- Ôi dễ vãi ~~

Ta có:

\(\frac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\frac{2^{35}.\left(9.5\right)^{25}.13^{22}.\left(5.7\right)^{16}}{9^{26}.\left(5.13\right)^{22}.\left(7.4\right)^{17}.\left(5.5\right)^9}\)

\(=\frac{2^{35}.9^{25}.5^{25}.13^{22}.5^{16}.7^{16}}{9^{26}.13^{22}.5^{22}.7^{17}.4^{17}.5^9.5^9}\)

\(=\frac{2^{35}.5^3}{9.4^{17}.5^2.7}\)

\(=\frac{2^{35}.5}{9.4^{17}.7}\)

\(=\frac{2^{35}.5}{9.2^{34}.7}\)

\(=\frac{2.5}{9.7}\)

\(=\frac{10}{63}\)

p/s: - Ko chắc ~

\(\frac{21}{11}\cdot\frac{68}{63}\cdot\frac{22}{17}\)

\(=1\cdot\frac{4}{3}\cdot2\)

\(=\frac{8}{3}\)

\(\left(\frac{27}{25}-\frac{4}{9}\right)-\left(\frac{2}{25}+\frac{5}{9}\right)\)

\(=\frac{27}{25}-\frac{4}{9}-\frac{2}{25}-\frac{5}{9}\)

\(=\left(\frac{27}{25}-\frac{2}{25}\right)-\left(\frac{4}{9}+\frac{5}{9}\right)\)

\(=1-1\)

\(=0\)

\(A=\dfrac{2^{35}.45^{25}.13^{22}.35^{16}}{9^{26}.65^{22}.28^{17}.25^9}=\dfrac{2^{35}.3^{50}.5^{25}.13^{22}.5^{16}.7^{16}}{3^{52}.13^{22}.5^{22}.2^{34}.7^{17}.5^{18}}\)

\(=\dfrac{2.5^3}{3^2.5^2.7}=\dfrac{2.5}{3^2.7}=\dfrac{10}{63}\)

 \(\frac{21}{11}\times\frac{22}{17}\times\frac{68}{63}\)

=\(\frac{21}{1}\times\frac{2}{17}\times\frac{68}{63}\)

= 21 x \(\frac{8}{63}\)

=\(\frac{8}{3}\)

\(-\dfrac{3}{16}+-\dfrac{3}{8}-\dfrac{5}{4}\)

\(=-\dfrac{3}{16}-\dfrac{3}{8}-\dfrac{5}{4}\)

\(=-\dfrac{3}{16}-\dfrac{6}{16}-\dfrac{20}{16}\)

\(=\dfrac{-3-6-20}{16}\)

\(=-\dfrac{29}{16}\)

\(\left(-\dfrac{25}{13}\right)+\dfrac{-9}{17}+\dfrac{12}{13}+\dfrac{25}{17}\)

\(=\left[\left(-\dfrac{25}{13}\right)+\dfrac{12}{13}\right]+\left[\left(-\dfrac{9}{17}+\dfrac{25}{17}\right)\right]\)

\(=-\dfrac{13}{13}+\dfrac{17}{17}\)

\(=-1+1\)

\(=0\)

giúp với

\(\frac{2^{35}.9^{25}.5^{25}.13^{22}.7^{16}.5^{16}}{9^{26}.13^{22}5.^{22}.7^{17}.4^{17}.5^{2.9}}=2^{\left(35-2.17\right)}.9^{\left(25-26\right)}.5^{\left(25+16\right)-\left(22+2.9\right)}.13^{22-22}.7^{16-17}.\)

\(2^1.9^{-1}.5^1.13^0.7^{-1}=\frac{2.5}{9.7}=\frac{10}{63}\)

Ban co the giai giup mk dc ko ?

\(\frac{2^{23}\cdot45^{25}\cdot13^{22}\cdot35^{16}}{9^{26}\cdot65^{22}\cdot28^{17}\cdot25^9}=\frac{2^{23}\cdot5^{25}\cdot3^{50}\cdot13^{22}\cdot5^{16}\cdot7^{16}}{3^{52}\cdot5^{22}\cdot13^{22}\cdot7^{17}\cdot2^{54}\cdot5^{18}}=\frac{2^{23}\cdot3^{50}\cdot5^{31}\cdot7^{16}\cdot13^{22}}{2^{54}\cdot3^{52}\cdot5^{22}\cdot7^{17}\cdot13^{22}}=\frac{5^9}{2^{31}\cdot3^2\cdot7}\)
 

a/=\(\dfrac{-17}{25}\).(\(\dfrac{20}{33}+\dfrac{13}{3}\))+\(\dfrac{-3}{25}\)

=\(\dfrac{-17}{25}\).\(\dfrac{163}{33}\)+\(\dfrac{-3}{25}\)

=\(\dfrac{-2771}{825}\)+\(\dfrac{-3}{25}\)

=\(\dfrac{-574}{165}\)

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