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\(\dfrac{11}{3}-\dfrac{2}{3}\left(2\dfrac{2}{5}x\dfrac{1}{4}+0,2\right)\)
\(\Leftrightarrow3\left(\dfrac{12}{5}\times\dfrac{1}{4}+0,2\right)\)
\(\Leftrightarrow3\left(\dfrac{3}{5}+\dfrac{1}{5}\right)\)
\(\Leftrightarrow3\times\dfrac{4}{5}\)
\(\Leftrightarrow\dfrac{12}{5}\)
a)\(\frac{4}{5}-\frac{1}{4}+\frac{3}{10}\)
\(=\frac{16}{20}-\frac{5}{20}+\frac{6}{20}\)
\(=\frac{17}{20}\)
b) \(\frac{2}{5}:\left(1-\frac{1}{10}\right)\)
\(=\frac{2}{5}:\frac{9}{10}\)
\(=\frac{4}{9}\)
c)\(\frac{7}{8}\times\frac{4}{9}+\frac{1}{14}:\frac{5}{14}\)
\(=\frac{7}{18}+\frac{1}{5}\)
\(=\frac{53}{90}\)
d)\(\frac{2}{7}\times\frac{3}{11}+\frac{2}{7}\times\frac{8}{11}\)
\(=\frac{2}{7}\times\left(\frac{3}{11}+\frac{8}{11}\right)\)
\(=\frac{2}{7}\times1=\frac{2}{7}\)
e) \(12+\left(16-11\right)\times4\)
\(=12+20=32\)
f)\(2\frac{3}{7}+1\frac{4}{7}\)
\(=\frac{17}{7}+\frac{11}{7}\)
\(=4\)
g)\(\frac{2}{3}\times\frac{4}{5}+\frac{1}{5}:\frac{9}{11}\)
\(=\frac{8}{15}+\frac{11}{45}\)
\(=\frac{7}{9}\)
h)\(\left(6,2:2+3,7\right):0,2\)
\(=\left(3,1+3,7\right):0,2\)
\(=6,8:0,2=34\)
#H
\(x-\dfrac{11}{15}=3+\dfrac{x}{5}\\ \Leftrightarrow\dfrac{4}{5}x=\dfrac{56}{15}\\ \Leftrightarrow x=\dfrac{14}{3}\)
\(\dfrac{2}{5}\times\dfrac{1}{x}+\dfrac{1}{x}\times2+\dfrac{2}{5}=\dfrac{1}{2}\\ \Leftrightarrow\dfrac{12}{5}\times\dfrac{1}{x}=\dfrac{1}{10}\\ \Leftrightarrow\dfrac{1}{x}=\dfrac{1}{24}\\ \Leftrightarrow x=24\)
a) \(\frac{51}{3}-\frac{22}{3}=\frac{51-22}{3}=\frac{29}{3}\)
b) \(\frac{5}{12}+\frac{5}{6}-\frac{3}{4}=\frac{5}{12}+\frac{10}{12}-\frac{9}{12}=\frac{5+10-9}{12}=\frac{6}{12}=\frac{1}{2}\)
c) \(1-\left(\frac{1}{5}+\frac{1}{2}\right)=\frac{10}{10}-\frac{2}{10}-\frac{5}{10}=\frac{10-5-2}{10}=\frac{3}{10}\)
d) \(\frac{111}{4}-\left(\frac{25}{7}+\frac{51}{4}\right)=\frac{777}{28}-\frac{60}{28}-\frac{357}{28}=\frac{360}{28}=\frac{90}{7}\)
e) \(\left(\frac{85}{11}+\frac{35}{7}\right)-\frac{35}{11}=\left(\frac{85}{11}-\frac{35}{11}\right)+\frac{35}{7}=\frac{50}{11}-\frac{35}{7}=\frac{350}{77}-\frac{385}{77}=-\frac{35}{77}\)
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20
=(20+1)+(2+19)+...+(10+11) có 10 cặp số
=21+21+..+21 Có 10 số hạng
=21 x 10
=210
\(\frac{7}{3}\)+ \(\frac{11}{2}\)- \(\frac{1}{5}\)= \(\frac{70}{30}\)+ \(\frac{165}{30}\)- \(\frac{6}{30}\)
= \(\frac{235}{30}\)- \(\frac{6}{30}\)
= \(\frac{229}{30}\)
\(\frac{11}{4}\)x \(\frac{2}{33}\)- \(\frac{1}{40}\)= \(\frac{22}{132}\)- \(\frac{1}{40}\)
= \(\frac{17}{120}\)
\(\frac{22}{7}:\left(11-x\right)+\frac{2}{3}=\frac{7}{5}\)
\(\frac{22}{7}:\left(11-x\right)=\frac{11}{15}\)
\(11-x=\frac{30}{7}\)
\(x=\frac{47}{7}\)
Vậy \(x=\frac{47}{7}\)
\(\frac{22}{7}\div\left(11-x\right)+\frac{2}{3}=\frac{7}{5}\)
\(\Leftrightarrow\frac{2}{7}-\frac{22}{7x}+\frac{2}{3}=\frac{7}{5}\)
\(\Rightarrow\frac{30x}{105x}+\frac{330}{105x}+\frac{70x}{105x}=\frac{147}{105x}\)
\(\Rightarrow100x+330=147\)
\(\Rightarrow100x=-153\)
\(\Rightarrow x=-1,53\)
\(\dfrac{11}{3}-\dfrac{2}{3}\times\left(2\dfrac{2}{5}+\dfrac{1}{4}+0,2\right)\)
\(=\dfrac{9}{3}\times\left(\dfrac{12}{5}+\dfrac{1}{4}+\dfrac{1}{5}\right)\)
\(=3\times\left(\dfrac{13}{5}+\dfrac{1}{4}\right)\)
\(=3\times\dfrac{57}{20}\)
\(=\dfrac{171}{20}\)