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Nhận xét: 1/1x2x3 - 1/2x3x4 = 3/1x2x3x4, 1/2x3x4 - 1/3x4x5 =3/2x3x4x5,...,1/27x28x29 - 1/28x29x30
Gọi biểu thức phải tính bằng A,ta tính được:
3A=1/2x3 - 1/28x29x30 = 4059/28x29x30
vậy A = 1353/8120
Bài 1:
a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)
b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)
c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)
d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)
hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)
e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)
hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)
6A=5.7.6+7.9.6+9.11.6+11.13.6+13.15.6+...+99.101.6
6A=5.7.(9-3)+7.9.(11-5)+9.11.(13-7)+11.13.(15-9)+13.15.(17-11)+...+99.101.(103-97)
6A=-3.5.7+5.7.9-5.7.9+7.9.11-7.9.11+9.11.13-9.11.13+11.13.15-11.13.15+13.15.17-...-97.99.101+99.101.103
6A=99.101.103-3.5.7 => A=(99.101.103-3.5.7)/6
\(-\frac{7}{11}.\frac{11}{19}+\frac{-7}{11}.\frac{8}{19}+\frac{-4}{11}=-\frac{7}{11}.\left(\frac{11}{19}+\frac{8}{19}\right)-\frac{4}{11}\)
\(=-\frac{7}{11}.1-\frac{4}{11}=-\frac{7}{11}-\frac{4}{11}\)
\(=-\frac{11}{11}=-1\)
9/11 x 10/13 + 9/13 x 12/11 - 7/11
= 9/13 x 10/11 + 9/13 x 12/11 - 7/11
= 9/13 x (10/11 + 12/11) - 7/11
= 9/13 x 22/11 - 7/11
= 9/13 x 2 - 7/11
= 18/13 - 7/11
= 198/143 - 91/143
= 107/143
\(\dfrac{9}{11}\times\dfrac{10}{13}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\dfrac{10}{11}+\dfrac{9}{13}\times\dfrac{12}{11}-\dfrac{7}{11}=\dfrac{9}{13}\times\left(\dfrac{10}{11}+\dfrac{12}{11}\right)-\dfrac{7}{11}=\dfrac{9}{13}\times2-\dfrac{7}{11}=\dfrac{18}{13}-\dfrac{7}{11}=\dfrac{107}{143}\)
11x19=209
11.19=209