Tim x:

a,-16+23+x=-16

x=-16+16+23

x=23

b,(x-1)-(-2)=0

x-1+2=0

x+1=0

x=-1

c,|x-1|=0

x-1=0

x=1

d,|9-x|=64+(-7)

\(|9-x|=57\)

\(\orbr{\begin{cases}9-x=57\\9-x=-57\end{cases}}\)

\(\orbr{\begin{cases}x=-48\\x=66\end{cases}}\)

a,-16+23+x=-16

23+x=0

x=-32

b,(x-1)-(-2)=0

(x-1)+2=0

x-1=-2

x=-1

`x xx 12=456 xx 16`

`x xx 12=7296`

`x=7296:12`

`x=608`

`-------`

`x : (23xx6)=9`

`x :138=9`

`x=9 xx 138`

`x=1242`

a)

`X xx 12 = 456 xx 16`

` X xx 12 = 7296`

`X = 7296:12`

`X=608`

b)

`x:(23xx6)=9`

`x:138=9`

`x=9xx138`

`x=1242`

a) x = 190            

b) x = 344           

c) x = 4                

d) x = 20

( 123 . 456 - 23 . 16 ) . ( 12 . 9 - 4 . 27)

= ( 56088 - 368) . ( 108 - 108 )

= 55720 . 0

= 0

( 123 x 456 - 23 x 16 ) x ( 12 x 9 -4 x 27 )

=( 123 x 456 - 23 x 16 ) x (108 -108)

=( 123 x 456 - 23 x 16 ) x 0=0

Ban co the giai giup mk dc ko ?

\(\frac{2^{23}\cdot45^{25}\cdot13^{22}\cdot35^{16}}{9^{26}\cdot65^{22}\cdot28^{17}\cdot25^9}=\frac{2^{23}\cdot5^{25}\cdot3^{50}\cdot13^{22}\cdot5^{16}\cdot7^{16}}{3^{52}\cdot5^{22}\cdot13^{22}\cdot7^{17}\cdot2^{54}\cdot5^{18}}=\frac{2^{23}\cdot3^{50}\cdot5^{31}\cdot7^{16}\cdot13^{22}}{2^{54}\cdot3^{52}\cdot5^{22}\cdot7^{17}\cdot13^{22}}=\frac{5^9}{2^{31}\cdot3^2\cdot7}\)
 

Bài 2:

a. $=58(75+50-25)=58.100=5800$
b. $=27.8+4.9-5=216+36-5=247$

Bài 3:

a. 

$(x-38):16=12$

$x-38=16\times 12=192$
$x=192+38 = 230$
b.

$10+2x=4^5:4^3=4^2=16$

$2x=16-10=6$

$x=6:2=3$
c.

$440+2(125-x)=546$

$2(125-x)=546-440=106$

$125-x=106:2=53$

$x=125-53=72$

d.

$(x-15):5+20=22$
$(x-15):5=22-20=2$

$x-15=2\times 5=10$

$x=10+15=25$

e.

$2x-138=2^3.3^2=8.9=72$

$2x=72+138 = 210$

$x=210:2=105$

BAI 1 ; 

Bài 2: 

a, \(\dfrac{5}{23}\) \(\times\) \(\dfrac{17}{26}\) + \(\dfrac{5}{23}\) \(\times\) \(\dfrac{9}{26}\) 

= \(\dfrac{5}{23}\) \(\times\) ( \(\dfrac{17}{26}\) + \(\dfrac{9}{26}\))

= \(\dfrac{5}{23}\) \(\times\) \(\dfrac{26}{26}\)

= \(\dfrac{5}{23}\) 

b, \(\dfrac{3}{4}\) \(\times\) \(\dfrac{7}{9}\) + \(\dfrac{7}{4}\)  \(\times\) \(\dfrac{3}{9}\)

= \(\dfrac{7}{12}\) + \(\dfrac{7}{12}\)

= \(\dfrac{14}{12}\)

= \(\dfrac{7}{6}\)

Lời giải:

a.

$23+x=15$

$x=15-23=-8$

b.

$x-18=-23$

$x=-23+18=-5$

c.

$x+(-4)=16$

$x=16-(-4)=16+4=20$

d.

$25-x=-16$

$x=25-(-16)=25+16=41$

e.

$(-35)x=-210$

$x=(-210):(-35)=6$
f.

$(-2)(15-x)=60$

$15-x=60:(-2)=-30$
$x=15-(-30)=15+30=45$