\(0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}-2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}\\ =\left(0,75-0,6-2,75-2,2\right)+3\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)+11\cdot\left(\dfrac{1}{7}+\dfrac{1}{13}\right)\\ =\left(-4,8\right)+\left(3+11\right)\cdot\dfrac{20}{91}\\ =-4,8+14\cdot\dfrac{20}{91}\\ =-\dfrac{24}{5}+\dfrac{40}{13}\\ =-\dfrac{112}{65}\)

0,75-0,6+\(\frac{3}{7}+\frac{3}{\frac{13}{2,75}}\) -2,2+\(\frac{11}{7}\) +\(\frac{11}{13}\)

=\(\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{11}{16}-\frac{11}{5}+\frac{11}{7}+\frac{11}{3}\)

= \(\left(\frac{11}{16}+\frac{3}{4}\right)+\left[\left(\frac{-3}{5}\right)-\frac{11}{5}\right]+\left(\frac{3}{7}+\frac{11}{7}\right)+\frac{11}{3}\)

= \(\frac{23}{16}-\frac{14}{5}+2+\frac{11}{3}\)

=\(\left(\frac{23}{16}+2\right)+\left[\left(\frac{-14}{5}\right)+\frac{11}{3}\right]\)

=\(\frac{55}{16}+\frac{13}{15}\)

\(\approx\) 4,3

chúc bạn học good (like nink nha)

chúc mừng cậu cậu đã nhầm vì đến phần 3/13 là trên số phép tính còn lại

= sửa thành + nhé

Đề bài yêu cầu gì?

\(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)

\(=\frac{\frac{3}{4}+\frac{3}{5}-\frac{3}{7}-\frac{3}{13}}{\frac{11}{4}+\frac{11}{5}-\frac{11}{7}-\frac{11}{13}}\)

\(=\frac{3.\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}{11.\left(\frac{1}{4}+\frac{1}{5}-\frac{1}{7}-\frac{1}{13}\right)}\)

\(=\frac{3}{11}\)

\(\frac{0,75-0,6-\frac{3}{7}+\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{13}}\)

\(=\frac{\frac{3}{4}-\frac{3}{5}+\frac{3}{7}+\frac{3}{13}}{\frac{11}{4}-\frac{11}{5}+\frac{11}{7}+\frac{11}{13}}\)

\(=\frac{3.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}{11.\left(\frac{1}{4}-\frac{1}{5}+\frac{1}{7}+\frac{1}{13}\right)}\)

\(=\frac{3}{11}\)

 A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{2,75+2,2-\frac{11}{7}-\frac{11}{3}}\)

A= \(\frac{0,75+0,6-\frac{3}{7}-\frac{3}{13}}{\frac{11}{3}\left(0,75+0,6-\frac{3}{7}-\frac{3}{13}\right)}\)

A=\(\frac{1}{\frac{11}{3}}\)

A= \(\frac{3}{11}\)

mình không hiểu lắm

=3/4-3/5+3/7+3/13 / 11/4-11/5+11/7+11/13   +   3/4-3/5+3/7+3/13 / 11/4-11/5+11/7+11/13

=3.1/4-3.1/5+3.1/7+3.1/13 / 11.1/4-11.1/5+11.1/7+11.1/13    +     3.1/4-3.1/5+3.1/7+3.1/13  /  11. 1/4-11.1/5+11.1/7+11.1/13

=3.(1/4-1/5+1/7+1/13) / 11.(1/4-1/5+1/7+1/13)     +   3.(1/4-1/5+1/7+1/13)   /  11.(1/4-1/5+1/7+1/13)

=3/11+3/11

=6/11

67,8 nhớ k đấy

Dấu "=" chính giữa mình ko biết là dấu + hay - nên mình sẽ làm cả hai TH nhé

TH1: \(P=\dfrac{0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}}+\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}}{\dfrac{11}{4}-\dfrac{11}{5}+\dfrac{11}{7}+\dfrac{11}{13}}\)

\(=\dfrac{3\left(0,25-0,2+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(0,25-0,2+\dfrac{1}{7}+\dfrac{1}{13}\right)}+\dfrac{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}=\dfrac{3}{11}+\dfrac{3}{11}=\dfrac{6}{11}\)

Tương tự TH2:

\(P=\dfrac{0,75-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{13}}-\dfrac{\dfrac{3}{4}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}}{\dfrac{11}{4}-\dfrac{11}{5}+\dfrac{11}{7}+\dfrac{11}{13}}=\dfrac{3}{11}-\dfrac{3}{11}=0\)