Câu 1: 

\(\dfrac{2}{5}-\dfrac{1}{4}+\dfrac{3}{10}=\dfrac{8}{20}-\dfrac{5}{20}+\dfrac{6}{20}=\dfrac{8-5+6}{20}=\dfrac{9}{20}\) 

Câu 2:

\(\dfrac{-2}{5}:\left(1-\dfrac{1}{10}\right)=\dfrac{-2}{5}:\dfrac{9}{10}=\dfrac{-2}{5}.\dfrac{10}{9}=\dfrac{-2.10}{5.9}=\dfrac{-20}{45}=\dfrac{-4}{9}\) 

Câu 3:

\(\dfrac{7}{8}.\dfrac{4}{9}+\dfrac{1}{14}:\dfrac{5}{14}=\dfrac{7}{18}+\dfrac{1}{5}=\dfrac{53}{90}\) 

Câu 4:

\(\dfrac{2}{7}.\dfrac{3}{11}+\dfrac{2}{7}.\dfrac{8}{11}\) 

\(=\dfrac{2}{7}.\left(\dfrac{3}{11}+\dfrac{8}{11}\right)\) 

\(=\dfrac{2}{7}.1\) 

\(=\dfrac{2}{7}\)

Câu 1

\(\dfrac{2}{5}\)-\(\dfrac{1}{4}\)+\(\dfrac{3}{10}\)= \(\dfrac{8}{20}\)-\(\dfrac{5}{20}\)+\(\dfrac{6}{20}\)=\(\dfrac{3}{20}\)+\(\dfrac{6}{20}\)=\(\dfrac{9}{20}\)

Câu 2

-\(\dfrac{2}{5}\):(1-\(\dfrac{1}{10}\))= -\(\dfrac{2}{5}\):\(\dfrac{9}{10}\)=-\(\dfrac{2}{5}\).\(\dfrac{10}{9}\)=-\(\dfrac{4}{9}\)

Câu 3

\(\dfrac{7}{8}.\dfrac{4}{9}+\dfrac{1}{14}:\dfrac{5}{14}\)= \(\dfrac{7}{8}.\dfrac{4}{9}+\dfrac{1}{14}.\dfrac{14}{5}\)=\(\dfrac{7.4}{4.2.9}+\dfrac{1.14}{14.5}\)=\(\dfrac{7}{18}+\dfrac{1}{5}\)=\(\dfrac{35}{90}+\dfrac{18}{90}\)=\(\dfrac{53}{90}\)

Câu 4

\(\dfrac{2}{7}.\dfrac{3}{11}+\dfrac{2}{7}.\dfrac{8}{11}\)=\(\dfrac{2}{7}.\left(\dfrac{3}{11}+\dfrac{8}{11}\right)\)=\(\dfrac{2}{7}.1\)=\(\dfrac{2}{7}\)

\(-\frac{12}{35}\div\frac{7}{11}-\frac{23}{35}\div\frac{7}{11}-\frac{5}{11}\)

\(=\left(-\frac{12}{35}-\frac{23}{35}\right)\div\frac{7}{11}-\frac{5}{11}\)

\(=-1\div\frac{7}{11}-\frac{5}{11}\)

\(=-\frac{11}{7}-\frac{5}{11}\)

\(=-\frac{156}{77}\)

\(2-\frac{11}{9}\div\frac{5}{14}-\frac{7}{9}\times\frac{14}{5}\)

\(=2-\frac{154}{45}-\frac{98}{45}\)

\(=-\frac{64}{45}-\frac{98}{45}\)

\(=-\frac{18}{5}\)

c) 147x(14+7) và 14^3+7^3

147x(14+7)= 147x21=3087vaf 14^3 +7^3=2911+273=3184

suy  ra 147x(14+7)>14^3+7^3

9063/308

\(S=\frac{3}{1\cdot4}+\frac{3}{4\cdot7}+\frac{3}{7\cdot11}+\frac{3}{11\cdot14}+\frac{3}{14\cdot17}\)

\(S=\frac{4-1}{1\cdot4}+\frac{7-4}{4\cdot7}+\frac{11-7}{7\cdot11}+\frac{14-11}{11\cdot14}+\frac{17-14}{14\cdot17}\)

\(S=\frac{4}{1\cdot4}-\frac{1}{1\cdot4}+\frac{7}{7\cdot4}-\frac{4}{4\cdot7}+\frac{11}{7\cdot11}-\frac{7}{7\cdot11}+\frac{14}{11\cdot14}-\frac{11}{11\cdot14}+\frac{17}{14\cdot17}-\frac{14}{14\cdot17}\)

\(S=\frac{1}{1}-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}\)

\(S=\frac{1}{1}-\frac{1}{17}=\frac{17}{17}-\frac{1}{17}=\frac{16}{17}\)

a: =35/17-18/17-9/5+4/5

=1-1=0

b: =-7/19(3/17+8/11-1)

=7/19*18/187=126/3553

c: =26/15-11/15-17/3-6/13

=1-6/13-17/3

=7/13-17/3=-200/39

a: =8/20-5/20+6/20=9/20

b: =-2/5:9/10=-2/5*10/9=-20/45=-4/9

c: =7/8*4/9+1/14*14/5

=28/72+1/5

=53/90

d: =2/7(3/11+8/11)

=2/7

a, \(\dfrac{1}{3}+\dfrac{2}{3}:x=-7\)                          b, \(\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\)
            \(\dfrac{2}{3}:x=\left(-7\right)-\dfrac{1}{3}\)                      \(\dfrac{9}{2}-2x\)           \(=\dfrac{11}{14}:\dfrac{11}{7}\)
            \(\dfrac{2}{3}:x=-\dfrac{22}{3}\)                             \(\dfrac{9}{2}-2x\)            \(=\dfrac{1}{2}\)
                  \(x=\dfrac{2}{3}.\left(-\dfrac{22}{3}\right)\)                           \(2x\)            \(=\dfrac{9}{2}-\dfrac{1}{2}\)
                  \(x=-\dfrac{1}{11}\)                                      \(2x\)            \(=4\) 
                                                                         \(x\)            \(=4:2\)
                                                                         \(x\)            \(=2\)

\(a,\dfrac{1}{3}+\dfrac{2}{3}:x=-7\\ \Rightarrow\dfrac{2}{3}:x=\dfrac{-22}{3}\\ \Rightarrow x=\dfrac{-1}{11}\\ b,\left(\dfrac{9}{2}-2x\right).\dfrac{11}{7}=\dfrac{11}{14}\\ \Rightarrow\dfrac{9}{2}-2x=\dfrac{1}{2}\\ \Rightarrow2x=4\\ \Rightarrow x=2\)