tìm a biết
[246/369 + 1616/2121] = 5/21 nhân a
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242/363 + 1616/ 2121= 5/7 x y
\(\frac{2}{3}+\frac{16}{21}=\frac{5}{7}\)x y
\(\frac{14}{21}\)+\(\frac{16}{21}\)= \(\frac{5}{7}\)x y
\(\frac{10}{7}\)=\(\frac{5}{7}\)x y
\(\frac{10}{7}\): \(\frac{5}{7}\)=y
\(\frac{10}{7}\)x \(\frac{7}{5}\)=y
2=y
vậy y=2
\(\frac{242}{363}+\frac{1616}{2121}=\frac{5}{7}\times y\)
\(\frac{121\times2}{121\times3}+\frac{101\times16}{101\times21}=\frac{5}{7}\times y\)
\(\frac{2}{3}+\frac{16}{21}=\frac{5}{7}\times y\)
\(\frac{10}{7}=\frac{5}{7}\times y\)
\(\Rightarrow y=\frac{10}{7}:\frac{5}{7}\)
\(y=2\)
\(\frac{242}{363}+\frac{1616}{2121}=\frac{2}{7}.\frac{2015}{A}\)
\(\frac{11.11.2}{11.11.3}+\frac{101.16}{101.21}=\frac{2}{7}.\frac{2015}{A}\)
\(\frac{2}{3}+\frac{16}{21}=\frac{2}{7}.\frac{2015}{A}\)
\(\Rightarrow\frac{2}{7}.\frac{2015}{A}=\frac{10}{7}\)
\(\frac{2015}{A}=\frac{10}{7}:\frac{2}{7}\)
\(\frac{2015}{A}=5\)
\(A=2015:5\)
\(A=403\)
\(\left(\frac{242}{363}+\frac{1616}{2121}\right)=\frac{2}{7}.\frac{2015}{A}\)
\(\Leftrightarrow\left(\frac{2}{3}+\frac{16}{21}\right)=\frac{2}{7}.\frac{2015}{A}\)
\(\Leftrightarrow\frac{10}{7}=\frac{2}{7}.\frac{2015}{A}\)
\(\Leftrightarrow5=\frac{2015}{A}\)
\(\Leftrightarrow A=403\)
\(\dfrac{242}{363}+\dfrac{1616}{2121}=\dfrac{2}{7}y\)
\(\dfrac{2\cdot121}{3\cdot121}+\dfrac{16\cdot101}{21\cdot101}=\dfrac{2}{7}y\)
\(\dfrac{2}{7}y=\dfrac{2}{3}+\dfrac{16}{21}\)
\(\dfrac{2}{7}y=\dfrac{10}{7}\)
\(y=\dfrac{10}{7}\div\dfrac{2}{7}=5\)
242/363 + 1616/2121 = 2/7 x a
10/7 = 2/7 x a
a = 10/7 : 2/7
a = 5
=> 10/7 = 2/7 . x
=> 2/7 . x = 10/7
=> x = 10/7 : 2/7
=> x = 5