=2016*97+2016*2+2016*1

=2016*[97+2+1]

=2016*100

=201600

2016 x 97 + 2016 x 2 + 2016

= 2016 x (97 + 2 + 1)

= 2016 x 100

= 201600

2016 × 35 + 2016 × 65

= 2016 × (35+65)

= 2016 × 100

= 201600

2016 × 99 + 2016

= 2016 × 99 + 2016 × 1 

= 2016 × (1+99)

= 2016 × 100

= 201600

2016 × 102 - 2016 × 2

= 2016 × (102-2)

= 2016 × 100

= 201600

2016 × 101 - 2016

= 2016 × 101 - 2016 × 1

= 2016 × (101-1)

= 2016 × 100

= 201600

2016 x 35 + 2016 x 65 

= 2016 x ( 35 + 65 )

= 2016 x 100

= 201600

2016 x 99 + 2016

= 2016 x 99 + 2016 x 1

= 2016 x ( 99 + 1 )

= 2016 x 100

= 201600

2016 x 102 - 2016 x 2 

= 2016 x  ( 102 - 2 )

= 2016 x 100

= 201600

2016 x 101 - 2016

= 2016 x 101 - 2016 x 1

= 2016 x ( 101 - 1 )

= 2016 x 100

= 201600

\(A=\frac{1}{2016}+\frac{2}{2016}+\frac{3}{2016}+...+\frac{2015}{2016}\)

\(A=\frac{1+2+3+...+2015}{2016}=\frac{2031120}{2016}=\frac{2015}{2}\)

2015/2

Ta có :A=\(\frac{1}{2016}+\frac{2}{2016}+...+\frac{2015}{2016}=\frac{1+2+...+2015}{2016}\)

Xét 1+2+ ... +2015 = \(\frac{2015\times2016}{2}=2031120\)---> A=\(\frac{2031120}{2016}=1007,5\)

=(1+2+3+...+2015)/2016=(2015.(2015+1):2)/2016=2031120/2016=2015/2

nhóm cuối sẽ nhóm được thành nhiều nhóm:

(1/2016+2015/2016)+(2/2016+2014/2016)+.......+(1008/2016+1008/2016) có tổng cộng 1008 nhóm =1

suy ra nhóm trên có kq là 1008

= 1/2+1+1+1008

=1/2+1010

=2021/2

cho mik nha

(1/2016+2015/2016)+(2/2016+2014/2016)+.......+(1008/2016+1008/2016) có tổng cộng 1008 nhóm =1

suy ra nhóm trên có kq là 1008

= 1/2+1+1+1008

=1/2+1010

=2021/2

2016 + 2016 + 2016 x 2 x 2=12096

k nha 

thanks

12096

2016(34+63+2+1)=2016*100=201600

2016.34+2016.63+2016.2+2016

= 2016.(34+63+2+1)

= 2016 . 100

= 201600.

Chúc bn hk tốt!!!

= 2016 * (34+63+2) +2016

=20169 * 99 +2016

=199584 + 2016

=201600 .

Tck mk nha , thanhk you

Cách 1:
Xét số bị trừ, ta có:
(2/3 + 3/4 + 4/5 + ... + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016 + 2016/2017) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
= (2/3 + 3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016) + 2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Xét số trừ, ta có: 
(1/2 + 2/3 + 3/4 + ... + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016 + 2016/2017) x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= (1/2 + 2/3 + 3/4 + ... + 2015/2016) x (2/3 + 3/4 + 4/5 + ... + 2015/2016) + 2016/2017 x (2/3 +3/4 + 4/5 + ... + 2015/2016) =
Ta thấy số bị trừ và số trừ có số hạng giống nhau là:
(2/3 +3/4 + 4/5 + ... + 2015/2016) x (1/2 + 2/3 + 3/4 + ... + 2015/2016)
Nên phép trừ trên có thể viết lại:
2016/2017 x (1/2 + 2/3 + 3/4 + ... + 2015/2016) - 2016/2017 x (2/3 + 3/4 + 4/5 + ... + 2015/2016)
= 2016/2017 x [(1/2 + 2/3 + 3/4 + ... + 2015/2016) - (2/3 +3/4 + 4/5 + ... + 2015/2016)]
= 2016/2017 x 1/2
= 1008/2017

Cách 2: