c=1+2+4+8+64

=79

\(C=2^0+2^1+2^2+2^3+2^0+2^1+2^2+2^3\)

\(=\left(2^0.2\right)+\left(2^1.2\right)+\left(2^2.2\right)+\left(2^3.2\right)\)

\(=2+4+8+16\)

\(=\left(2+8\right)+\left(4+16\right)\)

\(=10+20\)

\(=30\)

\(D=\left(2^0+2^1+2^2+2^3\right).2^0.2^1.2^2.2^3\)

\(=\left(1+2+4+8\right).1.2.4.8\)

\(=\left(8+2+4+1\right).1.2.4.8\)

\(=\left(10+4+1\right).1.2.4.8\)

\(=15.1.2.4.8\)

\(=\left(15.2\right).1.4.8\)

\(=30.1.4.8\)

\(=120.8\)

\(=960\)

(2^2 + 2^1 + 2^2 + 2^3). 2^0. 2^1. 2^2. 2^3

=(4 + 2 + 4 + 8). 1. 2. 4. 8

=18.64

=1152

Ta có F=(2^0+2^1+2^2+2^3).2^0.2^1.2^2.2^3

\(\Rightarrow F=\left(1+2+4+8\right).1.2.4.8\)

\(F=15.64\)

\(F=960\)

\(A=2^0.2^1.2^2....2^{100}\)

\(A=2^{0+1+2+...+100}\)

\(A=2^{101.50}\)

\(A=2^{5050}\)

z lm lại, nhưng nó cứ sao ý!

\(\left(2^2+2^1+2^2+2^3\right).2^0.2^1.2^2.2^3\)

\(=18.64\)

\(=1152\)

Sửa đề:

đặt A = \(\left(2^0+2^1+2^2+2^3\right).2^0.2^1.2^2.2^3\)

\(A=\left(1+2+2^2+2^3\right).2^6\)

\(A=2^6+2^7+2^8+2^9\)

\(\Rightarrow2A=2^7+2^8+2^9+2^{10}\)

\(\Rightarrow2A-A=2^{10}-2^6\)

\(A=2^{10}-2^6\)

\(A=960\)

xem đề mk ghi như z cs đúng ko? 

\(29.8+50.2+31.3=232+100+93=425\)(Nhớ click cho mình với nhoa!)

29.8 +50.2 +31.3 = 232 + 100 + 93 =332 + 93 = 425

tích mk nha!!