=> (35 : x + 3) . 19 = 152

=> 35 : x + 3 = 8

=> 35 : x = 5

=> x = 7

(35*x+3)*19=165-13

(35*x+3)*19=152

35*x+3=152/19

35*x+3=8

35*x=8-3

35*x=5

x=35/5

x=7

Đáp án là A

Ta có: 165 - (35:x + 3).19 = 13

     ⇔ (35:x + 3).19 = 165 - 13

     ⇔ (35:x + 3).19 = 152

     ⇔ (35:x + 3) = 152:19 = 8

     ⇔ 35:x = 5

     ⇔ x = 7

đáp án a nhé

165 - (35 : x + 3). 19 = 13

(35 : x + 3). 19 =165-13

(35 : x + 3). 19  =152

35:x+3= 152:19

35:x+3=8

35: x= 8-3

35:x= 5

x= 35:5

x= 7

Vậy..

\(165-\left(35:x+3\right).19=13\)

\(\Rightarrow\left(35:x+3\right).19=165-13\)

\(\Rightarrow\left(35:x+3\right).19=152\)

\(\Rightarrow\left(35:x+3\right)=152:19\)

\(\Rightarrow\left(35:x+3\right)=8\)

\(\Rightarrow35:x=8-3\)

\(\Rightarrow35:x=5\)

\(\Rightarrow x=35:5\)

\(\Rightarrow x=7\)

Vậy x = 7

a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)

\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)

\(\Leftrightarrow\left(x:3+17\right):10+48=50\)

\(\Leftrightarrow\left(x:3+17\right):10=2\)

\(\Leftrightarrow x:3+17=20\)

\(\Leftrightarrow x:3=3\)

hay x=9

b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)

\(\Leftrightarrow119-\left(x-6\right)=102\)

\(\Leftrightarrow x-6=17\)

hay x=23

c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)

\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)

\(\Leftrightarrow\left(35:x+3\right)=8\)

\(\Leftrightarrow35:x=5\)

hay x=7

a.\(2.x+69.2=49.4\)

\(2.x+138=196\)

\(2x=58\)

\(x=29\)

Câu b xem lại đề nha,

c.\(25.\left(x-75\right)=25\)

\(\left(x-75\right)=1\)

\(x=76\)

d.\(165-\left(35:x+3\right).19=13\)

\(\left(35:x+3\right).19=152\)

\(\left(35:x+3\right)=8\)

\(35:x=5\)

\(x=7\)

a) =>  (35:x+3)*15 = 165-15=150

=> 35:x+3 = 150:15=10

=> 35:x = 10-3 = 7

=> x = 35:7 = 5

b) => 1*3/10x :1/2 +4/5 =1

=> 1*3/10x:1/2 =1-4/5=1/5

=> 1*3/10x = 1/5 *1/2 =1/10

=> 3/10-x = 1/10

=> x = 3/10 - 1/10 = 2/10 = 1/5

Đáp án cần chọn là: A