(1 - 1/2) x (1 - 1/3) x (1 - 1/4) x (1 - 1/5) ...(1 - 1/100)
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`1/2 xx 1/3 xx 1/4`
`= (1xx1xx1)/(2xx3xx4)`
`= 1/24`
__
`1/2 xx 1/3 : 1/4`
`= 1/2 xx 1/3 xx 4`
`= (1xx1xx4)/(2xx3)`
`= 4/6`
`=2/3`
__
`1/2 : 1/3 xx1/4`
`= 1/2 xx 3 xx 1/4`
`=(1xx3xx1)/(2xx4)`
`= 3/8`
__
`1/2 : 1/3 : 1/4`
`= 1/2 xx 3xx4`
`= 12/2`
`=6`
`1/2xx1/3xx1/4`
`=1/24`
`1/2xx1/3:1/4`
`=1/6xx4`
`=4/6=2/3`
`1/2:1/3xx1/4`
`=1/2xx3xx1/4`
`=3/2xx1/4`
`=3/8`
`1/2:1/3:1/4`
`=1/2xx3xx4`
`=6`
Tìm X
\(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times\left(1-\frac{1}{5}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times\frac{4}{5}\)
\(=\frac{1}{5}\)
\(\Rightarrow x-100=\frac{1}{5}\)
\(x=\frac{1}{5}+100\)
\(x=\frac{1}{5}+\frac{500}{5}\)
\(x=\frac{501}{5}\)
Ta có : |1 - 5x| - 1 = 3
=> |1 - 5x| = 4
\(\Leftrightarrow\orbr{\begin{cases}1-5x=4\\1-5x=-4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}5x=1-4\\5x=1+4\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}5x=3\\5x=5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{5}\\x=1\end{cases}}\)
3/2.(x-5/3)+4/5=x+1
3/2.x-3/2.5/3+4/5=x+1
3/2.x-5/2-x=1+4/5
3/2.x-5/2-x=9/5
3/2.x-x=9/5+5/2
1/2.x=43/10
x=43/10:1/2
x=43/5
a, 2x3x4x8x25x125= (2x3)x(4x25)x(8x125)= 6x100x1000=600000
b,42/5 +56/9+23/4+3/5+1/3+1/4= (42/5+3/5)+(23/4+1/4)+(56/9+1/3)=9+6+59/9=
( 1 + x ) + ( 2 + x ) + ( 3 + x ) + ...+ ( 100 + x ) = 2018
\(\Rightarrow\)( 1 + 2 + 3 + ... + 100 ) + ( x + x + x + ... + x ) = 2018
\(\Rightarrow\){( 1 + 100 ) . [( 100 - 1 ) : 1 + 1 ] : 2 } + ( x + x + ... + x ) = 2018
\(\Rightarrow\)5050 + x . 100 = 2018
\(\Rightarrow\) x100 = 2018 - 5050 = -3032
\(\Rightarrow\)x = -3032 : 100 = -30,32
vậy x = -30,32
mà nè sai thì xin lỗi đề hơi có vấn đề nếu sai thì sorry nha !!!
`@` `\text {Ans}`
`\downarrow`
\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{1000}\right)\)
`=`\(\left(\dfrac{2}{2}-\dfrac{1}{2}\right)\times\left(\dfrac{3}{3}-\dfrac{1}{3}\right)\times\left(\dfrac{4}{4}-\dfrac{1}{4}\right)...\left(\dfrac{1000}{1000}-\dfrac{1}{1000}\right)\)
`=`\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{999}{1000}\)
`=`\(\dfrac{1}{1000}\)
\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}.......\dfrac{99}{100}=\dfrac{1}{100}\)