a) 1968 x 15 + 1968 x 84 + 1968

= 1968 x 15 + 1968 x 84 + 1968 x 1

= 1968 x (15 + 84 + 1)

= 1968 x 100 = 196800

b) 6412 + 5378 + 3582 + 4628

= (6412 + 5378) + (3582 + 4628)

= 11790 + 8210

= 20000

c) 178 x 101 - 178

= 178 x 101 - 178 x 1

= 178 x (101 - 1)

= 178 x 100

= 17800

d) 153 x 8 + 153 + 153

= 153 x 8 + 153 x 1 + 153 x 1

= 153 x (8 + 1 + 1)

= 153 x 10

= 1530

B1:

\(a.301^2=\left(300+1\right)^2=300^2+2.300.1+1^2\\ =90000+600+1=90601\\ b.88^2+2.88.12+12^2=\left(88+12\right)^2=100^2=10000\\ c.99.100=100^2-100=10000-100=9900\\ d,153^2+94.153+47^2=153^2+2.153.47+47^2=\left(153+47\right)^2=200^2=40000\)

B2:

\(A=x^2-20x+101\\ =x^2-2.x.10+10^2+1\\ =\left(x-10\right)^2+1\ge1\forall x\in R\left(Vì:\left(x-10\right)^2\ge0\forall x\in R\right)\\ \Rightarrow min_A=1\Leftrightarrow x-10=0\Leftrightarrow x=10\)

a: =(1-2-3+4)+(5-6-7+8)+...+(21-22-23+24)

=0+0+...+0

=0

b: =-7111+53+711-153=-6400-100=-6500

c: =-43(-1-296+296)=-43*(-1)=43

a)67.153-53.67+712:8

=67.(153-53)+89

=67.100+89

=6789

\(a,67\times153-53\times67+712:8\)

\(=67\times\left(153-53\right)+\left(712:8\right)\)

\(=67\times100+89\)

\(=6700+89\)

\(=6789\)

\(b,168-\left\{5\times\left[143-\left(15-12\right)^2\right]+10\right\}:10\)

\(=168-\left\{5\times\left[143-3^2\right]+10\right\}:10\)

\(=168-\left\{5\times134+10\right\}:10\)

\(=168-\left\{670+10\right\}:10\)

\(=168-680:10\)

\(=168-68\)

\(=100\)

\(c,\left(-13\right)+84+\left(-87\right)+16\)

\(=13+84-87+16\)

\(=\left(13+87\right)-\left(84+16\right)\)

\(=100-100\)

\(=0\)

\(d,9-\left(12-15\right)\)

\(=9-\left(-3\right)\)

\(=12\)

*19,96+4,19-24,15:(1/4-1/4)         *252/x=84/97

=19,96+4,19-24,15:0                          x=252x97:84

=19,96+4,19-0                                    x=291

=24,15-0                                      * x-2/255=114/153

=24,15                                          x-2/255=38/51 

                                                     x=38/51+2/255

                                                     x=64/85

a ) ko rõ đề

b )\(\frac{252}{x}=\frac{84}{97}\)

=> 252 . 97 = x . 84

=> x . 84 = 24 444

x = 24 444 : 84

x = 291

Vậy x = 291

c ) x - \(\frac{2}{255}=\frac{114}{153}\)

x = 114/153 + 2/255

x = 64/85

Vậy x = 64/85

(-33)+45+(-67)
=[(-33)+(-67)]+45
=(-100)+45
=55
mấy câu sau mỏi tay nên ghi đáp án thoi
c=3
2a     x=10

Bài 1:

a, (-33) + 45 + (-67)

= - (33 + 67) + 45

= - 100 + 45

= - 55 

c, 75 : [ (153 - 6.52).8 + 2011⁰ ]

= 75 : [ 153 - 312].8 + 1]

= 75 : [ - 159.8 + 1]

= 75 : [-1272 + 1]

= 75 : (-1271)

= - \(\dfrac{75}{1271}\)

Bài 2

6\(x\) + 15 = 75

6\(x\)         = 75 - 15

6\(x\)        = 60

  \(x\)        = 60 : 6

   \(x\)       = 10

-(15+153-170)+(153-170-915)

-15-153+170-153+170+915

(153-153)+(170-170)+(-15-915)

0+0+(-930)

-930

a)-x+y+z

b)-(15+153-170)+(153-170-915)=-930

a: 15/x=10/15

nên x=22,5

b: 3/x=51/85

=>3/x=3/5

hay x=5

zào nhầm nick chệ r ;-;