27^2.2^3.5^4 phần 15^2.6^9 rut gon
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Ta có:
\(\frac{5^2.6^{11}.16^2.6^2.12^6.15^2}{2.6^{12}.10^4-81^2.960^3}\) = \(\frac{5^2.6^{11}.6^2.6^2.6^6.2^6.3^2.5^2}{2.2^{12}.3^{12}.2^4.5^4-3^8.2^{15}.3^3}\) = \(\frac{5^6.6^{21}.2^8.3^2}{2^{17}.3^{12}.5^4-3^{11}.2^{15}}\) = \(\frac{5^6.3^{23}.2^{29}}{3^{11}.2^{15}.\left(2^2.3.5^4-1\right)}\)
= \(\frac{5^6.3^{13}.2^{14}}{2^2.3.5^4-1}\)
Nhớ cho mk nha bạn!
(-2)^3.3^3.5^3.7.8/3.5^3.2^4.42
=(-2)^2.(-2).3^3.5^3.7.8/3.5^3.2^2.2^2.7.6
=4.(-2).3^3.5^3.7.8/3.5^3.4.4.7.6
=-1.3^2.8/6
=-72/6=-12
\(\frac{\left(-2\right)^3.3^3.5^3.7.2^3}{3.5^3.2^4.2.3.7}\)=\(\frac{\left(-2\right)^2.\left(-2\right).3^3.5^3.7.2^3}{3^2.5^3.2^5.7}\)=\(\frac{2^5.\left(-2\right).3}{2^5}\)=\(-6\)
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
\(=\frac{2^{19}.\left(3^3\right)^3+3.5.\left(2^2\right)^9.\left(3^2\right)^4}{\left(2.3\right)^9.2^{10}+\left(2^2.3\right)^{10}}\)
\(=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)
\(=\frac{2^{19}.3^9+2^{19}.3^9.5}{2^{19}.3^9+2^{20}.3^{10}}\)
\(=\frac{2^{19}.3^9.\left(1+5\right)}{2^{19}.3^9\left(1+2.3\right)}\)
\(=\frac{6}{7}\)
\(B=\frac{4^2.25^2+32.125}{2^3.5^2}=\frac{2^4.5^4+2^5.5^3}{2^3.5^2}\)
\(=\frac{2^4.5^3\left(5+2\right)}{2^3.5^2}=\frac{2^3.5^2.2.5.7}{2^3.5^2}=2.5.7=70\)
`#3107.101107`
\(\dfrac{27^2\cdot2^3\cdot5^4}{15^2\cdot6^9}\)
\(=\dfrac{\left(3^3\right)^2\cdot2^3\cdot5^4}{3^2\cdot5^2\cdot2^9\cdot3^9}\)
\(=\dfrac{3^6\cdot2^3\cdot5^4}{3^{11}\cdot5^2\cdot2^9}\)
\(=\dfrac{5^2}{3^5\cdot2^6}\)
\(=\dfrac{25}{15552}\)