a) 136 x 68 + 16 x 272 =  136 x 68 + 16 x 2 x 136  =  136 x 68 + 32 x 136 = 136 x ( 68 + 32 ) = 136 x 100 = 13600

b) 8 x 9 x14 + 6 x 17 x 12 + 19 x 4 x18 = 2 x 4 x9 x 14 + 6 x 17 x 4 x 3 + 19 x 4 x 18

= 56 x 18 + 18 x 68 + 76 x 18 = 18 x ( 56 + 68 + 76 ) = 18 x 200 = 3600

mù mắt

là sao bạn NGUYỄN HỮU CHUNG 

để 2a76b chia hết cho 10 thì b = 0

Nếu b =0 thì 2a76b =2a760 

để 2a760 chia hết cho 9 thì [ 2 + a + 7 + 6 + 0 ] chia hết cho 9

                                             [ 15 + a ] chia hết cho 9 

                                        => a = 3 

Vậy : a = 3 và b = 0

a, ta có :

123/456 < 123/789 < 456/789

Từ đó suy ra 123/456< 456/789

k nha

Dấu này * là dấu nhân

Một năm rồi không có ai trả lời à 

a) = 1/10 - 1/11 + 1/11 -1/12 + 1/12 - 1/13 +1/13 1/14 +...+ 1/78 - 1/79

= 1/10 - 1/79

= máy tính ok

mấy câu khác bn làm tương tự là đc nhưng nhớ nhanh thêm khoảng cách giữa các mẫu nha

a)\(\frac{1}{10.11}+\frac{1}{11.12}+...+\frac{1}{78.79}=\frac{1}{10}-\frac{1}{11}+\frac{1}{11}-\frac{1}{12}+...+\frac{1}{78}-\frac{1}{79}=\frac{1}{10}-\frac{1}{79}=\frac{69}{790}\)

b) \(\frac{8}{7.9}+\frac{8}{9.11}+...+\frac{8}{133.135}=4\left(\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{133.135}\right)\)

\(=4\left(\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{133}-\frac{1}{135}\right)=4\left(\frac{1}{7}-\frac{1}{135}\right)=4.\frac{128}{945}=\frac{456}{945}\)

c) \(\frac{12}{8.11}+\frac{12}{11.14}+...+\frac{12}{503.506}=4\left(\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{503.506}\right)\)

\(=4\left(\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{503}-\frac{1}{506}\right)=4\left(\frac{1}{8}-\frac{1}{506}\right)=\frac{249}{506}\)

d) \(\frac{1}{4.7}+\frac{1}{7.10}+...+\frac{1}{391.394}=\frac{1}{3}\left(\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{391.394}\right)\)

\(=\frac{1}{3}\left(\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+...+\frac{1}{391}-\frac{1}{394}\right)=\frac{1}{3}.\left(\frac{1}{4}-\frac{1}{394}\right)=\frac{1}{3}.\frac{195}{788}=\frac{65}{788}\)

e) \(\frac{4}{5.8}+\frac{4}{8.11}+...+\frac{4}{602.605}=\frac{4}{3}.\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{602.605}\right)\)

\(=\frac{4}{3}\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{602}-\frac{1}{605}\right)=\frac{4}{3}\left(\frac{1}{5}-\frac{1}{605}\right)=\frac{4}{3}.\frac{24}{121}=\frac{32}{121}\)

g) Sửa đề\(1+\frac{1}{3}+\frac{1}{6}+...+\frac{1}{820}=2\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{1640}\right)=2\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{40.41}\right)\)

\(=2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{40}-\frac{1}{41}\right)=2\left(1-\frac{1}{41}\right)=2.\frac{40}{41}=\frac{80}{41}\)

1) \(\left(+15\right)+\left(+17\right)=15+17=32\)

2) \(\left(-3\right)+\left(-7\right)=-3-7=-\left(3+7\right)=-10\)

3) \(\left(-25\right)+\left(+4\right)=-25+4=-\left(25-4\right)=-21\)

4) \(\left(-6\right)+\left(-54\right)=-6-54=-\left(6+54\right)=-60\)

5) \(\left(-15\right)+20=20-15=5\)

6) \(\left(-5\right)+8+7+5\)

