b-1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256

gọi A=1/2+1/4+1/8+...+1/1024

2xA=1+1/2+1/4+.....+1/512

2xA-A=(1+1/2+1/4+....+1/512)-(1/2+1/4+1/8+...+1/1024)

A=1-1/1024

=1023/1024

vậy A=1023/1024

\(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+...+\frac{1}{512}-\frac{1}{1024}=1-\frac{1}{1024}=\frac{1023}{1024}\)

đặt  biểu thức là A ta có :

 A = 1/2 + 1/4  + 1/8 + 1/16 +1/32 +1/64 +1/128 + 1/256 + 1/512 + 1/102

A x 2 = 1+ 1/2 + 1/4 + 1/8 + 1/16 +1 /32+1/64 + 1/ 128 + 1/256 + 1/512 

A = ( 1 + 1/2 +1/4 + 1/ 8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 ) - ( 1/2 + 1/4 + 1/8 +1/16 +1/32 + 1/64 + 1/128 +1/256 +1/512 +1/1024)

A = 1 - 1/1024 

A = 1023/1024

nhớ k nhé

(1 / 2) + (1 / 4) + (1 / 8) + (1 / 16) + (1 / 32) + (1 / 64) + (1 / 128) + (1 / 256) + (1 / 512) + (1 / 1024) =

0.9990234375

đề phải là 1 +1/2 + 1/4 +1/32 + 1/64 + 1/128 +1/256 +/512 +1/1024 moi dug 

bằng 0,9990234375

1023/1024

 A = 1/2 + 1/4 + 1/8 + ... + 1/1024

2A = 1 + 1/2 + 1/4 + ... + 1/512

2A - A = (1 + 1/2 + 1/4 + ... + 1/512) - (1/2 + 1/4 + 1/8 + ... + 1/1024)

A = 1 - 1/1024

A = 1023/1024

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+....+\frac{1}{1024}\)

\(\Rightarrow2A=1+\frac{1}{2}+\frac{1}{4}+......+\frac{1}{512}\)

\(\Rightarrow A=2A-A=1-\frac{1}{1024}\)

\(A=\frac{1023}{1024}\)

2A=1+1/2+1/4+1/8+.........+1/512

2A-A=(1+1/2+1/4+1/8+....+1/512)-(1/2+1/4+1/8+.....+1/1024)

A=1-1/1024

A=1023/1024

vậy A=1023/1024

A = (1/2+1/64)+(1/4+1/128)+(1/8+1/256)+(1/16+1/512)+(1/32+1/1024)
= 1/2(1+1/32)+1/4(1+1/32)+1/8(1+1/32)+1/16(1+1/32)+1/32(1+1/32)
= (1+1/32) x (1/2+/14+1/8+1/16+1/32)
= (33/32) x (31/32) = 1023/1024

Cả lời giải bn

Mình nghĩ đây là nâng cao tiểu học 
Đặt S = 1/2 + 1/4 + 1/8 + 1/16 + ... 
==> 2S = 1 + 1/2 + 1/4 + 1/8 + 1/16 + ... 
2S = 1 + S 
==> S = 1 
Đây cũng là kết quả khi tính theo cấp số nhân khi n --> vô cùng

2A=1+1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512

2A-A=1-1/1024

A=1-1/1024

A=1023/1024