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\(\dfrac{x\sqrt{x}+1}{x-1}-\dfrac{x-1}{\sqrt{x}+1}\\ =\dfrac{x\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\dfrac{x-1}{\sqrt{x}+1}\\ =\dfrac{x\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\dfrac{\left(x-1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}+1\right)\left(\sqrt{x}-1\right)}\\ =\dfrac{x\sqrt{x}+1-\left(x\sqrt{x}-x-\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ =\dfrac{x\sqrt{x}+1-x\sqrt{x}+x+\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ =\dfrac{x+\sqrt{x}}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ =\dfrac{\sqrt{x}\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\\)
\(=\dfrac{\sqrt{x}}{\sqrt{x}-1}\)
Đăng đúng môn nhe cậu
Bạn không nêu rõ yêu cầu đề bài.
Nếu là rút gọn thì:
\(\sqrt{2+\sqrt{2}}+\frac{1}{\sqrt{18}}-\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{24}}=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{\sqrt{36}}-\frac{\sqrt{6}(\sqrt{2}-1)}{\sqrt{6}.\sqrt{4}}\)
\(=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{6}-\frac{\sqrt{2}-1}{2}=\sqrt{2+\sqrt{2}}+\frac{\sqrt{2}}{6}-\frac{3\sqrt{2}-3}{6}\)
\(=\sqrt{2+\sqrt{2}}+\frac{3-2\sqrt{2}}{6}\)
\(FeCO_3+2HCl\rightarrow FeCl_2+CO_2+H_2O\)
\(FeCl_2+2NaOH\rightarrow Fe\left(OH\right)_2+NaCl\)
\(2FeCl_2+Cl_2\rightarrow2FeCl_3\)
\(4Fe\left(OH\right)_2+2H_2O+O_2\rightarrow4Fe\left(OH\right)_3\)
\(CO_2+Ba\left(OH\right)_2\rightarrow Ba\left(HCO_3\right)_2\)
\(Ba\left(HCO_3\right)_2+NaOH\rightarrow BaCO_3+Na_2CO_3+H_2O\)
\(BaCO_3+2HCl\rightarrow CO_2+BaCl_2+H_2O\)
\(2FeCl_3+3Na_2CO_3+H_2O\rightarrow6NaCl+Fe_2\left(CO_3\right)_3\)
X1: nước
X2: NaHSO4
X3: Ba(HCO3)2
X4: BaCO3
X5: AgNO3
X6: KOH
X7: Ca(OH)2
X8: CaHPO4
X9: Fe
X10: H2SO4
X11: Ag
X12: Ba(OH)2
X14: Cu(NO3)2
X15: Cu
PT tự viết nha
1)xFe2O3+(3x-y)H2->FexOy+(3x-y)H2O
2) 2NaHSO4+Ba(HCO3)2->Na2SO4+BaSO4+2CO2+2H2O
3) 2NaHSO4+BaCO3->Na2SO4+BaSO4+CO2+H2O
4) 2AgNO3+2KOH->Ag2O+2KNO3+H2O
5) Ca(OH)2+CaHPO4->Ca(H2PO4)2