a: \(=\dfrac{4\cdot11\cdot3}{4\cdot9}\cdot\dfrac{1}{121}=\dfrac{11}{121}\cdot\dfrac{1}{3}=\dfrac{1}{33}\)

b: \(=\dfrac{7}{9}\left(\dfrac{3}{4}+\dfrac{1}{4}\right)=\dfrac{7}{9}\)

c: \(=\dfrac{-6}{7}-\dfrac{1}{7}+\dfrac{2}{11}+\dfrac{9}{11}+\dfrac{12}{17}=\dfrac{12}{17}\)

( x - 3 ) - 7 = 63

x - 3 = 56

=> x = 59

a: \(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^8\cdot5}=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+5\right)}=\dfrac{-2}{6}=\dfrac{-1}{3}\)

b: \(=\dfrac{5^{16}\cdot3^{21}}{5^{15}\cdot3^{22}}=\dfrac{5}{3}\)

cho xin đáp án chi tiết điiiii

Đề bài yêu cầu gì?

\(=\dfrac{2.3^9.2^9-\left(2^2\right)^5.\left(3^2\right)^4}{2^{10}.3^7+3^7.2^7.2^3.5}\\ =\dfrac{2^{10}.3^9-2^{10}.3^8}{2^{10}.3^7+3^7.2^{10}.5}\\ =\dfrac{2^{10}.3^8\left(3-1\right)}{2^{10}.3^7\left(1+5\right)}\\ =\dfrac{3.2}{6}=\dfrac{6}{6}=1\)

h mới dậy ko bt lmj cả:(

a,   x/12=10

    x=10*12=120

b. 159/n=3

n=19539/

a) x : 12 = 10

    x        = 12 . 10

    x        = 120

b) 159 : n = 3

             n = 159 : 3

             n = 53

c) (x - 3) - 7 = 63

     x - 3 - 7  = 63

     x - 10     = 63

     x            = 63 + 10

     x            = 73