a)\(x^{15}=x\Rightarrow x\in\left\{0;1\right\}\)                                            d)Là ý b

b)\(\left(2x+1\right)^3=125\\ \left(2x+1\right)^3=5^3\Rightarrow2x+1=5\\ 2x=4\\ x=2\)                       e)\(\left(x-3\right)^2=25\\ \Rightarrow\left(x-3\right)^2=5^2\\ \Rightarrow\hept{\begin{cases}x-3=5\Rightarrow x=8\\x-3=-5\Rightarrow x=-2\end{cases}}\)

c)\(\left(x-5\right)^4=\left(x-5\right)^6\\ \Rightarrow x-5\in\left\{0;1\right\}\Rightarrow x\in\left\{5;6\right\}\)

Chăc chết      \(\left(3.4.2^{16}\right)^2:\left(11.2^{13}.4^{11}-16\right)^{19}\)

o nung qua nung qua de

Câu 2.

a) Chứng minh: (ac + bd)² + (ad – bc)² = (a² + b²)(c² + d²)

b) Chứng minh bất dẳng thức Bunhiacôpxki: (ac + bd)² ≤ (a² + b²)(c² + d²)                                                                                                                        ai giúp tui đi!!!

\(\sqrt{\left(3x-1\right)^2}=\left|3x-1\right|=\orbr{\begin{cases}3x-1\left(x\ge\frac{1}{3}\right)\\1-3x\left(x< \frac{1}{3}\right)\end{cases}}\)

707: [(2^x -5) + 74] = 4² - 3²

(2^x -5) + 74 = 101

2^x - 5 + 74  = 101

2^x + 69 = 101

2^x = 32 = 2⁵

=> x = 5

707: [(2^x -5) + 74] = 4² - 3²

(2^x -5) + 74 = 101

2^x - 5 + 74  = 101

2^x + 69 = 101

2^x = 32 = 2⁵

=> x = 5

\(\left(3x-2\right)^3=2.32\)

\(\Leftrightarrow\left(3x-2\right)^3=64\)

\(\Leftrightarrow\left(3x-2\right)^3=4^{^3}\)

\(\Rightarrow3x-2=4\)

\(\Leftrightarrow3x=6\)

\(\Leftrightarrow x=2\)

Vậy \(x=2\)

kết quả bằng 17

cactoon

=2^4.5-{131-(13-4)^2}

=80-{131-9^2}

=80-50

=30

HT

=16.5-{131-9^2}

=80-{131-81}

=80-50

=30

__HT__

\(f\left(-1\right)=3\times\left(-1\right)^2+1=4\)

=>chọn C

f(-1) = 3.(-1)\(^{^2}\)+1 = 4

c là đáp án đúm nha