Bài 6: 

a: \(2^{27}=8^9\)

\(3^{18}=9^9\)

b: Vì \(8^9< 9^9\)

nên \(2^{27}< 3^{18}\)

cảm ơn nha

a: \(=10^{-1}\)

b: \(=10^{-2}\)

\(\left(0,09\right)^3=\left(\dfrac{9}{100}\right)^3=\left[\left(\dfrac{3}{10}\right)^2\right]^3=\left(\dfrac{3}{10}\right)^6\\ \left(\dfrac{3}{10}\right)^8=\left(\dfrac{3}{10}\right)^8\\ \left(0,027\right)^2=\left(\dfrac{27}{1000}\right)^2=\left[\left(\dfrac{3}{10}\right)^3\right]^2=\left(\dfrac{3}{10}\right)^6\)

a) \(2^{225}=2^{3.75}=\left(2^3\right)^{75}=8^{75}\)

\(3^{150}=3^{2.75}=\left(3^2\right)^{75}=9^{75}\)

Vì \(8^{75}\)\(< \)\(9^{75}\)  nên \(2^{225}< 3^{150}\)

b) \(2^{12}=16^3\)

\(4^{18}=16^9\)

K mk nha mk nhanh nhất 100% đấy

a)Ta có:  2²²⁵ = (2³)⁷⁵          và           3¹⁵⁰ = (3²)⁷⁵

Do 2³ < 3²  => (2³)⁷⁵ <  (3³)⁷⁵  => 2²²⁵ < 3¹⁵⁰

b) 2¹² = (2⁴)³ = 16³

   4¹⁸ = (4²)⁹ = 16⁹

Ta có: +) \({({2^2})^3} = {2^2}{.2^2}{.2^2} = {2^{2 + 2 + 2}} = {2^6}\)

+) \({\left[ {{{( - 3)}^2}} \right]^2} = {( - 3)^2}.{( - 3)^2} = {( - 3)^{2 + 2}} = {( - 3)^4}\)

Ta có:

\(\begin{array}{l}{\left( {\frac{1}{4}} \right)^8} = {[{\left( {\frac{1}{2}} \right)^2}]^8} = {(\frac{1}{2})^{2.8}} = {(\frac{1}{2})^{16}};\\{\left( {\frac{1}{8}} \right)^3} = {[{(\frac{1}{2})^3}]^3} = {(\frac{1}{2})^{3.3}} = {(\frac{1}{2})^9}\end{array}\)

\(4^{18}=\left(2^2\right)^{18}=2^{36}=\left(2^3\right)^{12}=8^{12}\)

\(2^{12}=2^{3.4}=\left(2^3\right)^4=8^4\)

Ta có : 2^12 = (2^4)^3 = 16^3

4^18 = ( 4^2 )^9 = 16^9 

a) 0,09⁷

0,027³=(0,09³)³=0,09⁹

=> 0,09⁷ và 0,09⁹ cùng cơ số là 0,09