a) 6mũ3 : 6mũ2 + 94
b) 135 - 5mũ4 : 5mũ2
c) 7mũ3 : 7 - 4mũ5 : 4mũ3
d) 8mũ7 : 8mũ4 : 8mũ2 + 8
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c) 73 : 7 - 45 : 43
= 72 - 42
= 49 - 16
= 33
d) 87 : 84 : 82 + 8
= 8 + 8
= 16
a) 63 : 62 + 94
= 6 + 94
= 100
b) 135 - 54 : 52
= 135 - 52
= 135 - 25
= 110
\(a,6^3:6^2+94=6+94=100\\ b,135-5^4:5^2=135-5^2=110\\ c,7^3:7-4^5:4^3=7^2-4^2=33\\ d,8^7:8^4:8^2+8=8+8=16\)
a,63:62+94=6+94=100
b,135-54:52=135-52=135-25=110
c,73:7-45:43=72-42=49-16=33
d,87:84:82+8=8+8=16.
\(a,6^3:6^2+94=6+94=100\\ b,135-5^4:5^2=135-5^2=135-25=110\\ c,7^3:7-4^5:4^3=7^2-4^2=49-16=33\\ d,8^7:8^4:8^2+8=8^2+8=64+8=72\)
a, 21.52.17 = 2.25.17 = 50.17 = 850
b, 22 + 23 + 24 = 4 + 8 + 16 = 28
c, 25.3 + 24:8 + 50: 52
= 32.3 + 16:8 + 50:25
=96 + 2 + 2
= 100
d, 112 - 102 - 32
= 121 - 100 - 9
= 21 - 9
= 12
e, 13 + 23 + 33 + 43 + 53
= ( 1+ 2+3+4+5)2
= 152
= 225
1)Tính:
a)\(4^2\cdot2=\left(2^2\right)^2\cdot2=2^4\cdot2=2^5=32\)
b)\(36^2:6^2=\left(36:6\right)^2=6^2=48\)
c)\(\left(\frac{2}{5}\right)^{10}:\left(\frac{4}{25}\right)^2=\left(\frac{2}{5}\right)^{10}\cdot\left(\frac{25}{4}\right)^2=\)\(\left(1\right)^{10}\cdot\left(\frac{5}{2}\right)^2=1\cdot\frac{5^2}{2^2}=1\cdot\frac{25}{4}=\frac{25}{4}\)
a
\(4^2.2=16.2=32\)
b\(36^2:6^2=36.36:6.6=36.36:36=36\)
c
a) Ta có : A=2+22+23+...+210
=(2+22)+(23+24)+...+(29+210)
=2(1+2)+23(1+2)+...+29(1+2)
=2.3+23.3+...+29.3
Vì 3\(⋮\)3 nên 2.3+23.3+...+29.3\(⋮\)3
hay A\(⋮\)3
Vậy A\(⋮\)3.
Ta có :
4 mũ 3=4.4.4=64;8 mũ 2=8.8=64
Bởi vì 64=64 nên suy ra 4 mũ 3= 8 mũ 2
\(A=5+5^2+5^3+5^4+...+5^{39}+5^{40}\)
\(=\left(5+5^2\right)+\left(5^3+5^4\right)+...+\left(5^{39}+5^{40}\right)\)
\(=5\left(1+5\right)+5^3\left(1+5\right)+...+5^{39}\left(1+5\right)\)
\(=6\left(5+5^3+...+5^{39}\right)⋮6\)
Suy ra \(A⋮3,A⋮2\).
\(a,6^3:6^2+94=6+94=100\\ b,135-5^4:5^2=135-5^2=135-25=110\\ c,7^3:7-4^5:4^3=7^2-4^2=49-16=33\\ d,8^7:8^4:8^2+8=8+8=16\)
câu b 5 mũ 4 vứt đi hả ANH