Dễ nhưng dài e nên tách ra

a) ƯCLN(12;18) = 6

b) ƯCLN(12;10)=2

c) ƯCLN(24;48)=24

d) ƯCLN(300;280)=20

e) ƯCLN(9;81)=9

f) ƯCLN(11;15)=1

g) ƯCLN(1;10)=1

h) ƯCLN(150;84)=6

a: \(42=2\cdot3\cdot7;70=2\cdot5\cdot7\)

=>\(BCNN\left(42;70\right)=2\cdot3\cdot5\cdot7=210\)

=>\(BC\left(42;70\right)=B\left(210\right)=\left\{0;210;420;...\right\}\)

b: \(70=2\cdot5\cdot7;180=3^2\cdot5\cdot2^2\)

=>\(BCNN\left(70;180\right)=2^2\cdot3^2\cdot5\cdot7=1260\)

=>\(BC\left(70;180\right)=\left\{1260;2520;...\right\}\)

c: \(5=5;7=7;8=2^3\)

=>\(BCNN\left(5;7;8\right)=5\cdot7\cdot8=280\)

=>\(BC\left(5;7;8\right)=\left\{280;560;...\right\}\)

d: \(12=2^2\cdot3;18=3^2\cdot2\)

=>\(BCNN\left(12;18\right)=2^2\cdot3^2=36\)

=>\(BC\left(12;18\right)=\left\{36;72;...\right\}\)

e: \(15=3\cdot5;18=3^2\cdot2\)

=>\(BCNN\left(15;18\right)=3^2\cdot2\cdot5=90\)

=>\(BC\left(15;18\right)=\left\{90;180;...\right\}\)

f: \(84=2^2\cdot3\cdot7;108=3^3\cdot2^2\)

=>\(BCNN\left(84;108\right)=2^2\cdot3^3\cdot7=756\)

=>\(BC\left(84;108\right)=\left\{756;1512;...\right\}\)

j: \(33=3\cdot11;44=2^2\cdot11;55=5\cdot11\)

=>\(BCNN\left(33;44;55\right)=3\cdot2^2\cdot5\cdot11=660\)

=>\(BC\left(33;44;55\right)=\left\{660;1320;...\right\}\)

g: \(1=1;12=2^2\cdot3;27=3^3\)

=>\(BCNN\left(1;12;27\right)=1\cdot2^2\cdot3^3=108\)

=>\(BC\left(1;12;27\right)=\left\{108;216;...\right\}\)

n: \(5=5;9=3^2;11=11\)

=>\(BCNN\left(5;9;11\right)=5\cdot3^2\cdot11=495\)

=>\(BC\left(5;9;11\right)=\left\{495;990;...\right\}\)

24 = 2³.3;  36 = 2⁴.3⁴; 60 = 2².3.5

ƯCLN( 24; 36; 60) = 2².3 = 12

12 = 2².3; 15 = 3.5; 10 = 2.5 

ƯCLN(12; 15; 10) = 1

24  = 2³.3; 16 = 2⁴; 8 = 2³

ƯCLN(24; 16; 8) = 2³

9 = 3²; 81 = 3⁴ 

ƯCLN( 9; 81) =  9

11 = 11; 15 = 3.5

ƯCLN( 11; 15) = 1

1 = 1; 10 = 2.5

ƯCLN(1; 10) = 1

150 = 2.3.5²;  84 = 2².3.7 

ƯCLN( 150; 84) = 6

Cha nội kia, trl tử tế vào:))

=0

\(a,ƯC\left(40,24\right)=Ư\left(8\right)=\left\{...\right\}\\ b,ƯC\left(12,52\right)=Ư\left(4\right)=\left\{...\right\}\\ c,ƯC\left(36,990\right)=Ư\left(18\right)=\left\{...\right\}\\ d,ƯC\left(54,36\right)=Ư\left(9\right)=\left\{...\right\}\\ e,ƯC\left(10,20,70\right)=Ư\left(10\right)=\left\{...\right\}\\ f,ƯC\left(25,55,75\right)=Ư\left(5\right)=\left\{...\right\}\\ g,ƯC\left(80,144\right)=Ư\left(16\right)=\left\{...\right\}\\ h,ƯC\left(63,2970\right)=Ư\left(9\right)=\left\{...\right\}\\ i,ƯC\left(65,125\right)=Ư\left(5\right)=\left\{...\right\}\\ j,ƯC\left(9,18,72\right)=Ư\left(9\right)=\left\{...\right\}\\ k,ƯC\left(24,36,60\right)=Ư\left(12\right)=\left\{...\right\}\\ l,ƯC\left(16,42,86\right)=Ư\left(2\right)=\left\{..\right\}\)

a:UC(40;24)=Ư(8)

b: UC(12;52)=Ư(4)

tui cần cả các bước giải nữa

a: 18=3^2*2; 42=2*3*7

=>ƯCLN(18;42)=3*2=6

b: 28=2^2*7

48=2^4*3

=>ƯCLN(28;48)=2^2=4

c: 24=2^3*3

36=2^2*3^2

60=2^2*3*5

=>ƯCLN(24;36;60)=12

d: 12=2^2*3

15=3*5

10=2*5

=>ƯCLN(12;15;10)=1

e: 24=2^3*3

16=2^4

8=2^3

=>ƯCLN(24;16;8)=2^3=8

h: 25=5^2; 55=5*11; 75=5^2*3

=>ƯCLN(25;55;75)=5

mn giúp mình đi

a: \(=11+\dfrac{3}{13}-2-\dfrac{4}{7}-5-\dfrac{3}{13}=4-\dfrac{4}{7}=\dfrac{24}{7}\)

b: \(=\dfrac{11}{2}\cdot\dfrac{15}{4}=\dfrac{165}{8}\)

c: \(=10+\dfrac{2}{9}+2+\dfrac{3}{5}-6-\dfrac{2}{9}=6+\dfrac{3}{5}=\dfrac{33}{5}\)

d: \(=6+\dfrac{4}{9}+3+\dfrac{7}{11}-4-\dfrac{4}{9}=5+\dfrac{7}{11}=\dfrac{62}{11}\)

bội chung nhỏ nhất của chúng là :

\(8\cdot9\cdot5\cdot7=2520\)

vậy bội chung của 1,2,3,4,5,6,7,8,9 là bội của 2520

a: \(12\dfrac{1}{3}-\left(3\dfrac{3}{4}+4\dfrac{3}{4}\right)\)

\(=\dfrac{37}{3}-3-4-\dfrac{3}{2}\)

\(=\dfrac{74-9}{6}-7=\dfrac{65}{6}-7=\dfrac{65-42}{7}=\dfrac{23}{7}\)

b: \(3\dfrac{5}{6}+2\dfrac{1}{6}\cdot6\)

\(=3+\dfrac{5}{6}+\dfrac{13}{6}\cdot6\)

\(=16+\dfrac{5}{6}=\dfrac{101}{6}\)

c: \(3\dfrac{1}{2}+4\dfrac{5}{7}-5\dfrac{5}{14}\)

\(=3+\dfrac{1}{2}+4+\dfrac{5}{7}-5-\dfrac{5}{14}\)

\(=2+\dfrac{7+10-5}{14}=2+\dfrac{12}{14}=2+\dfrac{6}{7}=\dfrac{20}{7}\)

d: \(=\dfrac{9}{2}+\dfrac{1}{2}:\dfrac{11}{2}=\dfrac{9}{2}+\dfrac{1}{11}=\dfrac{99+2}{22}=\dfrac{101}{22}\)

các bn giải mk nha