100/29=100 phần 29

ko co ket qua

\(\left(2008-x\right):29+32=100\)

\(\Leftrightarrow\left(2008-x\right):29=68\)

\(\Leftrightarrow2008-x=1972\)

\(\Leftrightarrow x=36\)

(Tíck cho mìk vs nhá!)

( 2008 - x ) : 29 + 32 = 100

( 2008 - x ) : 29 = 100 - 32

( 2008 - x ) : 29 = 68

2008 - x = 68 x 29

2008 - x = 1972

x = 2008 - 1972

x = 36

 Vậy x = 36

\(\left(2009-x\right):29+32=100\\ =>\left(2009-x\right):29=100-32=68\\ =>2009-x=68.29=1972\\ =>x=2009-1972=37\)

-

\(\left(x-2\right).3-270:45=120\\ =>3\left(x-2\right)-6=120\\ =>3\left(x-2\right)=120+6=126\\ =>x-2=126:3=42\\ =>x=42+2=44\)

( 2015 - x ) : 29 + 32 = 100

( 2015 - x ) : 29 = 100 - 32

( 2015 - x ) : 29 = 68

2015 - x = 68 x 29

2015 - x = 1972

x = 2015 - 1972

x = 43

L i k e nha các bạn !!!

(2015-x):26=100-32

(2015-x):26=68

2015-x=68x26

2015-x=1768

x=2015-1768

x=247
 

#)Giải :

a)\(\left(x-149\right)\div35=270\)

\(\Leftrightarrow x-149=9450\)

\(\Leftrightarrow x=9599\)

\(a,(x-149):35=270\)

\(\Leftrightarrow x-149=9450\)

\(\Leftrightarrow x=9450+149=9599\)

Vậy x = 9599

\(b,(2009-x):29+32=100\)

\(\Leftrightarrow(2009-x):29=68\)

\(\Leftrightarrow2009-x=1972\)

\(\Leftrightarrow x=2009-1972=37\)

Vậy x = 37

\(c,x+472=918\)

\(\Leftrightarrow x=918-472=446\)

Vậy x = 446

bài 2 tìm x

a,106- ( x+ 7) =9

x+7 = 106 - 9

x+7 = 107

x= 107 - 7

x=100

b, 2 x ( x+ 4) + 5 =65

2 x (x+4) = 65 - 5

2 x (x+4) = 60

x+4 = 60:2

x+4= 30

x= 30 - 4

x=26

c, (16x x -32) x 45=0

16 x X - 32 = 0: 45

16 x X - 32 =0

16 x X = 0 + 32

16 x X = 32

X= 32:16

X=2

d, x+4 x x = 100 : 5

X + 4 x X = 20

(1+4) x X = 20

5 x X  = 20

X= 20:5

X=4

ủa bài 1 đâu =]]

\(\frac{58}{27}.\frac{54}{29}< x< \frac{100}{3}-\frac{9}{13}\)

\(4< x< 32\frac{25}{39}\)

\(=>x\in\left\{5;6;7...;32\right\}\)

K cho mik với nhé