a: =35/17-18/17-9/5+4/5

=1-1=0

b: =-7/19(3/17+8/11-1)

=7/19*18/187=126/3553

c: =26/15-11/15-17/3-6/13

=1-6/13-17/3

=7/13-17/3=-200/39

^{_{\(\dfrac{5}{7}\cdot\dfrac{9}{11}+\dfrac{-5}{7}\cdot\dfrac{-2}{11}+\dfrac{1}{14}=\dfrac{45}{77}+\dfrac{10}{77}+\dfrac{1}{14}=\dfrac{5}{7}+\dfrac{1}{14}=\dfrac{10}{14}+\dfrac{1}{14}=\dfrac{11}{14}\)}}

\(\dfrac{5}{7}.\dfrac{9}{11}-\dfrac{5}{7}.-\dfrac{2}{11}+\dfrac{1}{14}=\dfrac{5}{7}.\left(\dfrac{9}{11}+\dfrac{2}{11}\right)+\dfrac{1}{14}=\dfrac{5}{7}.1+\dfrac{1}{14}=\dfrac{10+1}{14}=\dfrac{11}{14}\)

\(a,-\dfrac{5}{9}+\dfrac{14}{9}=\dfrac{-5+14}{9}=\dfrac{9}{9}=1\\ b,\dfrac{2}{7}+\dfrac{8}{-3}\\ =\dfrac{2}{7}-\dfrac{8}{3}\\ =\dfrac{2.3-8.7}{21}\\ =\dfrac{6-56}{21}\\ =\dfrac{-50}{21}\\ c,\dfrac{9}{11}+\dfrac{5}{7}+\dfrac{20}{-11}+\dfrac{12}{25}+\dfrac{2}{7}\\ =\left(\dfrac{2}{7}+\dfrac{5}{7}\right)+\left(\dfrac{9}{11}-\dfrac{20}{11}\right)+\dfrac{12}{25}\\ =\dfrac{7}{7}-\dfrac{11}{11}+\dfrac{12}{25}\\ =1-1+\dfrac{12}{25}\\ =\dfrac{12}{25}\)

Cho mình hỏi làm sao để lấy điểm GP và SP

\(-\frac{12}{35}\div\frac{7}{11}-\frac{23}{35}\div\frac{7}{11}-\frac{5}{11}\)

\(=\left(-\frac{12}{35}-\frac{23}{35}\right)\div\frac{7}{11}-\frac{5}{11}\)

\(=-1\div\frac{7}{11}-\frac{5}{11}\)

\(=-\frac{11}{7}-\frac{5}{11}\)

\(=-\frac{156}{77}\)

\(2-\frac{11}{9}\div\frac{5}{14}-\frac{7}{9}\times\frac{14}{5}\)

\(=2-\frac{154}{45}-\frac{98}{45}\)

\(=-\frac{64}{45}-\frac{98}{45}\)

\(=-\frac{18}{5}\)

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

a: =-5-7-8-3=-26

b: =-4-2-5-6=-17

c: =-8-11-4-2=-25

d: -9-15-6-3=-30

e: =-12-9-3-8=-32

a: \(=\dfrac{5}{7}\left(\dfrac{5}{11}+\dfrac{2}{11}-\dfrac{14}{11}\right)=\dfrac{5}{7}\cdot\dfrac{-7}{11}=-\dfrac{5}{11}\)

b: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\left(4+\dfrac{3}{8}\right)\)

\(=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{3}{2}\cdot5=\dfrac{15}{2}\)

c: \(=\dfrac{2}{15}-\dfrac{2}{15}\cdot5+\dfrac{3}{15}=\dfrac{2}{15}\cdot\left(-4\right)+\dfrac{3}{15}=\dfrac{-8+3}{15}=\dfrac{-5}{15}=-\dfrac{1}{3}\)

d: \(=\dfrac{4}{9}\left(19+\dfrac{1}{3}-39-\dfrac{1}{3}\right)=\dfrac{4}{9}\cdot\left(-20\right)=-\dfrac{80}{9}\)