15 + 4 (x - 2) = 95

4 (x - 2) = 95 - 15 = 80

x - 2 = 80 : 4 = 20

x = 20 + 2 = 22 

ai gúp tớ cho <3

\(15+4\left(x-2\right)=95\)

\(4\left(x-2\right)=95-15\)

\(4\left(x-2\right)=80\)

\(x-2=80:4\)

\(x-2=20\)

\(x=20+2\)

\(x=22\)

1. 15 + 4.(x-2) = 95

4.(x-2) = 95-15

4.(x-2) = 80

x - 2 = 80 : 4

x- 2 = 20

x=18

2. 20 - (x+14)=5

x+14=20-5

x+14=15

x =15-14

x= 1

- 15+4(x-2)=95

      4(x-2)=95-15

      4(x-2)=80

         x-2 =80:4

         x-2 =20

        x     =20+2

       x      =22

- 20-(x+14)=5

       (x+14)=20-5

        x+14=15

        x      =15-14

       x       =1

15+4(x-2)=95

      x-2    = (95-15) : 4

      x-2    =  20

      x-2  = 20

           x= 20+2=22  

24+3(5-x)=27

     5-x    =(27 - 24 ) : 3

      5-x   =1

          x= 5-1=4

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

2x - 3 = 7                    3 . ( x + 7 ) = 15                  24 . 3 . ( 5 - x ) = 27                    15 + 4 . ( x - 2 ) = 95

2x = 3 + 7                    x + 7 = 15 : 3                      3 . ( 5 - x ) = 27 : 24                     4 . ( x - 2 ) = 95 - 15

2x = 10                        x + 7 = 5                             3 . ( 5 - x ) = 1,125                       4 . ( x - 2 ) = 80

x = 10 : 2                     x = 5 - 7                              5 - x = 1,125 : 3                           x - 2 = 80 : 4

x = 5                            x = ( -2 )                             5 - x = 0,375                                 x - 2 = 20

                                                                               x =  5 - 0,375                                x = 20 + 2

                                                                              x = 4,625                                       x = 22

cac ban oi hay giup minh