3/3 - 1/4.x=0,25
=> 1-1/4x=0,25
        1/4x=1-0,25
        1/4x=0,75
             x=0,75:1/4
             x=3

Vậy x=3
 

a) 0,25x3/4-0,25x0,25+0,25x1/2

=0,25x(3/4-0,25+1/2)

=0,25x1

=0,25

b) 5,68x8+56,8x0,1+56,8:10

=5,68x8+5,68+5,68

=5,68x(8+1+1)

=5,68x10

=56,8

bài này mk vừa mới giúp bạn đó, tìm đi, có đó

( Chúc you học good )

\(9\times\left(\dfrac{-1}{3}\right)^3+\dfrac{1}{3}:0,25-5\dfrac{3}{4}=\dfrac{9}{1}\times\left(\dfrac{-1}{27}\right)+\dfrac{1}{3}:\dfrac{1}{4}-\dfrac{23}{4}\)

\(=\left(\dfrac{-9}{27}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\left(\dfrac{-1}{3}\right)+\dfrac{4}{3}-\dfrac{23}{4}=\dfrac{3}{3}-\dfrac{23}{4}=1-\dfrac{23}{4}=\dfrac{4}{4}-\dfrac{23}{4}=\dfrac{-19}{4}\)

= -\(\dfrac{19}{4}\)

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Mình xin lỗi câu này mình ko biết

\(\frac{2}{3}\cdot x-\frac{1}{4}\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\cdot\frac{2}{3}\)

\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\cdot\frac{2}{3}\)

\(\Rightarrow\frac{2}{3}\cdot x-\frac{1}{4}\cdot\frac{7}{12}=\frac{1}{6}\)

\(\Rightarrow\frac{2}{3}.x-\frac{7}{48}=\frac{1}{6}\)

\(\Rightarrow\frac{2}{3}x=\frac{5}{16}\)

\(\Rightarrow x=\frac{15}{32}\)

\(\frac{2}{3}\times x-\frac{1}{4}:\left(1\frac{1}{3}-\frac{3}{4}\right)=0,25\times\frac{2}{3}\)

\(\frac{2}{3}\times x-\frac{1}{4}:\left(\frac{4}{3}-\frac{3}{4}\right)=\frac{1}{4}\times\frac{2}{3}\)

\(\frac{2}{3}\times x-\frac{1}{4}:\frac{7}{12}=\frac{1}{6}\)

\(\frac{2}{3}\times x-\frac{3}{7}=\frac{1}{6}\)

\(\frac{2}{3}\times x=\frac{1}{6}+\frac{3}{7}\)

\(\frac{2}{3}\times x=\frac{25}{42}\)

\(x=\frac{25}{42}:\frac{2}{3}\)

\(x=\frac{25}{28}\)

\(x-0.25=-\frac{6}{11}\cdot\left(\frac{1}{2}+\frac{3}{4}-\frac{1}{3}\right)\)

\(x-\frac{1}{4}=-\frac{6}{11}\cdot\left(\frac{6}{12}+\frac{9}{12}-\frac{4}{12}\right)\)

\(x-\frac{1}{4}=-\frac{6}{11}\cdot\frac{11}{12}\)

\(x-\frac{1}{4}=-\frac{1}{2}\)

\(x=-\frac{1}{2}+\frac{1}{4}\)

\(x=-\frac{2}{4}+\frac{1}{4}\)

\(x=-\frac{1}{4}\)

Vậy .......