\(=\dfrac{-15}{8}\times\dfrac{8}{-15}-\dfrac{15}{8}\times\dfrac{32}{27}-\dfrac{15}{7}\\=1-\dfrac{20}{9}-\dfrac{15}{7}\\ =\dfrac{1\times9\times7-20\times7-15\times9}{63}=\dfrac{-212}{63}\)

a) =\(\left(\frac{1}{4}\right)^3\cdot2^5=\frac{1}{2^6}2^5=0,5\)

b) \(=\left(\frac{1}{8}\right)^3\cdot8^4\cdot10^4=80.000\)

c) \(=8^2\cdot\frac{4^5}{2^{20}}=\frac{2^6\cdot2^{10}}{2^{20}}=\frac{1}{2^4}=0,0625\)

d) = \(\frac{81^{11}\cdot3^{17}}{27^{10}\cdot9^{15}}=\frac{3^{44}\cdot3^{17}}{3^{30}\cdot3^{30}}=\frac{3^{61}}{3^{60}}=3\)

= 5/8:15/16

= .....( sử dụng máy tính đó bạn!)

Câu 1:

a) 25-(30+x) = x-(27-8)

    25-30-x   = x-19

      -5-x       = x-19

       (-5)+19  = x+x

        14        = 2x

          x        = 7

Vậy x = 7

b) (x-12)-15 = (20-7)-(18+x)

    x-12-15   = 13-18-x

    x-(12+15)= -5-x

    x-27       = -5-x

    x+x        = -5+27

     2x         = 22

      x          = 11

Câu 2:

a) 4573+46-4573+35-16-5

 = (4573-4573)+(46-16)+(35-5)

 = 0+30+30

 = 60

b) 32+34+36+38-10-12-14-16-18

 = (32-12)+(34-14)+(36-16)+(38-18)-10

 = 10+10+10+10-10

 = 30

1, a) 25 - (30 + x) = x - (27 - 8)

25 - 30 - x = x - 27 + 8

-x - x = -27 + 8 - 25 + 30

-2x = -14

x = -14 : (-2)

x = 7

b) (x - 12) - 15 = (20 - 7) - (18 + x)

x - 12 - 15 = 20 - 7 - 18 - x

x + x = 20 - 7 - 18 + 12 + 15

2x = 22

x = 22 : 2

x = 11

2, a) 4573 + 46 - 4573 + 35 - 16 - 5

= (4573 - 4573) + (46 - 16) + (35 - 5)

= 0 + 30 + 30

= 60

b) 32 + 34 + 36 + 38 - 10 - 12 - 14 - 16 - 18

= (32 - 10) + (34 - 12) + (36 - 14) + (38 - 16) - 18

= 22 + 22 + 22 + 22 - 18

= 22 x 4 - 18

= 88 - 18

= 70

`16/27xx13/29+16/27xx14/29`

`=16/27xx(13/29+14/29)`

`=16/27xx27/29`

`=16/29`

`48/49+15/39-18/49+15/39`

`=(48/49-18/49)+(15/39+15/39)`

`=30/49+30/39`

`=880/637`

1/4

\(=\dfrac{8}{15}\left(\dfrac{25}{32}-\dfrac{10}{32}\right)=\dfrac{8}{15}\cdot\dfrac{15}{32}=\dfrac{1}{4}\)