ta có :

 \(45^{10}\times\frac{5^{10}}{75^{10}}=\left(45\times\frac{5}{75}\right)^{10}=3^{10}\)

=(45.5)^10/75^10

=(225/75)^10

=3^10

=59049

\(\frac{45^{10}\cdot5^{10}}{75^{10}}=\frac{3^{10}\cdot15^{10}\cdot5^{10}}{75^{10}}=\frac{3^{10}\cdot3^{10}\cdot5^{10}\cdot5^{10}}{3^{10}\cdot25^{10}}=\frac{3^{10}\cdot3^{10}\cdot5^{10}\cdot5^{10}}{3^{10}\cdot5^{10}\cdot5^{10}}=\frac{3^{20}\cdot5^{20}}{3^{10}\cdot5^{20}}=3^{10}\)

từ đề bài ta có

\(\frac{45^5\cdot5^{10}}{75^5}=\frac{\left(15\cdot3\right)^5\cdot5^{10}}{\left(15\cdot5\right)^5}=\frac{15^5\cdot3^5\cdot5^{10}}{15^5\cdot5^5}=\frac{3^5\cdot5^5}{1}=15^5=759375\)

\(A=\dfrac{45^{10}.5^{10}}{75^{10}}=\dfrac{5^{10}.9^{10}.5^{10}}{25^{10}.3^{10}}=\dfrac{5^{20}.3^{20}}{3^{10}.5^{20}}=3^{10}=59049\)

\(\frac{45^{10}.5^{10}}{75^{40}}=\frac{\left(5.3^2\right)^{10}.5^{10}}{\left(5^2.3\right)^{40}}=\frac{5^{10}.3^{20}.5^{10}}{5^{80}.3^{40}}=\frac{1}{5^{60}.3^{20}}\)

Ý của bạn là\(\frac{45^{10}.5^{20}}{75^{10}}\)

bạn viết rõ ra được không

Vào câu tương tự vẫn mình giải thôi

Kết quả :

59049

Đặt \(S=\frac{45^{10}\cdot5^{10}}{75^{15}}=\frac{\left(3^2\cdot5\right)^{10}\cdot5^{10}}{\left(3\cdot5^2\right)^{15}}\)

\(=\frac{3^{20}\cdot5^{10}\cdot5^{10}}{3^{15}\cdot5^{30}}=\frac{3^{15}\cdot3^5\cdot5^{10}\cdot5^{10}}{3^{15}\cdot5^{20}\cdot5^{10}}=\frac{3^5\cdot5^{10}}{5^{20}}=3^5\cdot5^{-10}=3^5\cdot\frac{1}{9765625}\)

Đến đây bạn tính nhé , đề cho sai phải không vậy?

Trả lời:

\(\frac{45^{10}.5^{10}}{75^{15}}=\frac{\left(3.15\right)^{10}.5^{10}}{75^{15}}\)

                   \(=\frac{3^{10}.15^{10}.5^{10}}{75^{15}}\)

                   \(=\frac{3^{10}.\left(15.5\right)^{10}}{75^{15}}\)

                   \(=\frac{3^{10}.75^{10}}{75^{15}}\)

                   \(=\frac{3^{10}}{75^5}\)

                   \(=\frac{3^{10}}{\left(3.25\right)^5}\)

                   \(=\frac{3^{10}}{3^5.25^5}\)

                   \(=\frac{3^5}{25^5}=\frac{243}{9765625}\)

a: =25(15+45*3)

=25*150

=3750

b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)

c: =>3^x-2=27

=>x-2=3

=>x=5

d: =>2x-5=-4

=>2x=1

=>x=1/2

e: =>2(x-1)^2=32

=>(x-1)^2=16

=>x-1=4 hoặc x-1=-4

=>x=-3 hoặc x=5

f:  =>25(x+3)=75

=>x+3=3

=>x=0

\(=\dfrac{\left(3^2\cdot5\right)^{10}\cdot5^{20}}{\left(3\cdot5^2\right)^{15}}=\dfrac{3^{20}\cdot5^{10}\cdot5^{20}}{3^{15}\cdot5^{30}}=3^5=243\)