a: \(4^{10}\cdot2^{30}=2^{30}\cdot2^{20}=2^{50}\)

b: \(9^{25}\cdot27^4\cdot81^2=3^{50}\cdot3^{12}\cdot3^8=3^{70}\)

c: \(25^{50}\cdot125^5=5^{100}\cdot5^{15}=5^{115}\)

d: \(64^3\cdot4^8\cdot16^4=4^9\cdot4^8\cdot4^8=4^{25}\)

e: \(2^{10}:8^3=2^{10}:2^9=2\)

\(12^7:6^7=\left(\dfrac{12}{6}\right)^7=2^7\)

f: \(5^8:25^2=5^8:5^4=5^4\)

\(4^9:64^2=4^9:4^6=4^3\)

\(2^{25}:32^4=2^{25}:2^{20}=2^5\)

\(125^3:25^4=5^9:5^8=5\)

g: 2^5*8^4

=2^5*(2^3)^4

=2^5*2^12

=2^17

câu hỏi???

`5^12 .25^4 .125^3 .625^2=5^12 . (5^2)^4 . (5^3)^3 . (5^4)^2 =5^12 .5^8 .5^9 .5^8=5^37`

\(=3^7\times\left(3^3\right)^5\times\left(2^3\right)^{13}=3^7\times3^{15}\times2^{39}=3^{22}\times2^{39}\)

3^7.27^5.8^13= 37.275.813= 8272275

MIK SỬA LẠI ĐỀ CÂU B

a) \(27^5:81^3=\left(3^3\right)^5:\left(3^4\right)^3=3^{15}:3^{12}=3^3\)

b) \(3^9:81^3=3^9:\left(3^4\right)^3=3^9:3^{12}=3^{-3}\)

a) \(\left(3^3\right)^5:\left(3^4\right)^3\)

= \(3^{15}:3^{12}\)

= \(3^3\)

a) \(\left(-16\right).1253.\left(-8\right).\left(-4\right).\left(-3\right)\)

\(=16.1253.8.4.3>0\)

b) \(13.\left(-24\right).\left(-15\right).\left(-8\right).4< 0\) 

Phương pháp : ta nhóm 2 số âm với nhau rồi nhân vào thì làm mất dấu \("-"\)                       

1

(-57).(67-34)-67.(34-57)

=-57.67+57.34-67.34+67.57

=(-57.67+67.57)+57.34-67.34

=0+34(57-67)

=34.(-10)

=-340

2

a)(-16).(-8).(-4).(-3)>0 ; 1253>0 => (-16).1253.(-8).(-4).(-3)>0

b)13.4>0 ; (-24).(-15).(-8)<0=>13.(-24).(-15).(-8).4<0

a) \(9^3\cdot3^2\)

\(=\left(3^2\right)^3\cdot3^2\)

\(=3^6\cdot3^2\)

\(=3^8\)

b) \(x^7\cdot x:x^4\)

\(=x^8:x^4\)

\(=x^4\)

c) \(7\cdot3^9+3^{10}+51\cdot3^8\)

\(=3^8\cdot\left(7\cdot3+3^2+51\right)\)

\(=3^8\cdot81\)

\(=3^8\cdot3^4\)

\(=3^{12}\)

d) \(5^{15}\cdot125^3\cdot625\)

\(=5^{15}\cdot5^9\cdot5^4\)

\(=5^{28}\)

mấy bài này dễ mà bạn

dễ thì lm` jup đi

a: 13/67=91/469>91/470

b: 141/813=22419/129267

159/904=22419/127464

=>141/813<159/904

=127.33+33.127.2+127=127.(33+66+1)=127.100=12700

thanks

Chịu

Em mới lớp 4 hoi