Câu b

Ta có :x + 3 /1.3  +3/3.5 + 3/5.7+...+3/13.15=2 1/5

X + 2/3.(1-1/3+1/3-1/5+1/5-1/7+...+1/13-1/15)1=11/5

X+2/3.(1-1/15)=11/5

X+ 2/3.14/15=11/5

X + 28/45=11/5

X = 11/5 -28/45

X=71/45

Câu a  gợi ý 

1/2-1/3/1/6=0 

1/2- 1/3 - 1/6 ) x (1/2 + 2/3 + 3/4 +4/5 + .......+ 2019 /2020 ) =0 

3/4:x=9/10

X = 3/4:9/10

X = 5/6

\(\frac{1}{2}+\frac{4}{5}:\frac{3}{5}-\frac{1}{5}\)

\(=\frac{1}{2}+\frac{4.5}{5.3}-\frac{1}{5}\)

\(=\frac{1}{2}+\frac{4}{3}-\frac{1}{5}\)

\(=\frac{11}{6}-\frac{1}{5}=\frac{49}{30}\)

= \(\frac{1}{2}\)+ \(\frac{20}{15}\)- \(\frac{1}{5}\)

= \(\frac{55}{30}\)- \(\frac{1}{5}\)

= \(\frac{49}{30}\)

\(\frac{1}{4}:a=\frac{1}{4\times a}< \frac{1}{104}\rightarrow4\times a>104.\)

Như vậy a = 27

đúng thì k mik nha

chắc đang giải vòng 7

1/4:a=1/4x1/a=1/4xa

mà 1/4:a<1/104

nên 1/4xa<1/104

nên 4xa=104 mà a nhỏ nhất

nên a=27

= 1 là đúng

Bạn có thể cho mình biết cách giải được không vậy bạn.

\(\frac{a}{b}.4+\frac{1}{6}=\frac{17}{6}\)

\(\frac{a}{b}.4\)          \(=\frac{17}{6}-\frac{1}{6}\)

\(\frac{a}{b}.4\)           \(=\frac{8}{3}\)

                      \(\frac{a}{b}=\frac{8}{3}:4\)

                      \(\frac{a}{b}=\frac{2}{3}\)

\(\frac{a}{b}.4=\frac{17}{6}-\frac{1}{6}\)

\(\frac{a}{b}.4=\frac{16}{6}\)

\(\frac{a}{b}=\frac{16}{6}:4\)

\(\frac{a}{b}=\frac{16}{6}.\frac{1}{4}=\frac{16}{6.4}=\frac{2}{3}\)

\(\frac{1}{3}\) + \(\frac{5}{6}\): \(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)

<=> \(\frac{5}{6}\):\(\left(x-2\frac{1}{5}\right)\)= \(\frac{3}{4}\)- \(\frac{1}{3}\)

<=> \(\frac{5}{6}\) : \(\left(x-2\frac{1}{5}\right)\) = \(\frac{5}{12}\)

<=> \(\left(x-2\frac{1}{5}\right)\) =    \(\frac{5}{6}\) : \(\frac{5}{12}\)

,<=> \(\left(x-2\frac{1}{5}\right)\)=   2 

<=. x = 2 + \(\frac{11}{5}\)

<=> x = \(\frac{21}{5}\)

                                                         Bài giải

        \(1\frac{1}{3}\text{ x }2\frac{1}{4}\text{ x }\text{ }3\frac{1}{5}\text{ x }4\frac{1}{6}\text{ x }5\frac{1}{7}\text{ x }6\frac{1}{8}\text{ x }7\frac{1}{9}\text{ x }8\frac{1}{10}\)

\(=\frac{4}{3}\text{ x }\frac{9}{4}\text{ x }\frac{16}{5}\text{ x }\frac{25}{6}\text{ x }\frac{36}{7}\text{ x }\frac{49}{8}\text{ x }\frac{64}{9}\text{ x }\frac{81}{10}\)

\(=\frac{4\text{ x }9\text{ x }16\text{ x }25\text{ x }36\text{ x }49\text{ x }64\text{ x }81}{3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9}\)

\(=\frac{4\text{ x }3^2\text{ x }4^2\text{ x }5^2\text{ x }6^2\text{ x }7^2\text{ x }8^2\text{ x }9^2}{3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9}\)                   ( Nếu bạn chưa học lũy thừa thì bạn không cần viết bước này ) 

\(=4\text{ x }3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9\)

\(=725760\)

                                                         Bài giải

        \(1\frac{1}{3}\text{ x }2\frac{1}{4}\text{ x }\text{ }3\frac{1}{5}\text{ x }4\frac{1}{6}\text{ x }5\frac{1}{7}\text{ x }6\frac{1}{8}\text{ x }7\frac{1}{9}\text{ x }8\frac{1}{10}\)

\(=\frac{4}{3}\text{ x }\frac{9}{4}\text{ x }\frac{16}{5}\text{ x }\frac{25}{6}\text{ x }\frac{36}{7}\text{ x }\frac{49}{8}\text{ x }\frac{64}{9}\text{ x }\frac{81}{10}\)

\(=\frac{4\text{ x }9\text{ x }16\text{ x }25\text{ x }36\text{ x }49\text{ x }64\text{ x }81}{3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9}\)

\(=\frac{4\text{ x }3^2\text{ x }4^2\text{ x }5^2\text{ x }6^2\text{ x }7^2\text{ x }8^2\text{ x }9^2}{3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9}\)                   ( Nếu bạn chưa học lũy thừa thì bạn không cần viết bước này ) 

\(=4\text{ x }3\text{ x }4\text{ x }5\text{ x }6\text{ x }7\text{ x }8\text{ x }9\)

\(=725760\)