36³

<img src=https://hoc24.vn/images/avt/avt30201979_256by256.jpg><img src=https://hoc24.vn/images/avt/avt30201979_256by256.jpg>

Cần kq à hay lũy thừa

mì đi ngủ 

mì chịu

mì buồn ngủ lắm

học 3 ca xong mệt rồi

bye 

lúc nào mì trả lời cho

Máy tính, dùng nó là đc

Tối rồi đi ngủ đi, mai mì trả lời cho

khùng hả giờ mới có 9 giờ 50

5^x.15625=625
56^x=625:15625
56^x=0,04
x=-2
b)-13/35

\(25\cdot5^3\cdot\dfrac{1}{625}\cdot5^3=5^8\cdot\dfrac{1}{5^4}=5^4\)

3^ x . 3^ 2= 729

3^ x  . 9        = 729

3^ x               = 729: 9

3^x                 =81 

vậy    x            = 3^3

5^ x . 625 = 3125

5^x           = 3125:625

5^x            =   5

vậy x          = 1

( 2x+1 )^ 3 = 27

( 2x+1) ^ 3 = 3^3

vậy 2x+1 =  3

  vậy x = 0         

\(\left(\frac{3}{5}\right)^x.\left(\frac{625}{81}\right)^3=\frac{243}{3125}\)

=>\(\left(\frac{3}{5}\right)^x.\left(\frac{5}{3}\right)^{12}=\left(\frac{3}{5}\right)^5\)

=>\(\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^5:\left(\frac{5}{3}\right)^{12}\)

=>\(\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^{17}\)

=>x=17

\(\left(\frac{3}{5}\right)^x.\left(\frac{625}{81}\right)^3=\frac{243}{3125}\)

\(\Rightarrow\left(\frac{3}{5}\right)^x.\left(\frac{3}{5}\right)^{12}=\left(\frac{3}{5}\right)^5\)

\(\Rightarrow\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^5:\left(\frac{3}{5}\right)^{12}\)

\(\Rightarrow\left(\frac{3}{5}\right)^x=\left(\frac{5}{3}\right)^7\)

\(\Rightarrow x=-7\)

`a, = 5^3 xx 3^3 = 15^3`

`b, = 12^3 xx 4^3 = 48^3`

`c, = 625^3 xx 8^3 = 5000^3`

`d, = 625 ^3 xx 125^3 = 78125^3`

`e, = 5^20 : 5^14 = 5^6`

1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)

2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)

3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)

4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)

5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)

\(\left(\frac{3}{7}\right)^5.\left(\frac{7}{3}\right)^{-1}.\left(\frac{5}{6}\right)^6.\left(\frac{343}{625}\right)^{-2}\)

\(=\left(\frac{3}{7}\right)^5.\left(\frac{3}{7}\right).\left(\frac{5}{2.3}\right)^6.\left(\frac{5^4}{7^3}\right)^2\)

\(=\frac{3^5}{7^5}.\frac{3}{7}.\frac{5^6}{2^6.3^6}.\frac{5^8}{7^6}=\frac{1}{2^6}.\frac{3^6}{3^6}.\frac{5^{14}}{1}.\frac{1}{7^{12}}=\frac{5^{14}}{2^6.7^{12}}\)

Nó đâu có phải là số nguyên đâu

3/7 x 5/6 +5/6 x3/7

= (3/7x5/6) + (5/6x3/7)

= 15/42 + 15/42  = 30/42 = 5/7