Tính :
\(200+6+\frac{3}{100}\) \(27+\frac{4}{10}+\frac{6}{100}\)
Điền dấu > < =
\(3\frac{2}{5}.........3,25\) \(4\frac{1}{20}...........4,2\) \(21,09.......21\frac{1}{10}\) \(8\frac{7}{20}........8,35\)
( Lưu ý đổi trước khi làm bài tập điền dấu > < = )
Giúp mình nha
\(200+6+\frac{3}{100}\) \(27+\frac{4}{10}+\frac{6}{100}\)
= \(206+\frac{3}{100}\) = \(\frac{2700}{100}+\frac{40}{100}+\frac{6}{100}\)
= \(\frac{20600}{100}+\frac{3}{100}\) = \(\frac{2746}{100}\)
= \(\frac{20603}{100}\)
\(3\frac{2}{5}=3,4>3,25\) \(4\frac{1}{20}=4,05< 4,2\)
\(21,09< 21\frac{1}{10}=21,1\) \(8\frac{7}{20}=8,35\)
\(200+6+\frac{3}{100}=\frac{20603}{100}=206,03=206+\frac{3}{100}\)
\(27+\frac{4}{10}+\frac{6}{100}=27+\frac{23}{50}\)
Bài 2
\(3\frac{2}{5}=\frac{17}{5}=3,\: \: 4\: \: \) \(3,25=\frac{13}{4}\)
\(\Rightarrow3\frac{2}{5}>3,25\)
b)
\(4\frac{1}{20}< 4,2\)
c)
\(8\frac{7}{20}=8,35\)