a) \(\left(x-\dfrac{1}{2}\right)^2=0\)

\(\Rightarrow x-\dfrac{1}{2}=0\)

\(\Rightarrow x=\dfrac{1}{2}\)

b) \(\left(x-2\right)^2=1\)

\(\Rightarrow x-2=1\)

\(\Rightarrow x=3\)

c) \(\left(2x-1\right)^3=-8\)

\(\Rightarrow\left(2x-1\right)^3=\left(-2\right)^3\)

\(\Rightarrow2x-1=-2\)

\(\Rightarrow2x=-1\)

\(\Rightarrow x=\dfrac{-1}{2}\)

d) \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\)

\(\Rightarrow\left(x+\dfrac{1}{2}\right)^2=\left(\dfrac{1}{4}\right)^2\)

\(\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{4}\\x+\dfrac{1}{2}=-\dfrac{1}{4}\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{-1}{4}\\x=\dfrac{-3}{4}\end{matrix}\right.\).

a , \(\left(x-\dfrac{1}{2}\right)^2=0\)

<=> \(x-\dfrac{1}{2}=0\Rightarrow x=\dfrac{1}{2}\)

b , \(\left(x-2\right)^2=1\Rightarrow\left[{}\begin{matrix}x-2=1\\x-2=-1\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=1\end{matrix}\right.\)

c , \(\left(2x-1\right)^3=-8\Rightarrow2x-1=-2\Rightarrow x=\dfrac{-1}{2}\)

d , \(\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{16}\Leftrightarrow\left(x+\dfrac{1}{2}\right)^2=\dfrac{1}{4^2}\)

<=> \(\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{1}{4}\\x+\dfrac{1}{2}=\dfrac{-1}{4}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{-1}{4}\\x=\dfrac{-3}{4}\end{matrix}\right.\)

cái này là tìm x phải ko bn

a)27³-72x=0

-72x=27³

^=>x=27³/-72

x=-273,375

b)=>(x+2)²=6.(x+2)

(x+2)²/(x+2)=6

(x+2)=6

vậy x =6-2=4

1. 4x/6y=(2x+8)/(3y+11) <=> 12xy+44x=12xy+48y

<=> 44x=48y =>x/y=12/11

mình chỉ biết câu 1 thôi :v

Ai giúp mik với!

a)(x+1)+(x+2)+...+(x+30)=795

(x+x+...+x)+(1+2+3+...+30)=795

30x+465=795

30x=795-465

30x=330

x=330/30

x=11

b)(x+1)+(x+3)+...+(x+99)=5100

(x+x+...+x)+(1+3+...+99)=5100

50x+2500=5100

50x=5100-2500

50x=2600

x=2600/50

x=52

a, 17-(2+x)=3

=> x+2= 14

=> x=12

b, (6+x)+(17-21)= -25

6+x- 4= -25

=> x+2=-25

=> x= -27

c, nhận xét / x-1/>=0

=> x-1= 3

=> x=4

A ) 17-(2+x)=3

=> x+2= 14

=> x=12

B ) (6+x)+(17-21)= -25

6+x- 4= -25

=> x+2=-25

=> x= -27

C ) Có nhận xét / x-1/>=0

=> x-1= 3

=> x=4

đ/s : ...

a) (3^x-15)^7=0

  =) 3x-15=0

   =) 3x=15

=) x=5

b) 4^2.x-6=1

 4^2.x-6= 4^0 ( vì số nào mũ không cũng bằng 1)

2x-6=0

2x=6

x=3

a, 1.5 x ( 2 - x ) = 3.15 - 1.35

                          = 1.80

=> 1.5 x 2 - 1.5 x X =1.80

=> 1.5 x X = 3 - 1.80

                  = 2.2

=> x = 2.2 : 1.5 = 1.46

Tìm X 

A ) 3,15 - 1,5 x ( 2 - X ) = 1,35

                1,5 x ( 2 - X ) = 3,15 - 1,35

                1,5 x ( 2 - X ) = 1.8

                        ( 2 - X ) = 1,8 : 1,5

                          2 - X  = 1,2

                               X  = 0,8

Study well 

Ta có

\(a+b=ab\)

=>\(\frac{a+b}{ab}=1\)

<=>\(\frac{1}{a}+\frac{1}{b}=1\)