\(A=\left(27,54.\frac{11}{16}-3.405\right):3\)

\(A=\left(\frac{15147}{800}-3.405\right):3\)

\(A=\frac{12423}{800}:3\)

\(A=\frac{4141}{800}\)

\(B=\left(\frac{1}{6}+0,1+\frac{1}{5}\right):\left(\frac{1}{6}+0,1-\frac{1}{5}\right)\)

\(B=\frac{7}{15}:\frac{1}{15}\)

\(B=7\)

\(C=\left(0,5-\frac{1}{3}+0,25\right):\left(0,25-\frac{1}{6}\right)\)

\(C=\frac{5}{12}:\frac{1}{12}\)

\(C=5\)

\(D=\frac{13,5.1420+4,5.780.3}{3+6+9+...+24+27}\)

              Số số hạng từ 3 đến 27 là:
                      (27-3):3+1=9(số hạng)

              Tổng dãy số từ 3 đến 27 là:

                       (27+3)x9:2=135

\(D=\frac{13,5.1420+13,5.780}{135}\)

\(D=\frac{13,5.\left(1420+780\right)}{135}\)

\(D=2200\)

Dấu . là dấu nhân

tính giá trị biểu thức chứ còn cái gì nữa

a, \(A=\frac{22}{27}\)

b,\(B=\frac{1}{57}\)

C,\(C=\frac{1}{50}\)

d, \(D=0\)

\(H=\frac{4}{15}-\frac{23}{28}-\left(-\frac{23}{28}+\frac{-11}{15}-\frac{24}{27}\right)-\frac{2}{27}\)

\(H=\frac{4}{15}+\frac{-23}{28}+\frac{23}{28}+\frac{11}{15}+\frac{24}{27}+\frac{-2}{27}\)

\(H=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{-23}{28}+\frac{23}{28}\right)+\left(\frac{24}{27}+\frac{-2}{27}\right)\)

\(H=1+0+\frac{22}{27}\)

\(H=1+\frac{22}{27}\)

\(H=\frac{27}{27}+\frac{22}{27}=\frac{49}{27}\)

\(H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{24}{27}\right)-\frac{2}{27}\)

\(H=\frac{4}{15}-\frac{23}{28}+\frac{23}{28}+\frac{11}{15}+\frac{24}{27}-\frac{2}{27}\)

\(H=\left(\frac{4}{15}+\frac{11}{15}\right)+\left(\frac{-23}{28}+\frac{23}{28}\right)+\left(\frac{24}{27}-\frac{2}{27}\right)\)

\(H=1+0+\frac{22}{27}\)

\(H=\frac{49}{27}\)

C\(\frac{1}{1}-\frac{1}{2.3}+\frac{1}{3.4}-\frac{1}{4.5}+\frac{1}{5.6}\)-\(\frac{1}{6.7}\)+\(\frac{1}{7.8}\)-\(\frac{1}{8.9}+\frac{1}{9.10}\)

c=\(\frac{1}{1}-\frac{1}{10}\)

c=\(\frac{9}{10}\)

còn a và b rễ lắm mình ko thích làm bài rễ đâu bạn cố chờ lời giải khác nhé!

a) \(25^{\dfrac{1}{2}}=5\)

b) \(\left(\dfrac{36}{49}\right)^{-\dfrac{1}{2}}=\dfrac{7}{6}\)

c) \(100^{1,5}=1000\)

A =(1/2 +1)×(1/3 +1)×(1/4 +1)×....×(1/99 +1)

=3/2x4/3x...............x100/99

=2-1/99

=197/99

A= \(\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot.....\cdot\frac{100}{99}\)

A=\(\frac{\left(3\cdot4\cdot5\cdot....\cdot99\right)\cdot100}{2\cdot\left(3\cdot4\cdot5\cdot...\cdot99\right)}\)

A=\(\frac{100}{2}=50\)

\(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+...+\frac{2}{97\cdot99}\)

\(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{97}-\frac{1}{99}\)

=> \(\frac{1}{3}-\frac{1}{99}=\frac{32}{99}\)>\(\frac{32}{100}\)=32%