x/(2*2)+x/(3*4)+x/(6*4)+x/(8*5)+x/(10*6)=5
trả lời giúp mình với
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
x - 4/5 = 3/7
x = 3/7 + 4/5
x = 43/35
x + 3/7 = 4/5
x = 4/5 - 3/7
x = 13/35
19/20 - x = 8/5 - 3/4
19/20 - x = 17/20
x = 19/20 - 17/20
x = 2/20 = 1/10
4/5 x X = 6/9 - 4/7
4/5 x X = 2/21
x = 2/21 : 4/5
x =5/42
x : 7/9 = 6/8
x = 6/8 x 7/9
x = 7/12
2/3 - x/6 = 6/18
x/6 = 2/3 - 6/18
x/6 = 1/3
x/6 = 2/6
=> x =2
1. x = 43/35
2. x = 13/35
3. x = 1/10
còn lại tự tính nhá
tui bận òi
1 )
(-10 + 5) -(4-x)=12 -(5-6)
<=> -10 + 5 - 4 + x = 12 - 5 + 6
<=> x = 12 - 5 + 6 + 10 - 5 + 4
<=> x = 22
2 )
14-(5-8+3-x)=|-7+10|
<=> 14 - 5 + 8 - 3 + x = | 3 |
<=> x = | 3 | -14 + 5 - 8 + 3
<=> x = 3 - 14 + 5 - 8 + 3
<=> x = -11
3 )
-19-(3 +x-5)=|4-15+2|
<=> -19 - 3 - x + 5 = | -9 |
<=> -x = | -9 | - 5 + 19 + 3
<=> -x = 9 - 5 + 19 + 3
<=> -x = 26
<=> x = -26
4 )
45-(x+45-3)=|-7+3|
<=> 45 - x - 45 + 3 = | -4 |
<=> -x + 3 = | -4 |
<=> -x = 4 - 3
<=> -x = 1
<=> x =-1
10 )
-(-12 +4-10)-(4-x)=-(-3)
<=> 12 - 4 + 10 - 5 + x = 3
<=> x = 3 -12 + 4 - 10 + 5
<=> x = -10
Mình là Siêu Phẩm Hacker , rất mong được thi đấu một lần vs Edokawa conan
1) (-10 + 5) - (4 - x) = 12 - (5 - 6)
=> -5 - 4 + x = 12 + 1
=> -5 - 4 + x = 13
=> 4 + x = -5 - 13
=> 4 + x = - 18
=> x = -18 - 4
=> x = -22
2) 14 - (5 - 8 + 3 - x) = |-7 + 10|
=> 14 + 5 + 8 - 3 + x = |3|
=> 24 + x = 3
=> x = 3 - 24
=> x = -21
3) -19 - (3 + x - 5) = |4 - 15 + 2|
=> -19 - 3 - x + 5 = |-9|
=> -17 - x = 9
=> x = -17 - 9
=> x = -26
4) 45 - (x + 45 - 3) = |-7 + 3|
=> 45 - x - 45 + 3 = |-4|
=> 3 - x = 4
=> x = 3 - 4
=> x = -1
5) -(-12 + 4 - 10) - (4 - x) = -(-3)
=> -(-29) - (4 - x) = 3
=> 29 - (4 - x) = 3
=> 4 - x = 29 - 3
=> 4 - x = 26
=> x = 4 - 26
=> x = -22
2/3 = 2 x 4/ 3 x 4 =8/12
8/14 = 8 : 2/ 14 : 2 =4/7
5/9 = 5 x3/ 9 x 3 =15/37
35/ 40 = 35 : 5/ 40 : 5=7/8
a) \(\dfrac{13}{20}+\dfrac{3}{5}+x=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{5}{4}+x=\dfrac{5}{6}\)
\(\Rightarrow x=\dfrac{5}{6}-\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{-5}{12}\)
b) \(x+\dfrac{1}{3}=\dfrac{2}{5}-\dfrac{-1}{3}\)
\(\Rightarrow x+\dfrac{1}{3}=\dfrac{11}{15}\)
\(\Rightarrow x=\dfrac{11}{15}-\dfrac{1}{3}\)
\(\Rightarrow x=\dfrac{2}{5}\)
c)\(\dfrac{-5}{8}-x=\dfrac{-3}{20}-\dfrac{-1}{6}\)
\(\dfrac{-5}{8}-x=\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-5}{8}-\dfrac{1}{60}\)
\(\Rightarrow x=\dfrac{-77}{120}\)
d) \(\dfrac{3}{5}-x=\dfrac{1}{4}+\dfrac{7}{10}\)
\(\Rightarrow\dfrac{3}{5}-x=\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{3}{5}-\dfrac{19}{20}\)
\(\Rightarrow x=\dfrac{-7}{20}\)
e) \(\dfrac{-3}{7}-x=\dfrac{4}{5}+\dfrac{-2}{3}\)
\(\Rightarrow\dfrac{-3}{7}-x=\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-3}{7}-\dfrac{2}{15}\)
\(\Rightarrow x=\dfrac{-59}{105}\)
g) \(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-1}{3}\)
\(\Rightarrow\dfrac{-5}{6}-x=\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-5}{6}-\dfrac{1}{4}\)
\(\Rightarrow x=\dfrac{-13}{12}\)
\(\dfrac{3}{5}+\dfrac{4}{3}\times\dfrac{5}{6}=\dfrac{3}{5}+\dfrac{10}{9}=\dfrac{27}{45}+\dfrac{50}{45}=\dfrac{77}{45}\)
\(2-\dfrac{7}{6}+\dfrac{1}{3}=\dfrac{12}{6}-\dfrac{7}{6}+\dfrac{2}{6}=\dfrac{7}{6}\)
\(\dfrac{7}{6}\times3-\dfrac{3}{5}=\dfrac{7}{2}-\dfrac{3}{5}=\dfrac{35}{10}-\dfrac{6}{10}=\dfrac{29}{10}\)
`x/(2*2)+x/(3*4)+x/(6*4)+x/(8*5)+x/(10*6)=5`
`x/4 +x/12 +x/24 +x/45 + x/60 =5`
`x(1/4 +1/12 +1/24 +1/40 +1/60)=5`
`x( (30+10+5+3+2)/120 ) =5`
`x *50/120 =5`
`x = 5 *120/50 =12`
\(\dfrac{x}{4}+\dfrac{x}{12}+\dfrac{x}{24}+\dfrac{x}{40}+\dfrac{x}{60}=5\)
\(\Leftrightarrow x\left(\dfrac{1}{4}+\dfrac{1}{12}+\dfrac{1}{24}+\dfrac{1}{40}+\dfrac{1}{60}\right)=5\)
\(\Leftrightarrow x.\dfrac{5}{12}=5\)
\(\Leftrightarrow x=12\)