-1

-1

a: =>3/2x=64/15

=>x=128/45

b: =>-1/6x=7/12

=>x=-7/2

c: =>11/2*x=1/2

=>x=1/2:11/2=1/11

Bài 1:

0,5\(x\) - \(\dfrac{2}{3}\)\(x\) = \(\dfrac{7}{12}\)  

\(\dfrac{1}{2}\)\(x\) - \(\dfrac{2}{3}x\)  = \(\dfrac{7}{12}\)

(\(\dfrac{1}{2}-\dfrac{2}{3}\))\(x\) = \(\dfrac{7}{12}\)

- \(\dfrac{1}{6}\)\(x\)         = \(\dfrac{7}{12}\)

     \(x\)         = \(\dfrac{7}{12}\) : (- \(\dfrac{1}{6}\))

     \(x\)        = - \(\dfrac{7}{2}\)

Vậy \(x\) = - \(\dfrac{7}{2}\)

bn đừng nói ai xin lỗi với mình nữa nhé ! trả lời nick mình rồi mình sẽ nói cho

\(\frac{-2}{5}x+\frac{1}{5}=\frac{3}{10}\)

\(\Leftrightarrow\frac{-2}{5}x=\frac{3}{10}-\frac{1}{5}=\frac{1}{10}\)

\(\Leftrightarrow x=\frac{1}{10}:\frac{-2}{5}=\frac{1}{10}.\frac{5}{-2}=\frac{1}{-4}\)

Vậy: x=1/-4

\(0,5x-\frac{2}{3}=\frac{7}{12}\)

\(\Leftrightarrow\frac{1}{2}x=\frac{7}{12}+\frac{2}{3}\)

\(\Leftrightarrow\frac{1}{2}x=\frac{15}{12}=\frac{5}{4}\)

\(\Leftrightarrow x=\frac{5}{4}:\frac{1}{2}=\frac{5}{4}.2=\frac{5}{2}\)

Vậy x=5/2

a: =>1/2x-2/3x=7/12

=>-1/6x=7/12

hay x=-7/2

b: \(\Leftrightarrow x=-\dfrac{5}{2}\cdot\dfrac{13}{3}=\dfrac{-65}{6}\)

c: =>x=13/15:11/2=26/165

d: =>3/7x+1=1/7

=>3/7x=-6/7

hay x=-2