a)67.153-53.67+712:8

=67.(153-53)+89

=67.100+89

=6789

\(a,67\times153-53\times67+712:8\)

\(=67\times\left(153-53\right)+\left(712:8\right)\)

\(=67\times100+89\)

\(=6700+89\)

\(=6789\)

\(b,168-\left\{5\times\left[143-\left(15-12\right)^2\right]+10\right\}:10\)

\(=168-\left\{5\times\left[143-3^2\right]+10\right\}:10\)

\(=168-\left\{5\times134+10\right\}:10\)

\(=168-\left\{670+10\right\}:10\)

\(=168-680:10\)

\(=168-68\)

\(=100\)

\(c,\left(-13\right)+84+\left(-87\right)+16\)

\(=13+84-87+16\)

\(=\left(13+87\right)-\left(84+16\right)\)

\(=100-100\)

\(=0\)

\(d,9-\left(12-15\right)\)

\(=9-\left(-3\right)\)

\(=12\)

\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)

\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)

a,(-67.77) - (-67.44) - 77.44+77.67

= (-67).(77-44)-77.(44+67)

= (-67-77).(77-44+44+67)

=-144.144

=-20736

b,[-36:(-12)]-12.8+6³-1

=3-12.8+216-1

=3-96+216-1

=122

a) \(\left(-16\right).1253.\left(-8\right).\left(-4\right).\left(-3\right)\)

\(=16.1253.8.4.3>0\)

b) \(13.\left(-24\right).\left(-15\right).\left(-8\right).4< 0\) 

Phương pháp : ta nhóm 2 số âm với nhau rồi nhân vào thì làm mất dấu \("-"\)                       

1

(-57).(67-34)-67.(34-57)

=-57.67+57.34-67.34+67.57

=(-57.67+67.57)+57.34-67.34

=0+34(57-67)

=34.(-10)

=-340

2

a)(-16).(-8).(-4).(-3)>0 ; 1253>0 => (-16).1253.(-8).(-4).(-3)>0

b)13.4>0 ; (-24).(-15).(-8)<0=>13.(-24).(-15).(-8).4<0

\(a\)\(3^{39}\)và \(11^{21}\)

\(3^{39}< 11^{21}\)vì

\(3^{39}< 3^{40}=3^{39}< \left(3^2\right)^{20}=9^{20}< 11^{21}\)

\(\Rightarrow3^{39}< 11^{29}\)

CÂU A 

MIK LÀM ĐÚNG KO

MÍ BẠN

a, 3³⁹ < 3⁴⁰ = (3²)²⁰=9²⁰<11²¹

b, chép đúng đề bài ko pn

c, 13⁴⁰< 16⁴⁰= (2⁴)⁴⁰= 2¹⁶⁰<2¹⁶²

a/ 234 - 117 + (-100) + (-234) = 234 + (-234) - 117 + (-100) = -217

b/ -927 + 1421 + 939 + (-1421) = 1421 + (-1421) - 927 + 939 = 12

c/ 11 - 12 + 13 - 14 + 15 -16 + 17 - 18 + 19 - 20

   = (-1) + (-1) + (-1) + (-1) + (-1) = -5

d/ 101 - 102 - (-103) - 104 - (-105) - 106 - (-107) - 108 - (-109) -110

  = (101 - 102) - [( -103) + 104] - [ (-105) + 106] - [(-107) + 108]  - [(-109) + 110]

  = (-1) - 1 - 1 - 1 - 1 = -5

a) 234 - 117 + (-100) + (-234) = [234 + (-234)] - [117 + (-100)] = 0 + 17 = 17.

b) (-927) + 1421 + 930 + (-1421) = [(-927) + 927)] + (1421 + 930) = 0 + 2351 = 2351.

c) 11 - 12 + 13 - 14 + 15 - 16 + 17 -18 + 19 - 20 = (11 - 20) + (12 - 19) + (13 - 18) + (14 - 17) + (15 - 16)

= (-9) + (-7) + (-5) + (-3) + (-1) = -25.

d) 101 - 102 - (-103) - 104 - (-105) - 106 - (-107) - 108 - (-109) - 110

= (-101) + (-102) + 103 + (-104) + 105 + (-106) + 107 + (-108) + 109 + (-110)

=               (-203) +                      (-205) +           (-204) +           (-203) + (-110)

= -925.

e) (-125) + 100 + 80 + 125 + 20 = [(-125) + 125] + 100 + (80 + 20) = 0 + 100 + 100 = 200.

a ) 1 2 . b ) − 2 5 . c ) − 7 8 . d ) 0. e ) 0.