12000 - ( 1500.2 + 1800.3 + 1800.2 : 3 )

= 12000 - ( 1500.2 + 1800.3 + 3600 : 3 )

= 12000 - ( 3000 + 1800.3 + 3600 : 3 )

= 12000 - ( 3000 + 5400 + 3600 : 3)

= 12000 - ( 8400 + 3600 : 3 )

= 12000 - ( 8400 + 1200 )

= 12000 - 9600

= 2400

12000 - (3000+3600+1200)

=12000 -7800

=4200

\(\left(x-4\right)^9=49.\left(x-4\right)^7\\ =>\left(x-4\right)^9:\left(x-4\right)^7=49\\ =>\left(x-4\right)^2=49\\ =>\left[{}\begin{matrix}x-4=7\\x-4=-7\end{matrix}\right.\\ =>\left[{}\begin{matrix}x=11\\x=-3\end{matrix}\right.\)

              (x - 4)⁹ = 49 . (x - 4)⁷

(x - 4)⁹ : (x - 4)⁷ = 49

              (x - 4)² = 7² = (-7)²

TH1 :                                                    TH2 :

(x - 4)² = 7²                                          (x - 4)² = (-7)²

    x - 4 = 7                                                x - 4 = -7

         x = 7 + 4                                               x = -7 + 4

         x = 11                                                   x = -3

    Vậy x = 11                                          Vậy x = -3

* \(20+65.4=\left(x+75\right):5+30\)

\(\Leftrightarrow20+260-30=\frac{x}{5}+\frac{75}{5}\)

\(\Leftrightarrow20+260-30-\frac{75}{5}=\frac{x}{5}\)

\(\Leftrightarrow235=\frac{x}{5}\Rightarrow x=235.5=1175\)

* \(2248:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow2248:\left(119-x+6\right)=24\)

\(\Leftrightarrow2248:\left(125-x\right)=24\)

A mình lỡ tay, để mình tính tiếp nhá!

\(\Leftrightarrow125-x=2248:24\Leftrightarrow125-x=\frac{281}{3}\Rightarrow-x=\frac{94}{3}\Rightarrow x=-\frac{94}{3}\)(bài này mình thấy sai sai sao á, nếu mình làm sai thì thông cảm cho mình nhé!

* \(\left(x+70\right):14-40=\left(32.15\right):2\)

\(\Leftrightarrow\left(x+70\right):14=480:2+40\)

\(\Leftrightarrow\frac{x}{14}+5=280\Leftrightarrow\frac{x}{14}=275\Rightarrow x=3850\)

* \(x-4867=\left(175.2050.70\right):25+23\)

\(\Leftrightarrow x-4867-23=\left(175:25\right).\left(2050:25\right).\left(70:25\right)\)

\(\Leftrightarrow x-4890=7.82.\frac{14}{5}\)

\(\Leftrightarrow x-4890=\frac{8036}{5}\Rightarrow x=\frac{8036}{5}+4890=\frac{32486}{5}\)(bài này mình thấy hình như cũng có cái gì đó sai sai luôn hihi!)

\(5\cdot x+10\cdot9=990\)

\(\Rightarrow5\cdot x+90=990\)

\(\Rightarrow5\cdot x=900\)

\(\Rightarrow x=\dfrac{900}{5}\)

\(\Rightarrow x=180\)

_____________

\(1045:\left[215-\left(3\cdot x-24\right)\right]=5\)

\(\Rightarrow215-\left(3\cdot x-24\right)=1045:5\)

\(\Rightarrow215-\left(3\cdot x-24\right)=209\)

\(\Rightarrow3\cdot x-24=215-209\)

\(\Rightarrow3\cdot x-24=6\)

\(\Rightarrow3\cdot x=30\)

\(\Rightarrow x=10\)

`@` `\text {Ans}`

`\downarrow`

`5.x + 10.9 = 990`

`\Rightarrow 5x + 90 = 990`

`\Rightarrow 5x = 990 - 90`

`\Rightarrow 5x = 900`

`\Rightarrow x = 900 \div 5`

`\Rightarrow x = 180`

Vậy, `x = 180`

\(1045 \div [ 215 - (3 . x - 24 ) ] = 5\)

`\Rightarrow 1045 \div (215 - 3x + 24) = 5`

`\Rightarrow 191 + 3x = 1045 \div 5`

`\Rightarrow 191 + 3x = 209`

`\Rightarrow 3x = 209 - 191`

`\Rightarrow 3x =18`

`\Rightarrow x = 18 \div 3`

`\Rightarrow x = 6`

Vậy, `x = 6.`

Phanh đã chuyển đến đây 

1/2 . x + 3/5 . (x-2) = 3

1/2 . x + 3/5 . x - 3/5 . 2 = 3

1/2 . x + 3/5 . x - 6/5 = 3

x.(1/2+3/5) - 6/5 = 3

x.11/10 - 6/5 = 3

x.11/10 =3+6/5

x.11/10 =21/5

x = 21/5:11/10

x =42/11 

( x + 70 ) : 14 - 40 = (32 . 15 ) : 2

( x + 70 ) : 14 - 40 = 240

( x + 70 ) : 14 = 240 + 40 = 280

x + 70 = 280 x 14 = 3920

x = 3920 - 70 

x = 3850

Vậy x = 3850.

(x+70):14-40=(32.15):2

(x+70):14-40=480;2

(x+70):14-40=240

(x+70);14=240+40

(x+70):14=280

(x+70)=280.14

(x+70)=3360

x=3360-70

x=3290

\(36\div\left[7.\left(x-3\right)+4\right]=6\)

\(\Rightarrow7.\left(x-3\right)+4=36\div6\)

\(\Rightarrow7.\left(x-3\right)+4=6\)

\(\Rightarrow7.\left(x-3\right)=6-4\)

\(\Rightarrow7.\left(x-3\right)=2\)

\(\Rightarrow x-3=2\div7\)

\(\Rightarrow x-3=\frac{2}{7}\)

\(\Rightarrow x=\frac{2}{7}+3\)

\(\Rightarrow x=\frac{23}{7}\)

\(36:\left[7.\left(x-3\right)+4\right]=6\)

\(7.\left(x-3\right)+4=36:6\)

\(7.\left(x-3\right)+4=6\)

\(7.\left(x-3\right)=6-4\)

\(7.\left(x-3\right)=2\)

\(x-3=2:7\)

\(x-3=\frac{2}{7}\)

\(x=\frac{2}{7}+3\)

\(x=\frac{23}{7}\)

\(4\left(x+2\right)-8\left(x+3\right)=36\)

\(\Rightarrow4x+8-8x-24=36\)

\(\Rightarrow4x-8x=36+24-8\)

\(\Rightarrow-4x=52\)

\(\Rightarrow x=-13\)

\(x\left(x+y+z\right)=10\)    (1)

\(y\left(y+z+x\right)=25\)  (2)

\(z\left(z+x+y\right)=-10\)  (3)

Lấy  (1) + (2) + (3)  theo vế ta có:

      \(x\left(x+y+z\right)+y\left(y+z+x\right)+z\left(z+x+y\right)=10+25-10\)

\(\Leftrightarrow\)\(\left(x+y+z\right)^2=25\)

\(\Leftrightarrow\)\(x+y+z=\pm\sqrt{25}=\pm5\)

Nếu  \(x+y+z=5\) thì:    \(\hept{\begin{cases}x=2\\y=5\\z=-2\end{cases}}\)

Nếu   \(x+y+z=-5\)thì   \(\hept{\begin{cases}x=-2\\y=-5\\z=2\end{cases}}\)

Vậy...