\(=49+\dfrac{8}{23}-5-\dfrac{7}{32}-14-\dfrac{8}{32}\)

\(=30-\dfrac{89}{736}=\dfrac{21991}{736}\)

Bài 1: 

a) \(\sqrt{72}:\sqrt{8}=\sqrt{72:8}=3\)

b) \(\left(\sqrt{28}-\sqrt{7}+\sqrt{112}\right):\sqrt{7}=5\sqrt{7}:\sqrt{7}=5\)

Bài 2: 

a) \(\sqrt{\dfrac{49}{8}}:\sqrt{3\dfrac{1}{8}}=\sqrt{\dfrac{49}{8}:\dfrac{25}{8}}=\sqrt{\dfrac{49}{25}}=\dfrac{7}{5}\)

b) \(\sqrt{54x}:\sqrt{6x}=\sqrt{54x:6x}=\sqrt{9}=3\)

c) \(\sqrt{\dfrac{1}{125}}\cdot\sqrt{\dfrac{32}{35}}:\sqrt{\dfrac{56}{225}}\)

\(=\dfrac{\sqrt{5}}{25}\cdot\dfrac{4\sqrt{2}}{\sqrt{35}}:\dfrac{2\sqrt{14}}{15}\)

\(=\dfrac{\sqrt{5}\cdot4\sqrt{2}\cdot15}{25\cdot\sqrt{35}\cdot\sqrt{14}\cdot2}\)

\(=\dfrac{6}{35}\)

em cảm ơn ạ 

  chúc bạn học tốt

a: \(\dfrac{7}{3}+\dfrac{4}{9}=\dfrac{21}{9}+\dfrac{4}{9}=\dfrac{21+4}{9}=\dfrac{25}{9}\)

b: \(\dfrac{3}{14}+6=\dfrac{3+6\cdot14}{14}=\dfrac{84+3}{14}=\dfrac{87}{14}\)

c: \(\dfrac{7}{8}-\dfrac{1}{2}=\dfrac{7}{8}-\dfrac{4}{8}=\dfrac{7-4}{8}=\dfrac{3}{8}\)

d: \(5-\dfrac{9}{10}=\dfrac{50}{10}-\dfrac{9}{10}=\dfrac{50-9}{10}=\dfrac{41}{10}\)

a) 9
b)90
c)8
d)7/10
e)2/5

a=9

b=90

c=2

d=0,7

e=0,2

a, -49

b, 25

c, 40

d, -88

a) (-10)-21-18=-(10+21+18)=-49

b) 24-(-16)+(-15)=24+16-15=40-15=25

c) 49-[15+(-6)]=49-9=40

d) (-44)-[(-14)-30]=-44-(-44)=0

\(=\dfrac{x^2+2x+1+x^2-4x+4+x-14}{\left(x-2\right)\left(x+2\right)}=\dfrac{2x^2-x-9}{\left(x-2\right)\left(x+2\right)}\)

a: \(\sqrt{4\cdot36}=\sqrt{144}=12\)

b: \(\left(\sqrt{8}-3\sqrt{2}\right)\cdot\sqrt{2}\)

\(=\left(2\sqrt{2}-3\sqrt{2}\right)\cdot\sqrt{2}\)

\(=-\sqrt{2}\cdot\sqrt{2}=-2\)

c: \(\dfrac{\sqrt{14}-\sqrt{7}}{1-\sqrt{2}}=\dfrac{-\sqrt{7}\left(1-\sqrt{2}\right)}{1-\sqrt{2}}=-\sqrt{7}\)

d: \(\dfrac{2}{\sqrt{5}+2}+\dfrac{2}{\sqrt{5}-2}\)

\(=\dfrac{2\left(\sqrt{5}-2\right)+2\left(\sqrt{5}+2\right)}{5-4}\)

\(=2\sqrt{5}-4+2\sqrt{5}+4=4\sqrt{5}\)

Bài 1:

a)-54

b)-8

Bài 2:

a)(x-14):5=4¹⁵:4¹³

⇔(x-14):5=4²

⇔(x-14):5=16

⇔x-14=80

⇔x=94

b)7x-15x=15-175

⇔-8x=-160

⇔x=20

cho mik xin cách làm của bài 1