\(=\left(-5+5\right)+\left(8+7\right)\)

\(=15\)

7) \(\left(-8\right)+\left(-11\right)+\left(-2\right)\)

\(=\left[\left(-8\right)+\left(-2\right)\right]+\left(-11\right)\)

\(=\left(-10\right)+\left(-11\right)\)

\(=-21\)

8) \(15+\left(-5\right)+\left(-14\right)+\left(-16\right)\)

\(=\left[15+\left(-5\right)\right]+\left[\left(-14\right)+\left(-16\right)\right]\)

\(=10+\left(-30\right)\)

\(=-20\)

9) \(\left(-20\right)+\left(-14\right)+3+\left(-86\right)\)

\(=\left[\left(-20\right)+3\right]+\left[\left(-14\right)+\left(-86\right)\right]\)

\(=\left(-17\right)+\left(-100\right)\)

\(=-117\)

10) \(\left(-136\right)+123+\left(-264\right)+\left(-83\right)+240\)

\(=\left[\left(-136\right)+\left(-264\right)\right]+\left[123+\left(-83\right)\right]+240\)

\(=\left(-400\right)+40+240\)

\(=\left(-360\right)+240\)

\(=-120\)

11) \(\left(-596\right)+2001+1999+\left(-404+189\right)\)

\(=\left(-596\right)+2001+1999-404+189\)

\(=\left[\left(-596\right)-404\right]+\left(2001+189\right)+1999\)

\(=\left(-1000\right)+2190+1999\)

\(=1190+1999\)

\(=3189\)

12) \(314+\left(-153\right)+64+121+\left(-247\right)+218\)

\(=\left(314+64+121\right)+\left[\left(-153\right)+\left(-247\right)\right]+218\)

\(=\left(378+121\right)+\left(-400\right)+218\)

\(=499-400+218\)

\(=99+218\)

\(=317\)

\(\text{#}Toru\)

A = 3.136.8 + 4.14.6 - 14.150

A = 3 x (136 x 8 + 4 x 14 x 2 - 14 x 50)

A = 3 x (1088 + 112 - 700)

A = 3 x 500

A = 1500

tính nhanh

A = 3. 136. 8 + 4. 14. 6 - 14. 150

A = 24 . 136 + 24 . 14 - 14 . 150 

A = 24 ( 136 + 14 ) - 14 . 150

A = 24 . 150 - 14 . 150

A = 150 ( 24 - 14 )

A = 150 . 10

A = 1500 

104 x (14 + 6 )

= 104 x 20

= 2080

67 x 136 + 33 x 136

= ( 67 + 33 ) x 136 

= 100 x 136 

= 13600

51 x 115 - 115 x 41

= ( 51 - 41 ) x 115

= 10 x 115

= 1150 

104 x ( 14+6 ) 

= 104 x 20  

= 104 x 10 x 2

1040 x 2 =2080 k nha mình đang âm

a) \(A=\frac{135}{135.136-1}\)             và                    \(B=\frac{136}{136.137-1}\)

   \(A=\frac{1}{136-1}=\frac{1}{135}\)                             \(B=\frac{1}{137-1}=\frac{1}{136}\)

Vì \(\frac{1}{136}\)< \(\frac{1}{135}\)nên A > B.

a, A = \(\frac{136-1}{\left(136-1\right)136-1}\) = \(\frac{136-1}{136^2-136-1}\)                 B=\(\frac{136}{136\left(136+1\right)-1}\)=\(\frac{136}{136^2+136-1}\)

x=136,  A-B =\(\frac{x-1}{x^2-x-1}\)-\(\frac{x}{x^2+x-1}\) =\(\frac{x^3+x^2-x-x^2-x+1-x^3+x^2+x}{\left(x^2-1\right)^2-x^2}\)=\(\frac{x^2-x+2}{\left(x^2-1\right)^2-x^2}\)<0

=> A<B

b,A = \(\frac{456-333}{456}\)= 1-333/456       B=\(\frac{789-333}{789}\)= 1-333/789

=> A>B

c, 3/14<3/13<3/12<3/11<3/10 <2/5

M = 3/10+3/11+3/12+3/13+3/14 < 2/5 x5 = 2= N