1-3 -1000+3300-10000x300000
mik ko biết đáp ắn :|
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38.x-x.12-x.16=40
<=> x(38-12-16)=40
<=> x.10=40
<=>x =4
Chọn đáp ắn đúng nhất (giúp mik giải thích cả 10 câu nha mn)
1. I think most children are creative enough to write .......... poems.
A. beautiful B. beautifully C. beauty D. beautify
2. It is necessary ............ forests.
A. protect B. protected C. to protect D. protecting
3. They made their living by .......... fish in the ocean every day.
A. catch B. to catch C. catching D. caught
4. I suggest.............. to the movies.
A. go B. going C. to go D. went
5. I have sent you a lot of letters but you have never been.....................
A. respond B. response C. responsive D. responsively
6. The cost of ............ is very high in big cities.
A. life B. live C. living D. lived
7. The next stage in the development of television is ...............TV.
A. interact B. interaction C. interactive D. interactively
8. By learning English, you can get access to the world’s...............
A. develop B development C. developed D. developing
9. Hurry up, or you won’t...................... the last bus.
A. miss B. take C. catch D. go
10. Let’s wait..............the rain stops.
A. before B. after C. until D. whe
\(\left|2x-3\right|=3-2x\)
\(ĐK:x\le\dfrac{3}{2}\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3-2x\\3-2x=3-2x\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{2}\\0=0\left(đúng\right)\end{matrix}\right.\)
Vậy \(S=\left\{x\in R;x=\dfrac{3}{2}\right\}\)
678*99+678
=678*99+678*1
=678*(99+1)
=678*100
=67800
33+34-230=số âm tiểu học chưa học
Tổng có 50 số hạng
Ta có:
(x + 1) + (x + 2) +...+ (x + 50) = 1475
(x + x +...+ x) + (1 + 2 +...+ 50) = 1475 (Tổng 1 có 50 số x)
50x + 1275 = 1475
=> 50x = 200
=> x = 4
(x+1)+(x+2)+(x+3)+....+(x+50)=1475
x50+ 1275 =1475
x50 =1475-1275
x50 =200
x =200:50
x =4
60 - [45 + (2 . 7 + 1)]
=60 - [45 + (14 + 1)]
=60 - [45 + 15]
= 60 - 60
= 0
\(B=3^1+3^2+3^3+...+3^{300}\\=(3^1+3^2)+(3^3+3^4)+(3^5+3^6)+...+(3^{299}+3^{300})\\=3\cdot(1+3)+3^3\cdot(1+3)+3^5\cdot(1+3)+...+3^{299}\cdot(1+3)\\=3\cdot4+3^3\cdot4+3^5\cdot4+...+3^{299}\cdot4\\=4\cdot(3+3^3+3^5+...+3^{299})\)
Vì \(4\cdot(3+3^3+3^5+...+3^{299})\vdots2\)
nên \(B\vdots2\)
B=(3+32)+(33+34)+...+(3299+3300)
B=3(1+3)+33(1+3)+...+3299(1+3)
B=3.4+33.4+...+3299.4
B=4(3+33+...+3299) chia hết cho 2 vì 4 chia hết cho 2
vậy B chia hết cho 2
1 - 3 - 1000 + 3300 - 10000 x 300000
= (-2) + (3300 - 1000) - 3000000000
= (-2) + 2300 - 3000000000
= 2298 - 3000000000
= 2999997702
-999997702 ắ