\(3\dfrac{1}{3}y+16\dfrac{3}{4}=-13,25\)

\(=>\dfrac{10}{3}y+\dfrac{67}{4}=\dfrac{-53}{4}\)

\(=>\dfrac{10}{3}y=\dfrac{-53-67}{4}\)

\(=>\dfrac{10}{3}y=\dfrac{-120}{4}\)

\(=>\dfrac{10}{3}y=-30\)

\(=>y=-30.\dfrac{3}{10}\)

\(=>y=-9\)

tick cho mk nha

k hiểu chỗ nào thì hỏi mk

tại sao lại tu y+30%.y ra la y .(1+30%)