chịu

ăn ba tô cơm

\((\frac{4}{3}-\frac{1}{4}-\frac{5}{12})\)+2x=\(\frac{8}{5}:\frac{3}{5}\)

=\(\frac{2}{3}\)+2x=\(\frac{8}{3}\)

2x=\(\frac{8}{3}-\frac{2}{3}\)

2x=2

x=2:2

x=1

Vậy x=1

\(\left(\frac{4}{3}-\frac{1}{4}-\frac{5}{12}\right)+2x=\frac{8}{5}:\frac{3}{5}\)

 \(\left(\frac{16}{12}-\frac{3}{12}-\frac{5}{12}\right)+2x=\frac{8}{5}.\frac{5}{3}\)

          \(\frac{2}{3}+2x=\frac{8}{3}\)

                     \(2x=\frac{8}{3}-\frac{2}{3}\) 

                      \(2x=2\)

                           \(x=2:2\)

                              \(x=1\)

                       Vậy \(x=1\)

Chúc bạn học thật tốt !!!

a)=<

b)=-1/6<1/12

=9 mũ 2021 

\(F=9^2+9^3+9^4+...+9^{2020}\)

\(\Rightarrow9F=9^3+9^4+9^5+...+9^{2021}\)

\(\Rightarrow9F-F=\left(9^3+9^4+9^5+...+9^{2021}\right)-\left(9^2+9^3+9^4+...+9^{2020}\right)\)

\(\Rightarrow8F=9^{2021}-9^2\)

\(\Rightarrow F=\frac{9^{2021}-9^2}{8}\)

\(4\left(x-1\right)-3\left(x-2\right)=-5\)

\(\Leftrightarrow4x-4-3x+6=-5\)

\(\Leftrightarrow x=-5+4-6\)

\(\Leftrightarrow x=-7\)

Vậy x=-7

Ta có: 4(x-1) - 3(x-2) = -5

          (4x-4) - (3x-6) = -5

          4x - 4 - 3x + 6 = -5 

     (4x - 3x) + (-4+6) = -5

                       x + 2  = -5

                             x  = -5 - 2

                              x = -7

                         Vậy x = -7

5-(4/7) hay là(5-4)/7 z bn

    (\(\dfrac{2}{3}\) - \(\dfrac{11}{7}\) + \(\dfrac{13}{5}\)) - (5 - \(\dfrac{4}{7}\) + \(\dfrac{6}{5}\)) - (\(\dfrac{11}{3}\) - \(\dfrac{3}{5}\))

=   \(\dfrac{2}{3}\) - \(\dfrac{11}{7}\) + \(\dfrac{13}{5}\) - 5 + \(\dfrac{4}{7}\) - \(\dfrac{6}{5}\) - \(\dfrac{11}{3}\) + \(\dfrac{3}{5}\)

=   (\(\dfrac{2}{3}\) - \(\dfrac{11}{3}\)) - (\(\dfrac{11}{7}\) - \(\dfrac{4}{7}\)) + (\(\dfrac{13}{5}\) - \(\dfrac{6}{5}\)+ \(\dfrac{3}{5}\)) 

= \(\dfrac{-9}{3}\) - \(\dfrac{7}{7}\) + (\(\dfrac{7}{5}\) + \(\dfrac{3}{5}\)) - 5

=  - 3 - 1 + 2 - 5

=  - (3 + 1)  - ( 5 - 2)

= - 4 - 3 

= - 7

Ảnh hơi mờ 

\(\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{3^{10}.\left(-5\right)^{20}.\left(-5\right)}{\left(-5\right)^{20}.3^{10}.3^2}=\frac{-5}{3^2}=-\frac{5}{9}\)