a) 15 x 21 - 16 : 4 + 7 

=    315    -      4    + 7

=           311   +     7

=             318

b) 123 - 11 x 6 + 150 : 30

=  123 -    66    +      5

=      57      +     5

=        62

Mình chỉ làm đến đó thôi chứ mấy câu còn lại khó hiểu quá!Ở lớp 5 mình chưa học bao giờ.

a)

=315-4+7=318

b)

=123-66+5=62

c)

=2017+5x[300-700:7]

=2017+5x[300-100]

=2017+5x200

=2017+1000

=3017

d)

=1560:[5x79-370+5x21]

=1560:[395-370+105]

=1560:130

=12

e)

=50-[12:2+34]

=50-40

=10

g)

=10-[16x5+88]:28

=10-168:28

=10-6

=4

ko hieu

x = 5 . Vì 15 va 20 dều là BC cua 5

\(\dfrac{x-1}{50}+\dfrac{x-2}{49}=\dfrac{x-3}{48}+\dfrac{x-4}{47}\)

\(\Rightarrow\dfrac{x-1}{50}-1+\dfrac{x-2}{49}-1=\dfrac{x-3}{48}-1+\dfrac{x-4}{47}-1\)

\(\Rightarrow\dfrac{x-51}{50}+\dfrac{x-51}{49}=\dfrac{x-51}{48}+\dfrac{x-51}{47}\)

\(\Rightarrow\dfrac{x-51}{50}+\dfrac{x-51}{49}-\dfrac{x-51}{48}-\dfrac{x-51}{47}=0\)

\(\Rightarrow\left(x-51\right)\left(\dfrac{1}{50}+\dfrac{1}{49}-\dfrac{1}{48}-\dfrac{1}{47}\right)=0\)

Vì \(\dfrac{1}{50}+\dfrac{1}{49}-\dfrac{1}{48}-\dfrac{1}{47}\ne0\) nên \(x-51=0\Rightarrow x=51\)

\(\dfrac{x+25}{6}+\dfrac{x+20}{11}+\dfrac{x+16}{15}+3=0\)

\(\Rightarrow\dfrac{x+25}{6}+1+\dfrac{x+20}{11}+1+\dfrac{x+16}{15}+1=0\)

\(\Rightarrow\dfrac{x+31}{6}+\dfrac{x+31}{11}+\dfrac{x+31}{15}=0\)

\(\Rightarrow\left(x+31\right)\left(\dfrac{1}{6}+\dfrac{1}{11}+\dfrac{1}{15}\right)=0\)

Vì \(\dfrac{1}{6}+\dfrac{1}{11}+\dfrac{1}{15}\ne0\) nên \(x+31=0\Rightarrow x=-31\)

\(\dfrac{x-15}{6}+\dfrac{x-10}{11}=\dfrac{x-3}{18}+\dfrac{x-7}{14}\)

\(\Rightarrow\dfrac{x-15}{6}-1+\dfrac{x-10}{11}-1=\dfrac{x-3}{18}-1+\dfrac{x-7}{14}-1\)

\(\Rightarrow\dfrac{x-21}{6}+\dfrac{x-21}{11}=\dfrac{x-21}{18}+\dfrac{x-21}{14}\)

\(\Rightarrow\dfrac{x-21}{6}+\dfrac{x-21}{11}-\dfrac{x-21}{18}-\dfrac{x-21}{14}=0\)

\(\Rightarrow\left(x-21\right)\left(\dfrac{1}{6}+\dfrac{1}{11}-\dfrac{1}{18}-\dfrac{1}{14}\right)=0\)

Vì \(\dfrac{1}{6}+\dfrac{1}{11}-\dfrac{1}{18}-\dfrac{1}{14}\ne0\) nên \(x-21=0\Rightarrow x=21\)

lần sau nhớ ghi rõ các phần ra , nhìn thek này phân biệt hơi khó :v

bài 1: 

\(a,21^{15}=3^{15}\times7^{15}\)

     \(27^5\times49^8=3^{15}\times7^{16}\)

Vậy: \(21^{15}< 27^5\times49^8\)

\(b,27^5=3^{15}\)

\(243^3=3^{15}\)

Vậy: \(27^5=243^3\)

Bài 2:

\(10^x+48=48^y\)

=100..0+48=\(48^y\)

=100...048=\(48^y\)

còn các bước tiếp mik chưa nghĩ ra cậu suy nghĩ thêm nhé