khùng ak???

Thằng điên chả ghi đề mà bảo nguời ta làm

Phân só đâu Shinichi Kudo

p/s ?

\(=\frac{3\text{x}5x7x11\text{x}13\text{x}37-3\text{x}7\text{x}13\text{x}37}{2^3x3^2x5\text{x}7\text{x}13\text{x}37+2^2x3\text{x}7\text{x}13\text{x}37}=\frac{3\text{x}7\text{x}13\text{x}37\left(5\text{x}11-1\right)}{2^2x3\text{x}7\text{x}13\text{x}37\left(2\text{x}3\text{x}5+1\right)}\)

\(=\frac{54}{2^2x31}=\frac{54}{124}=\frac{27}{62}\) thử lại kết quả rồi nhé

27/62

5.7.11.13.37-10101/1212120+40404

=3.5.7.11.13.37-10101/1212120.1/10+40404 (vì 1/1212120=1/121212.1/10)

= 3.37.7.11.13.5-101010/121212.1/100+40404

=111.1001.5-5/6.1/100+40404

=151515.5-250/3

=595959-250/3

=1787876/3

Dùng latex

là j vậy

tui hỏi toán

\(\frac{27}{62}\)

a: \(\dfrac{31995-81}{42660-108}=\dfrac{31914}{42552}=\dfrac{3}{4}\)

b: \(\dfrac{3\cdot5\cdot7\cdot11\cdot13\cdot37-10101}{1212120+40404}=\dfrac{545454}{1252524}=\dfrac{27}{62}\)

a, $\frac{31995-81}{42660-108}$

= $\frac{395.81-81}{395.108-108}$

=$\frac{81.394}{394.108}$

= $\frac{81}{108}$          = $\frac{3}{4}$

b, $\frac{3.5.7.11.13.37-10101}{1212120+40404}$

= $\frac{3.5.7.11.13.37-3.7.13.37}{\mathrm{3.7.12.13.37.10}+\mathrm{3.4.7.13.37}}$

= $\frac{\left(\mathrm{3.7.13.37}\right)(5.11-1)}{\left(\mathrm{3.7.13.37}\right)(120+4)}$

= $\frac{5.11-1}{120+4}$

= $\frac{54}{124}$ = $\frac{27}{62}$

a, \(\dfrac{3.5.7.11.13.37-10101.55}{1212120+40404}\)

\(=\dfrac{55\left(3.7.13.37-10101\right)}{1212120+40404}\)

\(=\dfrac{55.0}{1212120+40404}=0\)

b, \(\dfrac{5+55+555+5555}{9+99+999+9999}\)

\(=\dfrac{5.\left(1+11+111+1111\right)}{9.\left(1+11+111+1111\right)}=\dfrac{5}{9}\)

Chúc bạn học tốt!!!