\(a,\dfrac{7}{12}-\left(x+\dfrac{7}{10}\right):\dfrac{6}{5}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{10}:\dfrac{6}{5}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x-\dfrac{7}{12}=\dfrac{5}{4}\)

\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{5}{4}+\dfrac{7}{12}\)

\(\Leftrightarrow\dfrac{7}{12}-x=\dfrac{11}{6}\)

\(\Leftrightarrow x=\dfrac{7}{12}-\dfrac{11}{6}\)

\(\Leftrightarrow\dfrac{-5}{4}\)

Còn phần B thì sao bn

Trả lời :
0 x 1 x 2 x 3 x 4 x 5 x 6 x 7 x 8 x 9 = 0.

#hoctot

=0 

k mk

mk mún có

#)Giải :

Đặt \(A=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\)

\(A=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+\frac{1}{8}-\frac{1}{9}+\frac{1}{9}-\frac{1}{10}\)

\(A=\frac{1}{5}-\frac{1}{10}\)

\(A=\frac{1}{10}\)

cho mk hỏi chút là tại sao ta lấy 1/5 - 1/6 r + 1/6....

A, 7[x + 5] - 20 = 190

7x + 35 - 20 = 190

7x + 15 = 190

7x = 175

x = 25

B, 155 - 10[x + 1] = 55

155 - 10x - 10 = 55

-10x + 90 = 55

-10x = -35

x = 3.5

C, 6[x + 2^3] + 40 = 100

6[x + 8] + 40 = 100

6x + 48 + 40 = 100

6x + 88 = 100

6x = 1

2 x = 2

D, 15x - 133 = 17

15x = 150

x = 10

E, 90[x + 2] = 45

90x + 180 = 45

90x = -135

x = -1.5

F, 4x + 54 = 82

4x = 28

x = 7

G, 17x - 20 = 14

17x = 34

x = 2

\(\frac{6}{7}+\frac{5}{7.\left(-5\right)}=\frac{-1}{28.\left(-2\right)^2}\)

\(< =>\frac{6\left(-35\right)}{7\left(-35\right)}+\frac{35}{7\left(-35\right)}=-\frac{1}{28.4}=-\frac{1}{112}\)

\(< =>\frac{5\left(-35\right)}{7\left(-35\right)}=-\frac{1}{112}\)

\(< =>\frac{1}{112}=\frac{1}{2.\left(-35\right)}\)

\(< =>-35.2=112\)(vô lý)

a) Bạn xemm lại đề nhé.

b) \(5\left(x+35\right)=515\)

\(x+35=515\div5\)

\(x+35=103\)

\(x=103-35\)

\(x=68\)

Vậy \(x=68\).

c) \(90-3\left(x+1\right)=42\)

\(3\left(x+1\right)=90-42\)

\(3\left(x+1\right)=48\)

\(x+1=48\div3\)

\(x+1=16\)

\(x=16-1\)

\(x=15\)

Vậy \(x=15\).

d) \(12x-33=3^2.3^3\)

\(12x-33=3^5\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=276\div12\)

\(x=23\)

Vậy \(x=23\).

e) \(100-7\left(x-5\right)=58\)

\(7\left(x-5\right)=100-58\)

\(7\left(x-5\right)=42\)

\(x-5=42\div7\)

\(x-5=6\)

\(\Rightarrow x=6+5=11\)

Vậy \(x=11\).

j) \(24+5x=7^5\div7^3\)

\(24+5x=7^2\)

\(24+5x=49\)

\(5x=49-24\)

\(5x=25\)

\(\Rightarrow x=25\div5=5\)

Vậy \(x=5\).

541+(218-x)=735

(218-x)=735-541

(218-x)=194

x=218-194

x=24

vậy x=24

5 (x+35)=515

(x+35)=515:5

(x+35=103

x=103-35

x=68

vậy x=68

90-3 (x+1)=42

3 (x+1)=90-42

3 (x+1)=48

(x+1)=48:3

(x+1)=16

x=16-1

x=15

vậy x=15

12x-33=3^2.3^3

12x-33=3^5

12x-33=243

12x=243-33

12x=210

x=210:12

x=17,5

vậy x=17,5

100- 7 (x-5)=58

7 (x-5)=100-58

7 (x-5)=42

(x-5)=42:7

(x-5)=6

x=6-5

x=1

vậy x=1

24+5x=7^5:7^3

24+5x=7^2

24+5x=49

5x=49-24

5x=25

x=25:5

x=5

vậy x=5

a) Quy đồng : 7/40 = 21/120 . Ta có :

21/120 + 11/120 = 32/120

b) Rút gọn : 24/146 = 12/73 . Quy đồng : 12/73 = 156/949 ; 6/13 = 438/949 . Ta có :

156/949 + 438/949 = 594/949

c)Quy đồng : 7/30 = 28/120 ; 13/60 = 26/120 ; -9/40 = -27/120 . Ta có :

28/120 + 26/120 + -27/120 = 27/120

d) Rút gọn : -64/90 = -32/45 . Quy đồng : 17/60 = 51/180 ; -5/18 = -50/180 ; -32/45 = -128/180 . Ta có :

51/180 + -50/180 + -128/180 = -127/180

ADSVN. VNtheo mình bạn nên cách ra bớt để nó dính như vậy nhìn rối lắm:D vả lại bạn cũng làm sai rồi