ai giải hộ mình mình k liền

eo ơi đưa về lũy thừa của các số nguyên tố là xong      

\(\frac{27^2.15^3.125^{17}.10^{10}.3^8.512+1024.25^{28}.12^6.15^7}{125.6^{17}+625^{12}.6^{13}.125^2.25^5.16}\)

=\(\frac{3^6.3^3.5^3.5^{34}.2^{10}.5^{10}.3^8.2^9+2^{10}.5^{56}.3^6.2^{12}.3^7.5^7}{5^{63}.6^{17}+5^{48}.6^{13}.5^6.2^4}\)=\(\frac{3^{17}.5^{47}.2^{19}+2^{22}.5^{63}.3^{13}}{5^{63}.6^{17}+5^{48}.6^{13}.5^6.2^4}=\frac{3^{13}.5^{47}.2^{19}.3^4+2^{19}.5^{47}.3^{13}.2^3.5^{16}}{5^{54}.6^{13}.5^9+5^{54}.6^{13}.2^4}\)

=\(\frac{3^{13}.5^{47}.2^{19}\left(3^4+2^3.5^{16}\right)}{5^{54}.6^{13}\left(5^9+2^4\right)}=\frac{6^{13}.2^6.5^{47}\left(3^4+2^3.5^{16}\right)}{5^7.5^{47}.6^{13}\left(5^9+2^4\right)}=\frac{2^6\left(3^4+2^3.5^{16}\right)}{5^7\left(5^9+2^4\right)}\)

Bạn hãy tự giải nốt

`(6^10:6^8):{780:[87.5-(125+5.7^2)+13.5]}`

`=6^2:[780:(435-49.5-125+65)]`

`=36:[780:(435-245-125+65)]`

`=36:(780:130)`

`=36:6`

`=6`

Anh làm sai rồi :v

Nhìn bài em thử đi..

\(=\dfrac{10+5+100+125}{216+3+36+27}\cdot\dfrac{7}{125}=\dfrac{240}{282}\cdot\dfrac{7}{125}=\dfrac{56}{1175}\)

\(\begin{array}{l}a){\left( {\frac{2}{3}} \right)^{10}}{.3^{10}} = \frac{{{2^{10}}}}{{{3^{10}}}}{.3^{10}} = {2^{10}}\\b){( - 125)^3}:{25^3} = {( - 125:25)^3} = {( - 5)^3} =  - 125\\c){(0,08)^3}{.10^6} = {(0,08)^3}{.100^3} = {(0,08.100)^3} = {8^3}\end{array}\)

1) \(125^5:25^7\)

\(=\left(5^3\right)^5:\left(5^2\right)^7\)

\(=5^{15}:5^{14}\)

= 5

2) \(27^8:9^9\)

\(=\left(3^3\right)^8:\left(3^2\right)^9\)

\(=3^{24}:3^{18}\)

\(=3^6\)

3) \(36^5:6^8\)

\(=\left(6^2\right)^5:6^8\)

\(=6^{10}:6^8\)

\(=6^2\)

4) \(49^6:7^{10}\)

\(=\left(7^2\right)^6:7^{10}\)

\(=7^{12}:7^{10}=7^2\)

5) \(7^{20}:49^9\)

\(=7^{20}:\left(7^2\right)^9\)

\(=7^{20}:7^{18}=7^2\)

6) \(\frac{1}{2^{10}}:\frac{1}{8^3}\)

\(=\frac{1}{2^{10}}:\frac{1}{\left(2^3\right)^3}\)

\(=\frac{1}{2^{10}}:\frac{1}{2^9}=\frac{1}{2^{10}}.\frac{2^9}{1}=\frac{1}{2}\)

7) \(\left(-\frac{1}{2}\right)^{21}:\frac{1}{4^{10}}\)

\(=\frac{\left(-1\right)^{21}}{2^{21}}:\frac{1}{\left(2^2\right)^{10}}\)

\(=-\frac{1}{2^{21}}:\frac{1}{2^{20}}=-\frac{1}{2^{21}}.\frac{2^{20}}{1}\)

\(=-\frac{1}{2}\)

8) \(\frac{1}{16^5}:\left(-\frac{1}{2}\right)^{18}\)

\(=\frac{1}{\left(2^4\right)^5}:\frac{\left(-1\right)^{18}}{2^{18}}\)

\(=\frac{1}{2^{20}}:\frac{1}{2^{18}}\)

\(=\frac{1}{2^{20}}.\frac{2^{18}}{1}=\frac{1}{4}\)

9) \(\frac{1}{5^{30}}:\frac{1}{25^{14}}\)

\(=\frac{1}{5^{30}}:\frac{1}{\left(5^2\right)^{14}}\)

\(=\frac{1}{5^{30}}:\frac{1}{5^{28}}=\frac{1}{25}\)

nhiều lúc bực vs olm 
đăng bài mà có dòng thông báo : câu hỏi của bạn đang đc duyệt
 đợi olm duyệt xong em cũng đéo cần nữa

ai như mk thì cùng tố cáo ad nha

125.64-10.25.6.4

=125.8.8-10.6.25.4

=(125.8).8-(10.6).(25.4)

=1000.8-60.100

=8000-6000

=2000

2^(10 : 64 x 16) = 2^[(10 x 16) : 64] = 2^(160 : 64) = 2^25

2^(10 x 8) = 2^80     3^(5 : 27) = 3^(5/27)     5^(2 x 125) = 5^250     6^(6 : 36) = 6^(1/6)

                                                 Giải

a) (125-5):5+1=25  

     ( 125+5)x25:2=1625

             Đ/S=1625

b)(307-7):10+1=31

(307+7)x31:2=4867

          ĐS: 4867

c)3+(91-1)x2=183

(183-3):3+1=61

(183+3)x61:2=5673

        ĐS 5673

d)  6+(70-1)x2=150

   (150-6):4+1=37

(150+6)x37:2=2886

        Đs:2886

a)     \(\left(125-5\right):5+1=25\)

b)      \(\left(307-7\right):10+1=31\)

c)       Ko có kết quả

d)      \(\left(70-6\right):4+1=17\)