Tính bằng cách thuận tiện nhất:
-5/8 + 14/8 - 3/8 + 2/9 - 1/2006
17 2/31 + (2 4/7 - 6 2/31)
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a; 5\(\dfrac{3}{4}\) : 3 + 2\(\dfrac{1}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) : 3 + \(\dfrac{9}{4}\).\(\dfrac{1}{3}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{4}\) x \(\dfrac{1}{3}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{23}{12}\) + \(\dfrac{3}{4}\) - \(\dfrac{3}{8}\)
= \(\dfrac{46}{24}\) + \(\dfrac{18}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{64}{24}\) - \(\dfrac{9}{24}\)
= \(\dfrac{55}{24}\)
9+3+2+1+7+8+5+10+6+4= (9+1)+(2+8)+(3+7)+(4+6)+5=10+10+10+10+5=10.4+5=40+5=45
5/7-4/19+2/7-15/19-1999/2006=(5/7+2/7)-(4/19+15/19)-1999/2006
=1-1-1999/2006=0-1999/2006=-1999/2006
\(A=\frac{\left[\left(25-1\right):1+1\right]\left(25+1\right)}{2}=325.\)
\(B=\frac{\left[\left(51-3\right):2+1\right]\left(51+3\right)}{2}=675\)
\(C=\frac{\left[\left(81-1\right):4+1\right]\left(81+1\right)}{2}=861\)
\(\frac{1.3.5+2.6.10+4.12.20+7.21.35}{1.5.7+2.10.14+4.20.28+7.35.49}\)
\(=\frac{1.3.5\left(1+2+4+7\right)}{1.5.7\left(1+2+7+7\right)}=\frac{1.3.5}{1.5.7}=\frac{15}{35}=\frac{3}{7}\)
\(\frac{1\cdot3\cdot5+2\cdot6\cdot10+4\cdot12\cdot20+7\cdot21\cdot35}{1\cdot5\cdot7+2\cdot10\cdot14+4\cdot20\cdot28+7\cdot35\cdot49}\)
\(=\)\(\frac{1\cdot3\cdot5\cdot\left(1+2+4+7\right)}{1\cdot5\cdot7\cdot\left(1+2+7+7\right)}\)
\(=\frac{1\cdot3\cdot5}{1\cdot5\cdot7}\)\(=\frac{15}{35}=\frac{3}{7}\)
bn vội quá viết nhầm lun kìa
hj hj chúc bn làm bài tốt nha
Tính bằng cách thuận tiện nhất
a,5*12*3*7/3*8*7*5
b, 2*5*4*6/4*3*5*7
Làm nhanh nha , mình đang cần gấp
a)
\(\frac{5.12.3.7}{3.8.7.5}=\frac{1.12.1.1}{1.8.1.10}=\frac{12}{8}=\frac{3}{2}\)
b)
\(\frac{2.5.4.6}{4.3.5.7}\frac{2.1.1.2.3}{1.1.1.7}=\frac{12}{7}\)
HOK TỐT!
a) 3/8 x 14/53 x 8/3
=3/8x8/3x14/53
= 1 x 14/53
=14/53
b) 9/17x1/5+9/17x4/5
=9/17x(1/5+4/5)
=9/17x 5/5
=9/17x1
= 9/17
Li-ke cho mik nhé!
1200-31/40=47969/40
câu 2 =45/56+25/56=(45+25)/56=70/56=5/4
1+2+3+4+5+6+7+8+9 = ( 1+9) + ( 2+8) + (3+7) + (4+6) +5
= 10 + 10 + 10 + 10 + 5
= 45
- \(\dfrac{5}{8}\) + \(\dfrac{14}{8}\)- \(\dfrac{3}{8}\) + \(\dfrac{2}{9}\) - \(\dfrac{1}{2006}\)
= -(\(\dfrac{5}{8}+\dfrac{3}{8}\)) + \(\dfrac{7}{4}\) + \(\dfrac{2}{9}\) - \(\dfrac{1}{2006}\)
= - 1 + \(\dfrac{7}{4}\) + \(\dfrac{2}{9}\) - \(\dfrac{1}{2006}\)
= \(\dfrac{3}{4}\) + \(\dfrac{2}{9}\) - \(\dfrac{1}{2006}\)
= \(\dfrac{35}{36}\) - \(\dfrac{1}{2006}\)
= \(\dfrac{35087}{36108}\)