a) \(232-\left(581+132-331\right)\)

\(=232-581-132+331\)

\(=\left(232-132\right)+\left(331-581\right)\)

\(=100-250\)

\(=-150\)

b) \(\left[12+\left(-57\right)\right]-\left[-57-\left(-12\right)\right]\)

\(=12-57+57-12\)

\(=\left(12-12\right)+\left(57-57\right)\)

\(=0+0\)

\(=0\)

a) 232 - ( 581 + 132 - 331 )

= 232 - 581 - 132 + 331

= ( 232 - 132 ) - ( 581 - 331 )

= 100 - 250

= -150

a: \(232-\left(581+132-331\right)\)

\(=232-581-132+331\)

\(=\left(232-132\right)+\left(-581+331\right)\)

\(=100-250\)

=-150

b: \(\left[12+\left(-57\right)\right]-\left[-57-\left(-12\right)\right]\)

\(=12+\left(-57\right)+57+\left(-12\right)\)

\(=\left(12-12\right)+\left(57-57\right)\)

=0+0

=0

`a, 232 - ( 581 + 132 -331)`

`= 232 - 581 - 132 +331`

`= (232-132) +(-581 + 331)`

`= 100 -250`

`=-150`

`b, [12+ (-57)] - [-57-(-12)]`

`= 12+ (-57) - (-57+12)`

`= 12+ (-57) + 57 -12`

`= (12-12) + (-57+57)`

`= 0+0`

`=0`

`a)232-(581+132-331)`

`=232-581-132+331`

`=(232-132)-(581-331)`

`=100-250`

`=-150`

`b)[12+(-57)]-[-57-(-12)]`

`=(12-57)-(-57+12)`

`=12-57+57-12`

`=(12-12)-(57-57)`

`=0-0`

`=0`

a, -321 + (-29 ) - 142 - (-72) = -321 - 29 - 142 + 72 = -420.

b, 214 - (-36) + (-305) = 214 + 36 - 305 = -55.

c, 232 - (581 + 132 - 331) = 232 - 581 - 132 + 331 = -150.

d, [ 12+ (-57)] - [-57 -  (-12) = 12 - 57 + 57 - 12 = 0.

Bài 3.21:

b: =28+19-28-32+57

=76-32

=44

Bài 1:

a, 386-287 -386 -13

= (386-386) -287-13

= 0 -300

=-300

b, =332-681 -232+431

= (332 -232) +(431-681)

= 100 - 250

= -150

Bài 2

a, = 27+65+ 364-27-65

= (27-27) +(65-65) +364

= 0+0+ 364

=364

b, = 42-69+17 -42-17

= (42-42) + (17-17) -69

= -69

chúc bạn học tốt nha!

a) 2763 + 152 = 2915

\(2915\)

1x\(10^{17}\)

100000000000000000

\(a.\) \(50\cdot374\cdot2=\left(50\cdot2\right)\cdot347=100\cdot347=34700\)

\(b.\)\(36\cdot97+97\cdot64=97\cdot\left(36+64\right)=97\cdot100=9700\)

\(c.157\cdot289-289\cdot57=289\cdot\left(157-57\right)=289\cdot100=28900\)