Mk nghĩ số 1000 ở mẫu bn nên sửa thành 2000 ms đúng

2014 × 2015 - 15/2000 + 2015 × 2013

= (2013 + 1) × 2015 - 15/2000 + 2015 × 2013

= 2013 × 2015 + (2015 - 15)/2000 + 2015 × 2013

= 2013 × 2015 + 2000/2000 + 2015 × 2013

= 1

=[2013*2014*+2014*2015+2015*2016]*[\(1\frac{1}{3}-1\frac{1}{3}\)]

=A*0

=0

nhớ k nha mấy friends/

what men

\(\frac{45.47-33}{45.46+12}\)

= \(\frac{45.\left(46+1\right)-33}{45.46+12}\)

= \(\frac{45.46+45-33}{45.46+12}\)

= \(\frac{45-33}{12}\)

= \(1\)

=> biểu thức trên = 1

\(\frac{2013.2014+2000}{2014.2014-15}\)

\(=\frac{2013.2014+2000}{2014.\left(2013+1\right)-15}\)

\(=\frac{2013.2014+2000}{2014.2013+2014-15}\)

\(=\frac{2000}{2014-15}\)

\(=\frac{2000}{1999}\)

=> biểu thức trên < 1

\(\frac{2012+2013x2014}{2014x2015-2016}\)^{\(=\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)}

                                                       ^{\(=\frac{2012+2013x2014}{2014x2013+4028-2016}\)}

                                                        ^{\(=\frac{2012+2013x2014}{2014x2013+2012}\)}

                                                        ^\(=1\)

\(\frac{2012+2013x2014}{2014x2015-2016}\)

= \(\frac{2012+2013x2014}{2014x\left(2013+2\right)-2016}\)

= \(\frac{2012+2013x2014}{2014x2013+4028-2016}\)

= \(\frac{2012+2013x2014}{2014x2013+2012}\)

= 1

4/35 cau nay minh tung lam rui

bằng 1 

    \(\frac{2012+2013x2014}{2014x2015-2016}\)

= \(\frac{2012+4054182}{4058210-2016}\)

= \(\frac{4056194}{4056194}\)

= \(\frac{1}{1}\)

= \(1\)

Answer : \(1\)

\(\frac{2012+2013.2014}{2014.2015-2016}\)

\(=\frac{2012+2013.2014}{2014.\left(2013+2\right)-2016}\)

\(=\frac{2012+2013.2014}{2014.2013+2014.2-2016}\)

\(=\frac{2012}{4028-2016}\)

\(=\frac{2012}{2012}\)

\(=1\)

36.47-18.94=18.2.47-18.94=18.94-18.94=0

=>2013.2014(36.47-18.94)=0

2011*2012+4022/2013*2014-4028

1/1=1

bạn có thể giải chi tiết được ko 

2/ 

a) \(\frac{4}{1\cdot5}+\frac{4}{5\cdot9}+\frac{4}{9\cdot13}+\frac{4}{13\cdot17}+\frac{4}{17\cdot21}\)

\(=\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+....+\frac{1}{17}-\frac{1}{21}\right)\)

\(=1-\frac{1}{21}=\frac{20}{21}\)

b) \(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot...\cdot\left(1-\frac{1}{2017}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot..\cdot\frac{2016}{2017}\)

\(=\frac{1}{2017}\)

c) \(A=2000-5-5-5-..-5\)(có 200 số 5) 

\(A=2000-\left(5\cdot200\right)\)

\(A=2000-1000\)

\(A=1000\)