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Số các số hạng là: ( 29 - 1 ) : 2 + 1 = 15 ( số )
Tổng dãy số trên là: ( 29 + 1 ) x 15 : 2 = 225
Đáp số : ...
Số các số hạng là:
\(\frac{29-1}{2}+1=15\)(số)
Tổng trên là:
\(\frac{\left(29+1\right)x15}{2}=225\)
Bài 2. > , < , = ?
5/7 < 4/3 2/5 < 6/10 1/4 = 3/12 27/36 >
2/9 7/6 > 7/9
7/2 = 2/7 15/23 < 1 27/9 > 2 14/15 < 1 51/17 < 4
Ta có:
\(A=\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{13.15}\)
\(A=\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{13}-\frac{1}{15}\)
\(A=\frac{1}{3}-\frac{1}{15}=\frac{4}{15}\)
\(B=2.\left(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{9.10}\right)\)
\(B=2.\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(B=2.\left(\frac{1}{1}-\frac{1}{10}\right)=2.\frac{9}{10}\)
\(B=\frac{9}{5}\)
a)\(\frac{-3}{5}+\frac{1}{4}+\frac{-3}{10}\)
\(=\frac{-12}{20}+\frac{5}{20}+\frac{-6}{20}\)
\(=\frac{-13}{20}\)
b)\(\frac{1}{5}+\frac{-9}{10}+\frac{-7}{25}=\frac{10}{50}+\frac{-45}{50}+\frac{-14}{50}=\frac{-49}{50}\)
c)\(\frac{1}{5}+\frac{-1}{6}+\frac{1}{7}+\frac{-1}{8}+\frac{1}{9}+\frac{1}{8}+\frac{-1}{7}+\frac{1}{6}+\frac{-1}{5}\)
=\(\left(\frac{1}{5}+\frac{-1}{5}\right)+\left(\frac{-1}{6}+\frac{1}{6}\right)+\left(\frac{1}{7}+\frac{-1}{7}\right)+\left(\frac{1}{8}+\frac{-1}{8}\right)+\frac{1}{9}\)
=\(0+0+0+0+\frac{1}{9}\)
=\(\frac{1}{9}\)
a)\(\frac{4}{3.7}+\frac{4}{7.11}+...+\frac{4}{23.27}=\frac{1}{3}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{23}-\frac{1}{27}=\frac{1}{3}-\frac{1}{27}=\frac{8}{27}\)
b)\(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{6.7}=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{6}-\frac{1}{7}=\frac{1}{2}-\frac{1}{7}=\frac{5}{14}\)
c)\(\frac{2}{3.5}+\frac{2}{5.7}+...+\frac{2}{11.13}+\frac{2}{1.2}+\frac{2}{2.3}+...+\frac{2}{9.10}=\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{11}-\frac{1}{13}\right)+2\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\right)\)
\(=\frac{1}{3}-\frac{1}{13}+2\left(1-\frac{1}{10}\right)=\frac{10}{39}+\frac{9}{5}=\frac{401}{195}\)
\(\dfrac{5}{6}\) + \(\dfrac{7}{8}\)
= \(\dfrac{5\times4}{6\times4}\) + \(\dfrac{7\times3}{8\times3}\)
= \(\dfrac{20}{24}\) + \(\dfrac{21}{24}\)
= \(\dfrac{41}{24}\)
5/6 + 7/8 = 41/24
2 + 2/3 = 8/3
7/9 - 1/7 = 40/63
1-1/11 =10/11
2x17/81 = 34/81
9/11 : 5/6 = 54/55
3: 12/25 = 25/4
Tick cho mik nhé.
Chúc bạn học tốt nha !
`@` `\text {Ans}`
`\downarrow`
`1/3+6/9+4/5+5/25`
`= 1/3+2/3+4/5+1/5`
`= 1+1`
`= 2`
`4/7*2/5+4/7*3/5-1/7`
`= 4/7*(2/5+3/5)-1/7`
`= 4/7*1-1/7`
`= 4/7-1/7=3/7`
.....................................................
\(\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}+...+\dfrac{1}{25\times27}\)
\(=\dfrac{1}{2}\times\left(\dfrac{1}{3\times5}+\dfrac{1}{5\times7}+\dfrac{1}{7\times9}+...+\dfrac{1}{25\times27}\right)\)
\(=\dfrac{1}{2}\times\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{25}-\dfrac{1}{27}\right)\)
\(=\dfrac{1}{2}\times\left(\dfrac{1}{3}-\dfrac{1}{27}\right)\)
\(=\dfrac{1}{2}\times\dfrac{8}{27}\)
\(=1\times\dfrac{4}{27}=\dfrac{4}{27}\)
\(\dfrac{1}{3\text{x}5}+\dfrac{1}{5\text{x}7}+...+\dfrac{1}{25\text{x}27}\)
\(=\dfrac{1}{2}\text{x}\left(\dfrac{2}{3\text{x}5}+\dfrac{2}{5\text{x}7}+...+\dfrac{2}{25\text{x}27}\right)\)
\(=\dfrac{1}{2}\text{x}\left(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{25}-\dfrac{1}{27}\right)\)
\(=\dfrac{1}{2}\text{x}\left(\dfrac{1}{3}-\dfrac{1}{27}\right)=\dfrac{1}{2}\text{x}\dfrac{8}{27}=\dfrac{4}{27}\)